/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 A new thermostat has been engine... [FREE SOLUTION] | 91Ó°ÊÓ

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A new thermostat has been engineered for the frozen food cases in large supermarkets. Both the old and the new thermostats hold temperatures at an average of \(25^{\circ} \mathrm{F}\). However, it is hoped that the new thermostat might be more dependable in the sense that it will hold temperatures closer to \(25^{\circ} \mathrm{F}\). One frozen food case was equipped with the new thermostat, and a random sample of 21 temperature readings gave a sample variance of \(5.1 .\) Another, similar frozen food case was equipped with the old thermostat, and a random sample of 16 temperature readings gave a sample variance of \(12.8 .\) Test the claim that the population variance of the old thermostat temperature readings is larger than that for the new thermostat. Use a \(5 \%\) level of significance. How could your test conclusion relate to the question regarding the dependability of the temperature readings?

Short Answer

Expert verified
The variance of the old thermostat is not significantly greater, suggesting similar dependability.

Step by step solution

01

Understand the Hypotheses

We need to determine whether the population variance of the old thermostat is greater than that of the new thermostat. Thus, our null hypothesis \( H_0 \) is \( \sigma_1^2 = \sigma_2^2 \), and the alternative hypothesis \( H_a \) is \( \sigma_1^2 > \sigma_2^2 \), where \( \sigma_1^2 \) and \( \sigma_2^2 \) are the population variances for the old and new thermostats, respectively.
02

Determine the Test Statistic

We use the F-test for comparing the variances. The test statistic is calculated using:\[F = \frac{s_1^2}{s_2^2}\]where \(s_1^2 = 12.8\) for the old thermostat and \(s_2^2 = 5.1\) for the new thermostat. Substituting the values gives:\[F = \frac{12.8}{5.1} = 2.51\]
03

Find the Critical Value

Using an F-distribution table and given \( \alpha = 0.05 \) with degrees of freedom \( df_1 = 15 \) (old) and \( df_2 = 20 \) (new), we look up the critical value at 5% significance. The critical value \( F_{0.05, 15, 20} \) is about 2.54.
04

Compare the Test Statistic to the Critical Value

We compare the calculated F value (2.51) with the critical value (2.54). Since 2.51 < 2.54, we fail to reject the null hypothesis.
05

Conclusion

Since we failed to reject the null hypothesis, there is not enough statistical evidence to support the claim that the variance for the old thermostat is greater than that for the new thermostat at a 5% level of significance. This suggests that the dependability (in terms of holding temperatures close to 25°F) of the new thermostat is at least equal to that of the old thermostat.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

F-test
The F-test is a statistical method used to compare two variances and decide whether they are significantly different from each other. In the context of the thermostat exercise, the F-test helps us evaluate if the variance in temperature regulation by the old thermostat is larger than that of the new one.

This begins with formulating the null hypothesis, which states that both variances are equal, and the alternative hypothesis, which suggests one variance is greater. By comparing sample variances using the F-test statistic formula \[ F = \frac{s_1^2}{s_2^2} \] where \(s_1^2\) and \(s_2^2\) are sample variances, the methodology helps us conclude whether to accept or reject the null hypothesis.

Derived from the ratio of these variances, the test statistic is a crucial piece of evidence to support or refuse a claim about the variability between the two groups, in this case, the old and new thermostats.
Variance Comparison
Variance comparison plays a key role in hypothesis testing, especially in analyses like those involving the F-test. Variance measures how much data in a set differ from the mean, and in this exercise, it reflects how consistently the thermostats maintain temperature at 25°F.

Understanding variance involves calculating the average of the squared differences from the mean of the data. For instance, the old thermostat had a variance of 12.8, while the new one had a variance of 5.1. These values indicate that the new thermostat regulates temperature fluctuations more tightly around 25°F than the old one.

Comparing variances tells us more than just which set has larger fluctuations; it can also provide insights into the efficiency and dependability of systems being tested. If one variance is significantly larger, it implies a larger spread of data points and potential inconsistency.
Level of Significance
The level of significance in hypothesis testing determines how confident we can be in our results. Denoted as \(\alpha\), it represents the probability of rejecting a true null hypothesis. In simpler terms, it measures the risk of concluding that there is an effect when, in fact, there isn’t.

In many scientific studies, a 5% level of significance (\(\alpha = 0.05\)) is standard, as used in the thermostat case study. This threshold indicates that there is only a 5% chance of incorrectly rejecting the null hypothesis – suggesting that the evidence needs to be quite robust to claim a difference in variances.

Choosing a level of significance is crucial because it affects the conclusion of the test. A lower \(\alpha\) makes it harder to find significance, while a higher \(\alpha\) might lead to more frequent false discoveries.
Dependability Analysis
Dependability analysis assesses how reliable a system is under specified conditions. In thermostat studies, dependability relates to how consistently each device can maintain the target temperature of 25°F.

This analysis involves checking whether systems perform as expected over time, reducing the likelihood of failures or deviations. By looking at the variance of each thermostat's temperature readings, we assess how predictable and stable their performance is.

If one thermostat shows significantly less variance, it is considered more dependable as it maintains the desired output with less fluctuation. Dependability analysis provides valuable insights, especially in quality control and maintenance, helping in design improvements and ensuring better performance.

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Most popular questions from this chapter

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