/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 A person's blood glucose level a... [FREE SOLUTION] | 91Ó°ÊÓ

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A person's blood glucose level and diabetes are closely related. Let \(x\) be a random variable measured in milligrams of glucose per deciliter \((1 / 10 \text { of a liter })\) of blood. After a 12 -hour fast, the random variable \(x\) will have a distribution that is approximately normal with mean \(\mu=85\) and standard deviation \(\sigma=25\) (Source: Diagnostic Tests with Nursing Implications, edited by S. Loeb, Springhouse Press). Note: After 50 years of age, both the mean and standard deviation tend to increase. What is the probability that, for an adult (under 50 years old) after a 12 -hour fast, (a) \(x\) is more than \(60 ?\) (b) \(x\) is less than \(110 ?\) (c) \(x\) is between 60 and \(110 ?\) (d) \(x\) is greater than 125 (borderline diabetes starts at 125 )?

Short Answer

Expert verified
(a) 0.8413, (b) 0.8413, (c) 0.6826, (d) 0.0548

Step by step solution

01

Understanding the Normal Distribution

We know that the random variable \( x \) follows a normal distribution with a mean \( \mu = 85 \) and a standard deviation \( \sigma = 25 \). Thus, \( x \sim N(85, 25^2) \). We will use the properties of the normal distribution to solve the problems related to probability.
02

Converting to a Standard Normal Distribution (Z)

To find probabilities, we first convert the random variable \( x \) to a standard normal variable \( Z \) using the formula: \[ Z = \frac{x - \mu}{\sigma} \] This transforms \( x \) into a standard normal distribution \( N(0, 1) \).
03

Finding Probability for (a) \( x > 60 \)

Convert \( x = 60 \) to a \( Z \) value: \[ Z = \frac{60 - 85}{25} = \frac{-25}{25} = -1 \] We need \( P(X > 60) = P(Z > -1) \). Using the standard normal distribution table or calculator, find \( P(Z > -1) = 1 - P(Z < -1) \). The standard normal table gives \( P(Z < -1) \approx 0.1587 \), so \( P(Z > -1) \approx 1 - 0.1587 = 0.8413 \).
04

Finding Probability for (b) \( x < 110 \)

Convert \( x = 110 \) to a \( Z \) value: \[ Z = \frac{110 - 85}{25} = \frac{25}{25} = 1 \] We need \( P(X < 110) = P(Z < 1) \). From the standard normal distribution table, \( P(Z < 1) \approx 0.8413 \).
05

Finding Probability for (c) \( 60 < x < 110 \)

To find \( P(60 < x < 110) \), you can use the previous results:\[ P(60 < x < 110) = P(x < 110) - P(x < 60) \]We already know \( P(x < 110) \approx 0.8413 \) and \( P(x < 60) \approx 0.1587 \), so:\[ P(60 < x < 110) \approx 0.8413 - 0.1587 = 0.6826 \]
06

Finding Probability for (d) \( x > 125 \)

Convert \( x = 125 \) to a \( Z \) value: \[ Z = \frac{125 - 85}{25} = \frac{40}{25} = 1.6 \] We need \( P(X > 125) = P(Z > 1.6) \). Using the standard normal distribution table or calculator, \( P(Z > 1.6) \approx 1 - 0.9452 = 0.0548 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Normal Distribution
The standard normal distribution is a special statistical function that allows for the calculation of probabilities for any normally distributed random variable. It simplifies the problem-solving process across various fields, particularly in probability and statistics.
To transform any normal distribution to the standard normal distribution, you use the Z-score formula: \[ Z = \frac{x - \mu}{\sigma} \] Here, \( x \) is the value you are examining, \( \mu \) is the mean of the distribution, and \( \sigma \) is the standard deviation.
Through this transformation, we get a new distribution with a mean of 0 and a standard deviation of 1. By converting a normal distribution problem to a standard normal distribution problem, you can use the z-table (or a calculator) to find probabilities easily without requiring complex calculus.
Whenever you see problems involving normal distributions, remember that converting to a standard normal distribution makes calculations much more manageable.
Probability Calculation
Probability calculation involves determining the likelihood of an event occurring. When dealing with a normal distribution, this often means finding out the probability that a random variable falls within a certain range. This is where the standard normal distribution and Z-scores come into play.
Once you have your Z-score, probability calculations are done through:
  • Identifying the relevant point or points on the z-table, which gives you the area under the curve to the left of that Z-score.
  • If you're looking for \( P(Z>a) \), where \( a \) is a negative number, you calculate it by finding \( 1 - P(Z
  • For probabilities between two values, such as \( P(a

These techniques provide a straightforward way to find probabilities, key to solving many real-world problems.
Blood Glucose Levels
Blood glucose levels are a crucial indicator of how the body processes sugar. In medical diagnostics, they often follow a normal distribution, especially after fasting. This is why normal distribution can be applied to solve problems related to these levels.
The typical fasting blood glucose level has a mean around 85 mg/dL with a standard deviation of 25 for those under 50. Once the individual reaches 50 years or older, both values tend to rise due to changes in metabolism and increased medical risk factors like diabetes.
By applying normal distribution principles to blood glucose levels, practitioners can determine the probability of levels falling within a certain range, which is vital for early detection of diabetes and related conditions. Such calculations help clinicians advise patients on lifestyle changes or start interventions at specific risk thresholds.
Random Variable
In probability and statistics, a random variable is a variable whose value is subject to variations due to chance. Specifically, a random variable can take on different values based on an underlying random process.
For the blood glucose context, the random variable \( x \) represents the blood glucose level after fasting. This type of variable is continuous, as it can take on any value within a range rather than just distinct separate values.
Understanding random variables is essential to real-world applications. For blood glucose levels, recognizing \( x \) as a random variable enables us to model and predict outcomes, quantify uncertainty, and evaluate risks. By knowing the distribution properties such as the mean and standard deviation, you can analyze and infer probabilities and trends, crucial for informing personal or medical decisions.

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Most popular questions from this chapter

Find the indicated probability, and shade the corresponding area under the standard normal curve. $$P(z \geq 1.35)$$

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Find the \(z\) value described and sketch the area described.Find \(z\) such that \(95 \%\) of the standard normal curve lies to the right of \(z\).

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