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For a given data set in which not all data values are equal, which value is smaller, \(s\) or \(\sigma ?\) Explain.

Short Answer

Expert verified
The sample standard deviation \( s \) is typically larger than the population standard deviation \( \sigma \).

Step by step solution

01

Understand the Definitions

In statistics, the standard deviation of a sample ( is denoted as \( s \), and the standard deviation of a population is denoted as \( \sigma \).
02

Consider Formula for Sample Standard Deviation

The formula for the standard deviation of a sample is \( s = \sqrt{\frac{1}{n-1}\sum_{i=1}^{n}(x_i - \bar{x})^2} \), where \( n \) is the sample size and \( x_i \) are the observed values.
03

Consider Formula for Population Standard Deviation

The formula for the standard deviation of a population is \( \sigma = \sqrt{\frac{1}{N}\sum_{i=1}^{N}(x_i - \mu)^2} \), where \( N \) is the population size and \( \mu \) is the mean of the population.
04

Compare the Formulas

Notice that dividing by \( n-1 \) (for the sample) results in a larger calculated value compared to dividing by \( N \) (for the population), assuming the same set of data values.
05

Draw the Conclusion

Thus, \( s \) (sample standard deviation) tends to be larger than \( \sigma \) (population standard deviation) when calculated for the same data set since \( n-1 < N \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Sample Standard Deviation
The sample standard deviation, denoted as \( s \), is a statistical measure that gives us an idea of how spread out the values in a sample dataset are. A sample is a subset of a larger population, chosen to represent the population in studies. The calculation of \( s \) is essential when we want to make inferences about an entire population based on this smaller sample.

To compute the sample standard deviation, you first find the difference between each sample value and the sample mean \( \bar{x} \), square each difference, sum them all up, and then divide by \( n-1 \), where \( n \) is the sample size. This division by \( n-1 \) is called Bessel’s correction, and it's used to get an unbiased estimate of the population variance. Lastly, you take the square root of this result to achieve the standard deviation. The formula looks like this: \[ s = \sqrt{\frac{1}{n-1}\sum_{i=1}^{n}(x_i - \bar{x})^2} \]
  • \( n \) is the number of observations in the sample.
  • \( x_i \) are the data points in the sample.
  • \( \bar{x} \) is the mean of the sample.
The Concept of Population Standard Deviation
The population standard deviation, denoted by \( \sigma \), measures the spread of data in an entire population. Unlike the sample, which is a part of the whole, a population includes all members from the dataset we are interested in.

When we deal with population standard deviation, we want to ascertain how much individual data points differ from the mean of that population. The formula for \( \sigma \) is slightly different from sample standard deviation. Instead of dividing by \( n-1 \), you divide by \( N \), the total number of data points in the population. This approach gives us the precise measure of variation since the entire population is being considered. The formula is: \[ \sigma = \sqrt{\frac{1}{N}\sum_{i=1}^{N}(x_i - \mu)^2} \]
  • \( N \) is the total number of observations in the population.
  • \( x_i \) are the data points in the population.
  • \( \mu \) is the mean of the population.
The Role of Statistical Formulas
Statistical formulas are the backbone of analyzing data in various fields such as economics, biology, and social sciences. They provide a structured way to compute important metrics that summarize data and reveal underlying patterns.

Both sample and population standard deviations are derived using specific statistical formulas that allow researchers to understand how data varies and how close data points are to the mean. The formulas involve:
  • Summing differences between data values and means.
  • Squaring these differences to remove negative signs and emphasize larger deviations.
  • Dividing by a figure (\( n-1 \) for the sample and \( N \) for the population) to normalize the measurement.
  • Taking the square root to return to the original units of measurement.
These operations, although appearing simple, are crucial for providing insights into the distribution and variability of data sets.

Understanding and correctly applying these statistical formulas can significantly improve the accuracy of data analysis, leading to better decisions and predictions.

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Most popular questions from this chapter

Police are tested for their ability to correctly recognize and identify a suspect based on a witness or victim's verbal description of the suspect. Scores on the identification test range from 0 to 100 (perfect score). Three cities in Massachusetts are under study. The mean score for all police in the three cities is requested. However, funding will only permit \(m=150\) police to be tested. There is no preliminary study to estimate sample standard deviation of scores in each city. City A has \(N_{1}=183\) police, City B has \(N_{2}=371\) police, and City \(\mathrm{C}\) has \(N_{3}=255\) police. In most cases \(n_{i}\) is not a whole number so we round to the nearest whole number. Remember our total sample size is \(m=n_{1}+n_{2}+n_{3}\) (a) Use the method of proportional sampling to compute \(n_{1}, n_{2},\) and \(n_{3},\) the size of the random sample to be taken from each of the three cities. Round each \(n_{i}\) to the nearest whole number and make sure \(m=n_{1}+n_{2}+n_{3}\) (b) Suppose you actually conducted the specified number of tests in each city and obtained the following result: \(\overline{x_{1}}=96\) is the mean test score from city \(\mathrm{A}, \overline{x_{2}}=85\) is the mean test score from City \(\mathrm{B},\) and \(\overline{x_{3}}=88\) is the mean test score from City C. Use the weighted average \(\mu \approx \frac{n_{1}}{m} \overline{x_{1}}+\frac{n_{2}}{m} \overline{x_{2}}+\frac{n_{3}}{m} \overline{x_{3}}\) to get your best estimate for the population mean test score of all police in all three cities. Estimates for \(\mu\) are usually better if we have a preliminary study with reasonably accurate estimates for the sample standard deviation \(s_{i}\) of each stratum (see Problems 28 and 29 ). However, in the case where there is no preliminary study we can use proportional sampling and still obtain good results.

One standard for admission to Redfield College is that the student rank in the upper quartile of his or her graduating high school class. What is the minimal percentile rank of a successful applicant?

In this problem, we explore the effect on the mean, median, and mode of multiplying each data value by the same number. Consider the data set 2,2,3,6,10. (a) Compute the mode, median, and mean. (b) Multiply each data value by \(5 .\) Compute the mode, median, and mean. (c) Compare the results of parts (a) and (b). In general, how do you think the mode, median, and mean are affected when each data value in a set is multiplied by the same constant? (d) Suppose you have information about average heights of a random sample of airplane passengers. The mode is 70 inches, the median is 68 inches, and the mean is 71 inches. To convert the data into centimeters, multiply each data value by \(2.54 .\) What are the values of the mode, median, and mean in centimeters?

Consider the data set \(1 \quad 2 \quad 3 \quad 4 \quad 5\) (a) Find the range. (b) Use the defining formula to compute the sample standard deviation \(s .\) (c) Use the defining formula to compute the population standard deviation \(\sigma .\)

For mallard ducks and Canada geese, what percentage of nests are successful (at least one offspring survives)? Studies in Montana, Illinois, Wyoming, Utah, and California gave the following percentages of successful nests (Reference: The Wildlife Society Press, Washington, D.C.). \(x:\) Percentage success for mallard duck nests $$56 \quad 85 \quad 52 \quad 13 \quad 39$$ \(y:\) Percentage success for Canada goose nests $$24 \quad 53 \quad 60 \quad 69 \quad 18$$ (a) Use a calculator to verify that \(\Sigma x=245 ; \Sigma x^{2}=14,755 ; \Sigma y=224 ;\) and \(\Sigma y^{2}=12,070\). (b) Use the results of part (a) to compute the sample mean, variance, and standard deviation for \(x,\) the percent of successful mallard nests. (c) Use the results of part (a) to compute the sample mean, variance, and standard deviation for \(y,\) the percent of successful Canada goose nests. (d) Use the results of parts (b) and (c) to compute the coefficient of variation for successful mallard nests and Canada goose nests. Write a brief explanation of the meaning of these numbers. What do these results say about the nesting success rates for mallards compared to those of Canada geese? Would you say one group of data is more or less consistent than the other? Explain.

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