/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Consider an \(x\) distribution w... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider an \(x\) distribution with standard deviation \(\sigma=12\). (a) If specifications for a research project require the standard error of the corresponding \(\bar{x}\) distribution to be \(2,\) how large does the sample size need to be? (b) If specifications for a research project require the standard error of the corresponding \(\bar{x}\) distribution to be \(1,\) how large does the sample size need to be?

Short Answer

Expert verified
(a) 36 samples; (b) 144 samples.

Step by step solution

01

Understanding Standard Error Formula

The standard error of the sample mean, given by \(SE_{\bar{x}}\), is calculated using the formula \[ SE_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \] where \(\sigma\) is the population standard deviation, and \(n\) is the sample size. This formula will be used to find the required sample size for the given standard errors.
02

Rearranging the Formula for Sample Size

To find the sample size \(n\), rearrange the formula \[ SE_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \] to solve for \(n\): \[ \sqrt{n} = \frac{\sigma}{SE_{\bar{x}}} \] \[ n = \left(\frac{\sigma}{SE_{\bar{x}}}\right)^2 \] This rearrangement will allow us to calculate the required sample size for a given standard error.
03

Calculate Sample Size for Standard Error of 2

Substitute \(\sigma = 12\) and \(SE_{\bar{x}} = 2\) into the rearranged formula: \[ n = \left(\frac{12}{2}\right)^2 \] \[ n = 6^2 \] \[ n = 36 \] Thus, the required sample size when the standard error is 2 is 36.
04

Calculate Sample Size for Standard Error of 1

Next, substitute \(\sigma = 12\) and \(SE_{\bar{x}} = 1\) into the rearranged formula: \[ n = \left(\frac{12}{1}\right)^2 \] \[ n = 12^2 \] \[ n = 144 \] Therefore, the required sample size when the standard error is 1 is 144.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size Calculation
When tackling statistical problems, the size of the sample you choose can significantly affect the accuracy of your results. A sample size is the number of observations or replicates included in a statistical sample. It is crucial because it determines how well your sample represents the entire population.
According to the formula for the standard error of the sample mean, the sample size \(n\) plays a critical role in determining the precision of the sample estimates. The formula is given by:
  • \( SE_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \)
This formula tells us that the standard error of the mean decreases as the sample size increases.
  • This is because a larger sample size provides more data points, which averages out fluctuations, leading to more accurate and reliable estimates.
For example, to achieve a specific standard error, such as 2 or 1, you’d rearrange the formula to calculate the necessary sample size:
  • \( n = \left(\frac{\sigma}{SE_{\bar{x}}}\right)^2 \)
This rearrangement allows researchers to determine the sample size they need to achieve their desired level of precision.
Population Standard Deviation
Standard deviation is a fundamental concept in statistics, specifically when dealing with data dispersion around a mean. The population standard deviation, \(\sigma\), measures the extent to which data points in a population vary from the mean population value.
In the context of sample size and standard error, knowing the population standard deviation is essential. It serves as the baseline variability measure and is a key component in the formula for standard error:
  • \( SE_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \)
The usage of population standard deviation rather than the sample standard deviation ensures that the formula accurately reflects the scale of data dispersion across the entire population.
Determining \(\sigma\) might require prior knowledge or careful estimation from preliminary studies, especially if the value is used for crucial calculations like sample size determination.
Standard Deviation Formula
The standard deviation formula provides a way to quantify the amount of variation or dispersion in a set of data points. For a population, it is defined as follows:
  • \(\sigma = \sqrt{\frac{\sum (x_i - \mu)^2}{N}}\)
where \(x_i\) represents each data point in the population, \(\mu\) is the population mean, and \(N\) is the total number of data points in the population.
  • This formula assesses how individual points differ from the mean, providing an average of the squared deviations, followed by taking the square root to bring it back into the same units as the original data points.
Alternate versions of this formula apply to sample data instead of whole populations, though these are adjusted by using \(N-1\) to provide an unbiased estimate for the sample standard deviation.
Understanding this concept is critical for interpreting the extent of data dispersion, which, in turn, impacts statistical analysis and decision-making.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sketch the areas under the standard normal curve over the indicated intervals and find the specified areas. To the right of \(z=-1.22\)

Assuming that the heights of college women are normally distributed with mean 65 inches and standard deviation 2.5 inches (based on information from Statistical Abstract of the United States, 112th edition), answer the following questions. Hint: Use Problems 5 and 6 and Figure \(6-3\) (a) What percentage of women are taller than 65 inches? (b) What percentage of women are shorter than 65 inches? (c) What percentage of women are between 62.5 inches and 67.5 inches? (d) What percentage of women are between 60 inches and 70 inches?

Airline Flights: No-Shows Based on long experience, an airline has found that about \(6 \%\) of the people making reservations on a flight from Miami to Denver do not show up for the flight. Suppose the airline overbooks this flight by selling 267 ticket reservations for an airplane with only 255 seats. (a) What is the probability that a person holding a reservation will show up for the flight? (b) Let \(n=267\) represent the number of ticket reservations. Let \(r\) represent the number of people with reservations who show up for the flight. Which expression represents the probability that a seat will be available for everyone who shows up holding a reservation? $$P(255 \leq r) ; P(r \leq 255) ; P(r \leq 267) ; P(r=255)$$ (c) Use the normal approximation to the binomial distribution and part (b) to answer the following question: What is the probability that a seat will be available for every person who shows up holding a reservation?

Measurement errors from instruments are often modeled using the uniform distribution (see Problem 16 ). To determine the range of a large public address system, acoustical engineers use a method of triangulation to measure the shock waves sent out by the speakers. The time at which the waves arrive at the sensors must be measured accurately. In this context, a negative error means the signal arrived too early. A positive error means the signal arrived too late. Measurement errors in reading these times have a uniform distribution from -0.05 to +0.05 microseconds. (Reference: J. Perruzzi and E. Hilliard, "Modeling Time Delay Measurement Errors," Journal of the Acoustical Society of America, Vol. 75, No. 1, pp. 197-201.) What is the probability that such measurements will be in error by (a) less than \(+0.03 \text { microsecond (i.e., }-0.05 \leq x<0.03) ?\) (b) more than -0.02 microsecond? (c) between -0.04 and +0.01 microsecond? (d) Find the mean and standard deviation of measurement errors. Measurements from an instrument are called unbiased if the mean of the measurement errors is zero. Would you say the measurements for these acoustical sensors are unbiased? Explain.

Find the indicated probability, and shade the corresponding area under the standard normal curve. $$P(0 \leq z \leq 1.62)$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.