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What is the relationship between the variance and the standard deviation for a sample data set?

Short Answer

Expert verified
Standard deviation is the square root of the variance.

Step by step solution

01

Understanding Variance

Variance represents how spread out the data points in a sample are from the sample mean. It is calculated as the average of the squared differences from the mean. In formula terms, for a sample, variance is given by: \[ s^2 = \frac{1}{n-1} \sum_{i=1}^{n} (x_i - \bar{x})^2 \]where \( s^2 \) is the variance, \( x_i \) are the data points, \( \bar{x} \) is the sample mean, and \( n \) is the number of data points.
02

Understanding Standard Deviation

Standard deviation is another measure of spread or dispersion within a dataset. It is essentially the square root of the variance, providing a measure in the same units as the original data. The formula for sample standard deviation is:\[ s = \sqrt{s^2} \] where \( s \) is the standard deviation and \( s^2 \) is the variance.
03

Relationship between Variance and Standard Deviation

The relationship between variance and standard deviation is direct; standard deviation is the square root of the variance. This relationship is crucial because it allows us to interpret the dispersion of data in the same units as the data itself, providing a more intuitive measure.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variance
Variance is a fundamental concept in statistics that helps us understand how data is distributed around the mean. Imagine you have a set of data points, such as the test scores of a class. If the scores are all close to the class average, the variance will be low. On the other hand, if there is a wide range of scores, the variance will be higher.

The formula for calculating variance for a sample data set is:
  • Subtract each data point from the mean of the data set.
  • Square each of these differences to eliminate negative values and emphasize larger differences.
  • Average these squared differences, but divide by one less than the total number of data points ( -1) to correct for bias. This is known as Bessel's correction.
The result is the variance, which provides a measure of the spread in squared units. Understanding variance is crucial because it forms the basis for calculating the standard deviation.
Sample Data Set
A sample data set is a smaller group selected from a larger population, used for analysis to make inferences about the entire group. When dealing with statistics, it's often impractical to collect data from an entire population. Instead, a sample set allows for the evaluation and interpretation of data trends without requiring comprehensive datasets.

Let's break this down. Assume you're interested in the average height of all students in a high school. Compiling the heights of every student may be cumbersome. Instead, a representative sample from each grade can provide insight without measuring every individual.

Analyzing a sample data set involves determining metrics like the sample mean, variance, and standard deviation. When you calculate these using a sample, it's important to remember that you're estimating the true parameters of the population. That is why measures like variance and standard deviation for a sample are slightly adjusted. They are divided by -1, not , to provide an unbiased estimate.
Dispersion Measure
Dispersion measures are statistical ways to describe how spread out or clustered together data points in a dataset are. These are essential in understanding the spread or variability in your data. There are several types of dispersion measures, but variance and standard deviation are among the most commonly used.

Variance gives a numerical value representing how the data points differ from the mean. Yet, because variance is calculated by squaring these deviations, it is expressed in squared units, making it less intuitive. This is where the standard deviation becomes useful.

Standard deviation is the square root of variance. It returns the measure of spread to the same unit as the data itself, making it more directly interpretable. A small standard deviation implies that most data points are close to the mean, while a large standard deviation indicates greater spread. Understanding both variance and standard deviation helps in recognizing the degree of variation in data, enabling clearer insights.

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Most popular questions from this chapter

Which average—mean, median, or mode—is associated with the standard deviation?

Kevlar epoxy is a material used on the NASA space shuttles. Strands of this epoxy were tested at the \(90 \%\) breaking strength. The following data represent time to failure (in hours) for a random sample of 50 epoxy strands (Reference: R. E. Barlow, University of California, Berkeley). Let \(x\) be a random variable representing time to failure (in hours) at \(90 \%\) breaking strength. Note: These data are also available for download at the Companion Sites for this text. $$\begin{array}{lllllllll} 0.54 & 1.80 & 1.52 & 2.05 & 1.03 & 1.18 & 0.80 & 1.33 & 1.29 & 1.11 \\ 3.34 & 1.54 & 0.08 & 0.12 & 0.60 & 0.72 & 0.92 & 1.05 & 1.43 & 3.03 \\ 1.81 & 2.17 & 0.63 & 0.56 & 0.03 & 0.09 & 0.18 & 0.34 & 1.51 & 1.45 \\ 1.52 & 0.19 & 1.55 & 0.02 & 0.07 & 0.65 & 0.40 & 0.24 & 1.51 & 1.45 \\ 1.60 & 1.80 & 4.69 & 0.08 & 7.89 & 1.58 & 1.64 & 0.03 & 0.23 & 0.72 \end{array}$$ (a) Find the range. (b) Use a calculator to verify that \(\Sigma x=62.11\) and \(\Sigma x^{2} \approx 164.23\). (c) Use the results of part (b) to compute the sample mean, variance, and standard deviation for the time to failure. (d) Use the results of part (c) to compute the coefficient of variation. What does this number say about time to failure? Why does a small \(C V\) indicate more consistent data, whereas a larger \(C V\) indicates less consistent data? Explain.

Consider two data sets with equal sample standard deviations. The first data set has 20 data values that are not all equal, and the second has 50 data values that are not all equal. For which data set is the difference between \(s\) and \(\sigma\) greater? Explain. Hint: Consider the relationship \(\sigma=s \sqrt{(n-1) / n}\).

Interpretation A job-performance evaluation form has these categories: \(1=\) excellent; \(2=\) good; \(3=\) satisfactory; \(4=\) poor; \(5=\) unacceptable Based on 15 client reviews, one employee had median rating of \(4 ;\) mode rating of 1 The employee was pleased that most clients had rated her as excellent. The supervisor said improvement was needed because at least half the clients had rated the employee at the poor or unacceptable level. Comment on the different perspectives.

Some data sets include values so high or so low that they seem to stand apart from the rest of the data. These data are called outliers. Outliers may represent data collection errors, data entry errors, or simply valid but unusual data values. It is important to identify outliers in the data set and examine the outliers carefully to determine if they are in error. One way to detect outliers is to use a box-and-whisker plot. Data values that fall beyond the limits, $$\begin{aligned} &\text { Lower limit: } Q_{1}-1.5 \times(I Q R)\\\ &\text { Upper limit: } Q_{3}+1.5 \times(I Q R) \end{aligned}$$ where \(I Q R\) is the interquartile range, are suspected outliers. In the computer software package Minitab, values beyond these limits are plotted with asterisks (*). Students from a statistics class were asked to record their heights in inches. The heights (as recorded) were $$\begin{array}{cccccccccccc} 65 & 72 & 68 & 64 & 60 & 55 & 73 & 71 & 52 & 63 & 61 & 74 \\ 69 & 67 & 74 & 50 & 4 & 75 & 67 & 62 & 66 & 80 & 64 & 65 \end{array}$$ (a) Make a box-and-whisker plot of the data. (b) Find the value of the interquartile range \((I Q R)\) (c) Multiply the IQR by 1.5 and find the lower and upper limits. (d) Are there any data values below the lower limit? above the upper limit? List any suspected outliers. What might be some explanations for the outliers?

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