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What does the expected value of a binomial distribution with \(n\) trials tell you?

Short Answer

Expert verified
The expected value of a binomial distribution indicates the average number of successes in \(n\) trials.

Step by step solution

01

Understanding Binomial Distribution

The binomial distribution is a discrete probability distribution that models the number of successes in a fixed number of independent trials, each with the same probability of success. It's characterized by two parameters: the number of trials \(n\), and the probability of success in each trial \(p\).
02

Determine the Expected Value Formula

For a binomial distribution, the expected value \(E(X)\) is determined by the formula \(E(X) = n \times p\), where \(X\) represents the random variable for the number of successes.
03

Interpret the Expected Value

The expected value \(E(X)\) represents the average number of successes you would expect to observe over a large number of trials. In essence, it tells you the long-term average or mean of the distribution's outcomes if the experiment were repeated many times.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
In a binomial distribution, the expected value is a fundamental concept that provides insight into the average outcome of a process over time. It's calculated using the formula:\[ E(X) = n \times p \]where:
  • \(n\) is the number of trials. This is the total number of attempts or experiments conducted.
  • \(p\) is the probability of success for each trial. This figure represents the likelihood of achieving the desired outcome in any single trial.
The expected value, therefore, reflects the average number of successes anticipated if the experiment were performed numerous times. For instance, if you're flipping a fair coin 10 times, and you define 'success' as flipping a head (with a probability of \(p = 0.5\)), the expected number of heads (successes) would be \(10 \times 0.5 = 5\). This expected value doesn't guarantee 5 heads in every set of 10 flips, but rather it suggests that across many sets of 10 flips, the average number of heads approaches 5.
Probability of Success
In the context of a binomial distribution, the probability of success \(p\) is a crucial element. It represents the likelihood that a single trial within the experimental setup results in what you define as a success. This value remains constant across all trials, making it a defining feature of a binomial distribution.

Let's say you're conducting an experiment where you're drawing a card from a deck to see if it's a red card. If the deck is standard, the probability of pulling a red card is 0.5, or 50%. This probability doesn't change for each draw if you replace the card back into the deck after each trial, maintaining the independence required for a binomial distribution repeatedly.
  • A constant probability ensures uniformity across trials.
  • It's essential for accurately predicting outcomes and calculating expected values.
  • Understanding this probability helps to set realistic expectations of outcomes over multiple trials.
It's this component that contributes to the predictability and mathematical determination of the expected value.
Discrete Probability Distribution
When dealing with a binomial distribution, it's essential to recognize that it's a type of discrete probability distribution. This means that the outcomes of the trials are countable and finite. In essence, you're measuring occurrences of specific results (like successes versus failures).

Discrete probability distributions differ from continuous distributions, which can take on any value within a range. Instead, discrete distributions, like binomial, focus on whole number outcomes. For example, if you were rolling a die, the outcomes (1 through 6) are part of a discrete distribution, as each roll results in one of a finite set of possible values.
  • Each outcome (success or failure) of a trial is distinct and separate from others.
  • The sum of probabilities across all possible outcomes in a binomial distribution equals 1, maintaining the integrity of probability theory.
  • This type of distribution helps in calculating various probabilities, including expected values, under specific experimental conditions.
Recognizing the discrete nature of binomial distributions is key to understanding how successes accumulate and why the expected value is what it is.

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Most popular questions from this chapter

USA Today reported that about 20\% of all people in the United States are illiterate. Suppose you interview seven people at random off a city street. (a) Make a histogram showing the probability distribution of the number of illiterate people out of the seven people in the sample. (b) Find the mean and standard deviation of this probability distribution. Find the expected number of people in this sample who are illiterate. (c) How many people would you need to interview to be 98\% sure that at least seven of these people can read and write (are not illiterate)?

Chances: Risk and Odds in Everyday Life, by James Burke, reports that only \(2 \%\) of all local franchises are business failures. A Colorado Springs shopping complex has 137 franchises (restaurants, print shops, convenience stores, hair salons, etc.). (a) Let \(r\) be the number of these franchises that are business failures. Explain why a Poisson approximation to the binomial would be appropriate for the random variable \(r\) What is \(n\) ? What is \(p\) ? What is \(\lambda\) (rounded to the nearest tenth)? (b) What is the probability that none of the franchises will be a business failure? (c) What is the probability that two or more franchises will be business failures? (d) What is the probability that four or more franchises will be business failures?

Bob is a recent law school graduate who intends to take the state bar exam. According to the National Conference on Bar Examiners, about \(57 \%\) of all people who take the state bar exam pass (Source: The Book of Odds by Shook and Shook, Signet). Let \(n=1,2,3, \ldots\) represent the number of times a person takes the bar exam until the first pass. (a) Write out a formula for the probability distribution of the random variable \(n .\) (b) What is the probability that Bob first passes the bar exam on the second \(\operatorname{try}(n=2) ?\) (c) What is the probability that Bob needs three attempts to pass the bar exam? (d) What is the probability that Bob needs more than three attempts to pass the bar exam? (e) What is the expected number of attempts at the state bar exam Bob must make for his (first) pass? Hint: Use \(\mu\) for the geometric distribution and round.

USA Today reported that approximately \(25 \%\) of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let \(x=\) number of prisoners out of five on parole who become repeat offenders. The methods of Section 5.2 can be used to compute the probability assignments for the \(x\) distribution. $$\begin{array}{c|cccccc} \hline x & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline P(x) & 0.237 & 0.396 & 0.264 & 0.088 & 0.015 & 0.001 \\ \hline \end{array}$$ (a) Find the probability that one or more of the five parolees will be repeat offenders. How does this number relate to the probability that none of the parolees will be repeat offenders? (b) Find the probability that two or more of the five parolees will be repeat offenders. (c) Find the probability that four or more of the five parolees will be repeat offenders. (d) Compute \(\mu,\) the expected number of repeat offenders out of five. (e) Compute \(\sigma,\) the standard deviation of the number of repeat offenders out of five.

When using the Poisson distribution, which parameter of the distribution is used in probability computations? What is the symbol used for this parameter?

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