/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 Sketch the areas under the stand... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the areas under the standard normal curve over the indicated intervals and find the specified areas. Between \(z=-1.98\) and \(z=-0.03\)

Short Answer

Expert verified
The area under the standard normal curve between \(z=-1.98\) and \(z=-0.03\) is approximately 0.4641.

Step by step solution

01

Set up the Problem

We are asked to find the area under the standard normal curve between the z-scores of -1.98 and -0.03. The area under the curve between two z-scores corresponds to the probability that a value falls within this range.
02

Use the Standard Normal Distribution Table

Consult a standard normal distribution table (Z-table) to find the cumulative probability for each z-score.For \( z = -1.98 \), find \( P(Z < -1.98) \). The table gives approximately 0.0239.For \( z = -0.03 \), find \( P(Z < -0.03) \). The table gives approximately 0.4880.
03

Calculate the Area Between the Z-Scores

The area between the z-scores is the difference between the cumulative probabilities for these values.\[ P(-1.98 < Z < -0.03) = P(Z < -0.03) - P(Z < -1.98) \]Substitute the values found from the table:\[ 0.4880 - 0.0239 = 0.4641 \]
04

Interpretation

The calculated area, 0.4641, represents the probability that a randomly selected value from a standard normal distribution falls between the z-scores -1.98 and -0.03. This is also the proportion of the standard normal distribution that lies between these z-scores.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Z-Scores
Z-scores are a way to describe where a specific value lies in relation to the mean of a standard normal distribution. This distribution is a special type of distribution where the mean is 0 and the standard deviation is 1. A z-score indicates how many standard deviations an element is from the mean. If the z-score is positive, the value is above the mean. If it is negative, the value is below the mean. For example, a z-score of -1.98 means the value is 1.98 standard deviations below the mean. Similarly, a z-score of -0.03 means the value is very close to the mean, only 0.03 standard deviations below. By using z-scores, we can easily calculate probabilities and understand the position of a particular value within the overall distribution.
  • Positive z-scores indicate values above the mean.
  • Negative z-scores indicate values below the mean.
  • Z-score of 0 means the value is exactly at the mean.
Probability Basics
Probability is the likelihood or chance of an event occurring. In the context of the standard normal distribution, probability refers to the likelihood that a value will fall within a specific range of z-scores. This range is represented by the area under the curve on a standard normal distribution graph. To determine the probability of an event, we often use cumulative distribution functions and probability density functions. In simple terms, think of probability as a way to measure how likely it is for a certain z-score or range of z-scores to occur in a dataset. Understanding probability helps us make predictions and informed decisions based on data.
Cumulative Distribution Function (CDF)
The cumulative distribution function (CDF) represents the probability that a variable will take a value less than or equal to a particular threshold. When dealing with z-scores, the CDF helps us find the probability for values up to a specific point in the standard normal distribution. In practice, it is used to determine the area under the curve up to a certain z-score. For example, in our step-by-step solution, the cumulative probability for a z-score of -1.98 was approximately 0.0239, meaning there's a 2.39% chance that a value will fall below this z-score. Similarly, a z-score of -0.03 has a cumulative probability of roughly 48.80%, indicating that nearly half the values fall below this point. This is crucial for calculating the probability of ranges between two z-scores by subtracting the lower cumulative probability from the higher.
Using a Z-Table for Probability Calculations
A Z-table, or standard normal distribution table, provides cumulative probabilities for z-scores in a standard normal distribution. It tells us the probability that a standard normal random variable is less than or equal to a given z-score.
  • Find the row corresponding to the z-score's whole number and first decimal place.
  • Find the column matching the second decimal place of the z-score.
  • The value at the intersection is the cumulative probability.
In our example, for z = -1.98, the Z-table shows a probability of approximately 0.0239, while for z = -0.03, it shows around 0.4880. Once we have these values, it's easy to compute the probability between any two z-scores by subtracting the smaller cumulative probability from the larger one. This makes Z-tables a potent tool for determining probabilities and understanding data within the standard normal distribution.

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Most popular questions from this chapter

Find the indicated probability, and shade the corresponding area under the standard normal curve. $$P(z \leq-2.15)$$

Find the indicated probability, and shade the corresponding area under the standard normal curve. $$P(z \leq 0)$$

Coal is carried from a mine in West Virginia to a power plant in New York in hopper cars on a long train. The automatic hopper car loader is set to put 75 tons of coal into each car. The actual weights of coal loaded into each car are normally distributed, with mean \(\mu=75\) tons and standard deviation \(\sigma=0.8\) ton. (a) What is the probability that one car chosen at random will have less than 74.5 tons of coal? (b) What is the probability that 20 cars chosen at random will have a mean load weight \(\bar{x}\) of less than 74.5 tons of coal? (c) Interpretation Suppose the weight of coal in one car was less than 74.5 tons. Would that fact make you suspect that the loader had slipped out of adjustment? Suppose the weight of coal in 20 cars sclected at random had an average \(\bar{x}\) of less than 74.5 tons. Would that fact make you suspect that the loader had slipped out of adjustment? Why?

Conditional Probability Suppose you want to eat lunch at a popular restaurant. The restaurant does not take reservations, so there is usually a waiting time before you can be seated. Let \(x\) represent the length of time waiting to be seated. From past experience, you know that the mean waiting time is \(\mu=18\) minutes with \(\sigma=4\) minutes. You assume that the \(x\) distribution is approximately normal. (a) What is the probability that the waiting time will exceed 20 minutes, given that it has exceeded 15 minutes? Hint: Compute \(P(x>20 | x>15)\).(b) What is the probability that the waiting time will exceed 25 minutes, give that it has exceeded 18 minutes? Hint: Compute \(P(x>25 | x>18)\) (c) Hint for solution: Review item \(6,\) conditional probability, in the summar= of basic probability rules at the end of Section \(4.2 .\) Note that $$P(A | B)=\frac{P(A \text { and } B)}{P(B)}$$,and show that in part (a), $$P(x>20 | x>15)=\frac{P((x>20) \text { and }(x>15))}{P(x>15)}=\frac{P(x>20)}{P(x>15)}$$.

Consider two \(\bar{x}\) distributions corresponding to the same \(x\) distribution. The first \(\bar{x}\) distribution is based on samples of size \(n=100\) and the second is based on samples of size \(n=225 .\) Which \(\bar{x}\) distribution has the smaller standard error? Explain.

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