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91Ó°ÊÓ

Sketch the areas under the standard normal curve over the indicated intervals and find the specified areas. Between \(z=-1.40\) and \(z=2.03\)

Short Answer

Expert verified
The area under the curve between z-scores -1.40 and 2.03 is 0.8980.

Step by step solution

01

Understand the Standard Normal Curve

The standard normal curve is a bell-shaped curve representing the distribution of many naturally occurring datasets. It is symmetric about the mean (0) and uses the standard deviation of 1. Values under this curve represent probabilities, with the total area under the curve equal to 1.
02

Identify the Interval

The given interval is between the z-scores of -1.40 and 2.03 on the standard normal curve. We will calculate the area under the standard normal curve between these two points, which represents the probability that a value falls within this range.
03

Use Z-Score Table

First, look up the z-score of -1.40 in a z-table. The value typically found here is approximately 0.0808, representing the area to the left of this z-score under the curve. Next, find the area to the left of the z-score of 2.03, which is approximately 0.9788.
04

Calculate the Area Between the Z-Scores

Subtract the table value of z = -1.40 from the table value of z = 2.03 to find the area between them: \[0.9788 - 0.0808 = 0.8980\]So the area between z = -1.40 and z = 2.03 is 0.8980.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Score Demystified
A Z-score is a statistical measurement that tells us how many standard deviations an element is from the mean. In a standard normal distribution, the mean is always zero, and the standard deviation is one. The Z-score allows us to compare different values from various data sets and standardize them for better analysis.
  • If the Z-score is zero, it indicates that the data point's score is identical to the mean score.
  • A positive Z-score indicates the data point is above the mean.
  • A negative Z-score reveals it is below the mean.
Knowing the Z-scores for specific data helps us determine the position within the normal curve.
If we're calculating the probability of an event, we often look at the Z-score to determine how typical or atypical your data is based on how many standard deviations away from the mean it is positioned.
Understanding the Area Under the Curve
In the context of a standard normal distribution, the area under the curve represents probabilities, or the likelihood that a value will fall within a particular range. These areas are significant because when we speak about probability distributions, the total area under the curve sums up to 1, indicating 100% certainty that a value falls somewhere in the curve.
To find the area between two Z-scores, you can use a Z-score table. This table provides the proportion of data falling to the left of a specified Z-score. For instance, looking at our example, the area under the curve to the left of a Z-score means we're including all probabilities from the far left up to that Z-score.
By finding areas for specified Z-scores, you can subtract to calculate the area between them, representing the chance that a randomly selected data point lies in that range. This method lets us quickly "see" how much of the data lies between any two points on a standard distribution.
Exploring Probability Distributions
A probability distribution describes how the values of a random variable are distributed. In a standard normal distribution, it's depicted by our bell-shaped curve, showcasing how data is distributed across various values. Probability distributions are used in various real-world contexts, whether predicting future sales, assessing risk, or analyzing test scores.
  • An important characteristic of these distributions is the mean, mode, and median center in the middle of the curve.
  • Standard deviation indicates how closely data is clustered around the mean.
  • Skewness and kurtosis describe the shape and spread of the data in relation to the normal curve.
Understanding these components helps in analyzing and interpreting data trends effectively. When applying the standard normal distribution, we gain insights into probabilities that allow us to make educated predictions or decisions based on statistical evidence.

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Most popular questions from this chapter

Find the indicated probability, and shade the corresponding area under the standard normal curve. $$P(z \geq 0)$$

Basic Computation: \(\hat{p}\) Distribution Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us. (a) Suppose \(n=100\) and \(p=0.23 .\) Can we safely approximate the \(\hat{p}\) distribution by a normal distribution? Why? Compute \(\mu_{j}\) and \(\sigma_{\tilde{p}}\) (b) Suppose \(n=20\) and \(p=0.23 .\) Can we safely approximate the \(\hat{p}\) distribution by a normal distribution? Why or why not?

The manager of Motel 11 has 316 rooms in Palo Alto, California. From observation over a long period of time, she knows that on an average night, 268 rooms will be rented. The long-term standard deviation is 12 rooms. This distribution is approximately mound-shaped and symmetric. (a) For 10 consecutive nights, the following numbers of rooms were rented each night: $$\begin{array}{l|cccccc} \hline \text { Night } & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline \text { Number of rooms } & 234 & 258 & 265 & 271 & 283 & 267 \\ \hline & & & & & & \\ \hline \text { Night } & 7 & 8 & 9 & 10 & & \\ \hline \text { Number of rooms } & 290 & 286 & 263 & 240 & & \\ \hline \end{array}$$ Make a control chart for the number of rooms rented each night, and plot the preceding data on the control chart. Interpretation Looking at the control chart, would you say the number of rooms rented during this 10-night period has been unusually low? unusually high? about what you expected? Explain your answer. Identify all out-of-control signals by type (I, II, or III). Make a control chart for the number of rooms rented each night, and plot the preceding data on the control chart. Interpretation Looking at the control chart, would you say the number of rooms rented during this 10-night period has been unusually low? unusually high? about what you expected? Explain your answer. Identify all out-of-control signals by type (I, II, or III). (b) For another 10 consecutive nights, the following numbers of rooms were rented each night: $$\begin{array}{l|cccccc} \hline \text { Night } & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline \text { Number of rooms } & 238 & 245 & 261 & 269 & 273 & 250 \\ \hline & & & & & & \\ \hline \text { Night } & 7 & 8 & 9 & 10 & & \\ \hline \text { Number of rooms } & 241 & 230 & 215 & 217 & & \\ \hline \end{array}$$ Make a control chart for the number of rooms rented each night, and plot the preceding data on the control chart. Would you say the room occupancy has been high? low? about what you expected? Explain your answer. Identify all out-of- control signals by type (I, II, or IIII).

A relay microchip in a telecommunications satellite has a life expectancy that follows a normal distribution with a mean of 90 months and a standard deviation of 3.7 months. When this computerrelay microchip malfunctions, the entire satellite is useless. A large London insurance company is going to insure the satellite for \(\$ 50 dollars million. Assume that the only part of the satellite in question is the microchip. All other components will work indefinitely. (a) Inverse Normal Distribution For how many months should the satellite be insured to be \)99 \%\( confident that it will last beyond the insurance date? (b) If the satellite is insured for 84 months, what is the probability that it will malfunction before the insurance coverage ends? (c) If the satellite is insured for 84 months, what is the expected loss to the insurance company? (d) If the insurance company charges \)\$ 3$ million for 84 months of insurance, how much profit does the company expect to make?

Sketch the areas under the standard normal curve over the indicated intervals and find the specified areas. To the left of \(z=-0.47\)

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