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The owners of a motel in Florida have noticed that in the long run, about \(40 \%\) of the people who stop and inquire about a room for the night actually rent a room. (a) How many inquiries must the owner answer to be \(99 \%\) sure of renting at least one room? (b) If 25 separate inquiries are made about rooms, what is the expected number of inquiries that will result in room rentals?

Short Answer

Expert verified
(a) At least 14 inquiries are needed. (b) The expected number of rentals is 10.

Step by step solution

01

Understanding the Problem

We are tasked with two parts: First, determining the number of inquiries needed to have a 99% probability of renting at least one room. Second, we need to calculate the expected number of room rentals if there are 25 inquiries. This involves probability and expectation in a binomial distribution, where the success probability is 40% or 0.4.
02

Determine Minimum Inquiries for 99% Probability

To find out how many inquiries are needed to have a 99% chance of renting at least one room, we use the complement probability. Let \(X\) be the number of rentals from \(n\) inquiries. We need \(P(X \geq 1) = 0.99\). The complement \(P(X = 0) = 0.01\). Using the binomial probability formula, we write \(P(X=0) = (1-p)^n = 0.01\), where \(p = 0.4\). So we solve \((0.6)^n = 0.01\).
03

Solve for n in the Probability Equation

Solve for \(n\) in the equation \((0.6)^n = 0.01\). This can be done using logarithms: \(n \log(0.6) = \log(0.01)\) leading to \(n = \frac{\log(0.01)}{\log(0.6)} \approx 13.29\). Thus, the owner must answer at least 14 inquiries to be 99% certain of renting at least one room.
04

Calculate Expected Rentals from 25 Inquiries

For part (b), the expected number of inquiries resulting in room rentals is calculated using the formula for expected value. With 25 inquiries and a rental probability of 0.4, the expected number is calculated as \(E(X) = np\), where \(n = 25\) and \(p = 0.4\). This gives \(E(X) = 25 \times 0.4 = 10\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Probability
Probability is a fundamental concept in statistics that measures the likelihood of an event happening. When dealing with a binomial distribution, probability helps quantify scenarios where there are two possible outcomes: success and failure. For example, in our motel problem, when someone inquires about a room, either they decide to rent a room or not.
The probability of a single person renting a room is 40% or 0.4. This probability can tell us how often we can expect a particular outcome in repeated trials under identical conditions.
  • Success probability (\(p\)) is 0.4, meaning the person rents a room.
  • Failure probability (\(1 - p\)) is 0.6, meaning the person does not rent a room.
By understanding the probability of both renting and not renting, one can calculate how many inquiries are needed to reach a certain level of certainty, like the 99% mentioned in the problem.
Expected Value Explained
The expected value is a critical concept in probability that provides the average outcome if a certain action is repeated multiple times. It's like the long-term average, indicating what you can "expect" to happen. In the context of our motel problem, the expected value helps us determine how many room rentals will likely result from inquiries.
The formula for expected value in a binomial distribution is given by \(E(X) = np\), where \(n\) is the number of trials (or inquiries), and \(p\) is the probability of success (a room rental).
  • If \(n = 25\) and \(p = 0.4\), then \(E(X) = 25 \times 0.4 = 10\).
This means that out of 25 inquiries, we can expect, on average, about 10 people to rent a room. The expected value doesn't guarantee precise numbers every time, but rather an average over lots of trials.
What are Random Variables?
Random variables are used to map outcomes of random processes to numerical values. They help us quantify randomness and are essential for calculating probabilities and expected values. In the binomial distribution, a random variable is defined to represent the number of successes in a fixed number of trials.
In our motel scenario, let \(X\) be the random variable representing the number of room rentals. Here \(X\) can take any value from 0 to the total number of inquiries, recording how many of these inquiries result in a rental.
  • A discrete random variable can only take specific values (like our \(X\)), counting the number of successes.
  • Each outcome (rental or no rental) contributes to the overall distribution of \(X\), informing probabilities and expected values.
Understanding random variables allows us to model and work with real-world scenarios statistically.
The Complement Rule
The complement rule is a handy tool in probability that helps calculate the chance of at least one success. Since directly calculating \(P(X \geq 1)\) can sometimes be complex, the complement rule simplifies it by calculating the likelihood of the opposite event and then subtracting from 1.
For example, \(P(X \geq 1) = 1 - P(X = 0)\). This tells us the chance of getting at least one success is the total probability (1) minus the probability of zero successes.
  • For the motel case: \(P(X = 0) = (1-p)^n\), where all inquiries fail to result in a room rental.
  • If \(P(X = 0) = 0.01\), then \(P(X \geq 1) = 1 - 0.01 = 0.99\), confirming the 99% surety of at least one rental.
Using the complement rule greatly simplifies solving complex probability questions and is especially useful in binomial distributions.

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Most popular questions from this chapter

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