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What does the random variable for a binomial experiment of \(n\) trials measure?

Short Answer

Expert verified
The random variable measures the number of successes in a fixed number of trials.

Step by step solution

01

Understanding the Binomial Experiment

A binomial experiment consists of a fixed number of independent trials, each with two possible outcomes: success or failure. So, the first step is to identify these trials in your context.
02

Defining the Random Variable

The random variable in a binomial experiment represents the number of successes in the given number of trials. This means you count how many times the successful outcome occurs across all trials.
03

Relating Trials and Random Variable

For example, if you conduct 10 trials and achieve success 3 times, the random variable would take the value 3, representing these 3 successes. The random variable is specifically focused on tallying successful outcomes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variable
In the context of a binomial experiment, a random variable is an essential concept to grasp. It is essentially a variable that represents numerical outcomes resulting from a series of trials. When dealing with binomial experiments, our focus is on counting the number of successes within these trials.
Imagine you're flipping a coin 10 times; each flip can be a success (say, heads) or a failure (tails). The random variable's job here is simple: it counts how many times heads come up in those 10 flips. This count, which can range from 0 to 10, represents the random variable for your binomial experiment.
This concept is particularly useful because it provides a way to measure outcomes and make probabilistic predictions about them. By defining the random variable as the number of successes, you can use probability distributions, such as the binomial distribution, to calculate the likelihood of various outcomes.
Independent Trials
In a binomial experiment, it's critical to understand the nature of independent trials. Independence here means the outcome of one trial does not affect the outcome of another. This independence is key to ensuring that the binomial equations and calculations remain valid.
Consider tossing a coin repeatedly. Each toss is independent because the result of the previous toss has no bearing on the outcome of the next one. Achieving either heads or tails doesn't increase or decrease the chance of getting heads or tails again in subsequent tosses. This independence ensures that each trial is a fresh start and critical for calculating accurate probabilities.
To verify if trials in your experiment are independent, ask yourself: 鈥淲ould the outcome of any single trial affect the outcome of another?鈥 If the answer is yes, they are not independent, and the setup wouldn't qualify as a binomial experiment in its true form.
Success and Failure Outcomes
For any binomial experiment, defining success and failure outcomes is fundamental. Every trial must have precisely two possible outcomes: success and failure. The definition of these outcomes is crucial as it sets the stage for the entire experiment.
Success doesn鈥檛 always mean achieving something grand; it merely refers to the outcome you鈥檙e counting. For instance, if you're rolling a die and considering a roll of four as a 'success', then any roll that isn't a four is a 'failure'.
Once these success and failure outcomes are clearly defined, they help in setting up the calculations for binomial probabilities. Success and failure probabilities are applied to each independent trial, determining the experiment's overall structure while allowing us to calculate the likelihood of various outcomes using binomial probability formulas.
Remember, the probability of success (commonly denoted as \( p \)) and that of failure (denoted as \( 1-p \)) in each trial remains constant throughout the experiment.

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Most popular questions from this chapter

A large bank vault has several automatic burglar alarms. The probability is 0.55 that a single alarm will detect a burglar. (a) How many such alarms should be used for \(99 \%\) certainty that a burglar trying to enter will be detected by at least one alarm? (b) Suppose the bank installs nine alarms. What is the expected number of alarms that will detect a burglar?

Much of Trail Ridge Road in Rocky Mountain National Park is over 12,000 feet high. Although it is a beautiful drive in summer months, in winter the road is closed because of severe weather conditions. Winter Wind Studies in Rocky Mountain National Park by Glidden (published by Rocky Mountain Nature Association) states that sustained galeforce winds (over 32 miles per hour and often over 90 miles per hour) occur on the average of once every 60 hours at a Trail Ridge Road weather station. (a) Let \(r=\) frequency with which gale-force winds occur in a given time interval. Explain why the Poisson probability distribution would be a good choice for the random variable \(r\) (b) For an interval of 108 hours, what are the probabilities that \(r=2,3,\) and 4? What is the probability that \(r<2 ?\) (c) For an interval of 180 hours, what are the probabilities that \(r=3,4,\) and 5? What is the probability that \(r<3 ?\)

Repair Service A computer repair shop has two work centers. The first center examines the computer to see what is wrong, and the second center repairs the computer. Let \(x_{1}\) and \(x_{2}\) be random variables representing the lengths of time in minutes to examine a computer \(\left(x_{1}\right)\) and to repair a computer \(\left(x_{2}\right) .\) Assume \(x_{1}\) and \(x_{2}\) are independent random variables. Long-term history has shown the following times: Examine computer, \(x_{1}: \mu_{1}=28.1\) minutes; \(\sigma_{1}=8.2\) minutes Repair computer, \(x_{2}: \mu_{2}=90.5\) minutes; \(\sigma_{2}=15.2\) minutes (a) Let \(W=x_{1}+x_{2}\) be a random variable representing the total time to examine and repair the computer. Compute the mean, variance, and standard deviation of \(W\). (b) Suppose it costs 1.50 dollar per minute to examine the computer and 2.75 dollar per minute to repair the computer. Then \(W=1.50 x_{1}+2.75 x_{2}\) is a random variable representing the service charges (without parts). Compute the mean, variance, and standard deviation of \(W .\) (c) The shop charges a flat rate of 1.50 dollar per minute to examine the computer, and if no repairs are ordered, there is also an additional 50 dollar service charge. Let \(L=1.5 x_{1}+50 .\) Compute the mean, variance, and standard deviation of \(L.\)

Consider a binomial distribution with \(n=10\) trials and the probability of success on a single trial \(p=0.85\) (a) Is the distribution skewed left, skewed right, or symmetric? (b) Compute the expected number of successes in 10 trials. (c) Given the high probability of success \(p\) on a single trial, would you expect \(P(r \leq 3)\) to be very high or very low? Explain. (d) Given the high probability of success \(p\) on a single trial, would you expect \(P(r \geq 8)\) to be very high or very low? Explain.

In Hawaii, January is a favorite month for surfing since \(60 \%\) of the days have a surf of at least 6 feet (Reference: Hawaii Data Book, Robert C. Schmitt). You work day shifts in a Honolulu hospital emergency room. At the beginning of each month you select your days off, and you pick 7 days at random in January to go surfing. Let \(r\) be the number of days the surf is at least 6 feet. (a) Make a histogram of the probability distribution of \(r .\) (b) What is the probability of getting 5 or more days when the surf is at least 6 feet? (c) What is the probability of getting fewer than 3 days when the surf is at least 6 feet? (d) What is the expected number of days when the surf will be at least 6 feet? (e) What is the standard deviation of the \(r\) -probability distribution? (f) Interpretation Can you be fairly confident that the surf will be at least 6 feet high on one of your days off? Explain.

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