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Trevor conducted a study and found that the correlation between the price of a gallon of gasoline and gasoline consumption has a linear correlation coefficient of \(-0.7 .\) What does this result say about the relationship between price of gasoline and consumption? The study included gasoline prices ranging from \(\$ 2.70\) to \(\$ 5.30\) per gallon. Is it reliable to apply the results of this study to prices of gasoline higher than \(\$ 5.30\) per gallon? Explain.

Short Answer

Expert verified
The negative correlation means as gasoline price goes up, consumption decreases. Do not apply results beyond the study's price range.

Step by step solution

01

Understand the Correlation Coefficient

The correlation coefficient, denoted as \( r \), measures the strength and direction of the linear relationship between two variables. In this exercise, \( r = -0.7 \), indicating a negative correlation. This means that as the price of gasoline increases, consumption tends to decrease, and the strength of this correlation is moderately strong.
02

Assess the Domain of the Study

The study conducted by Trevor considered gasoline prices ranging from \( \\(2.70 \) to \( \\)5.30 \) per gallon. The results of the study are valid and reliable for data within this specific range because the correlation coefficient was calculated based on these data points.
03

Evaluate Extrapolation Beyond the Given Range

Extrapolating the results of the study to prices higher than \( \$5.30 \) per gallon can be unreliable. Beyond the studied price range, the underlying relationship between price and consumption might change, and without additional data or analysis for higher prices, we cannot confidently apply the same correlation coefficient.
04

Conclusion

The correlation of \(-0.7\) shows a moderately strong negative relationship between gasoline price and consumption within the given range of \( \\(2.70 \) to \( \\)5.30 \). However, it is not advisable to apply these results for gasoline prices above \( \$5.30 \) due to potential changes in trends or behavior not captured in the original study.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Negative Correlation
In statistics, a negative correlation occurs when two variables move in opposite directions. This means when one variable increases, the other tends to decrease. In Trevor's study, a correlation coefficient of \(-0.7\) links gasoline price and consumption, implying that as gasoline prices rise, the amount of gasoline consumed generally falls. This is captured by the negative sign before the coefficient. The strength of a correlation, whether negative or positive, ranges from \(-1\) to \(1\), with values closer to \(-1\) or \(1\) indicating stronger relationships.

A coefficient of \(-0.7\) suggests a moderately strong negative correlation. Although it is not perfectly negative (-1), it still shows a clear trend. Understanding this relationship helps in predicting how a change in price might influence consumer behavior, at least within the observed range.
Extrapolation
Extrapolation involves projecting or extending existing data to make predictions beyond the original scope. It's like predicting future weather based on past trends. In Trevor's gasoline study, the data considered prices from \(\(2.70\) to \(\)5.30\) per gallon. Using extrapolation to predict consumption at prices above \($5.30\) can be risky.

Why is it risky? As prices continue to rise beyond the study's range, other factors influencing consumption may emerge or change. People's behavior and market conditions aren't always linear beyond the observed data. Therefore, while the existing correlation might suggest a method, it doesn't guarantee accuracy outside the studied range.
  • Extrapolation assumes no change in underlying patterns, which might not hold true.
  • New variables might come into play at higher prices, altering the price-consumption relationship.
Given this uncertainty, it's crucial to be cautious with extrapolation in studies like Trevor's.
Correlation Coefficient
The correlation coefficient is a statistical measure, usually denoted as \(r\), representing the strength and direction of a linear relationship between two variables. In Trevor's study, \(r = -0.7\), providing insight into how price changes relate to consumption shifts. The value of \(r\) ranges from \(-1\) to \(1\):
  • A coefficient of \(1\) signifies a perfect positive correlation—both variables move in the same direction.
  • A coefficient of \(0\) means no linear relationship exists between the variables.
  • A coefficient of \(-1\) indicates a perfect negative correlation—variables move in opposite directions.

A moderately strong correlation of \(-0.7\) reveals significant, but not absolute, price-consumption dynamics within the tested range (\(\(2.70\) to \(\)5.30\) per gallon). By understanding \(r\), we gauge the reliability of predictions and their limitations. This understanding is crucial for applying statistical findings to real-world scenarios.

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Most popular questions from this chapter

A motion picture industry analyst is studying movies based on epic novels. The following data were obtained for 10 Hollywood movies made in the past five years. Each movie was based on an epic novel. For these data, \(x_{1}=\) first- year box office receipts of the movie, \(x_{2}=\) total production costs of the movie, \(x_{3}=\) total promotional costs of the movie, and \(x_{4}=\) total book sales prior to movie release. All units are in millions of dollars. $$ \begin{array}{rrrr|rrrr} \hline x_{1} & x_{2} & x_{3} & x_{4} & x_{1} & x_{2} & x_{3} & x_{4} \\ \hline 85.1 & 8.5 & 5.1 & 4.7 & 30.3 & 3.5 & 1.2 & 3.5 \\ 106.3 & 12.9 & 5.8 & 8.8 & 79.4 & 9.2 & 3.7 & 9.7 \\ 50.2 & 5.2 & 2.1 & 15.1 & 91.0 & 9.0 & 7.6 & 5.9 \\ 130.6 & 10.7 & 8.4 & 12.2 & 135.4 & 15.1 & 7.7 & 20.8 \\ 54.8 & 3.1 & 2.9 & 10.6 & 89.3 & 10.2 & 4.5 & 7.9 \\ \hline \end{array} $$ (a) Generate summary statistics, including the mean and standard deviation of each variable. Compute the coefficient of variation (see Section \(3.2\) ) for each variable. Relative to its mean, which variable has the largest spread of data values? Why would a variable with a large coefficient of variation be expected to change a lot relative to its average value? Although \(x_{1}\) has the largest standard deviation, it has the smallest coefficient of variation. How does the mean of \(x_{1}\) help explain this? (b) For each pair of variables, generate the sample correlation coefficient \(r\). Compute the corresponding coefficient of determination \(r^{2} .\) Which of the three variables \(x_{2}, x_{3}\), and \(x_{4}\) has the least influence on box office receipts? What percent of the variation in box office receipts can be attributed to the corresponding variation in production costs? (c) Perform a regression analysis with \(x_{1}\) as the response variable. Use \(x_{2}, x_{3}\), and \(x_{4}\) as explanatory variables. Look at the coefficient of multiple determination. What percentage of the variation in \(x_{1}\) can be explained by the corresponding variations in \(x_{2}, x_{3}\), and \(x_{4}\) taken together? (d) Write out the regression equation. Explain how each coefficient can be thought of as a slope. If \(x_{2}\) (production costs) and \(x_{4}\) (book sales) were held fixed but \(x_{3}\) (promotional costs) was increased by \(\$ 1\) million, what would you expect for the corresponding change in \(x_{1}\) (box office receipts)? (e) Test each coefficient in the regression equation to determine if it is zero or not zero. Use level of significance \(5 \%\). Explain why book sales \(x_{4}\) probably are not contributing much information in the regression model to forecast box office receipts \(x_{1}\). (f) Find a \(90 \%\) confidence interval for each coefficient. (g) Suppose a new movie (based on an epic novel) has just been released. Production costs were \(x_{2}=11.4\) million; promotion costs were \(x_{3}=4.7\) million; book sales were \(x_{4}=8.1\) million. Make a prediction for \(x_{1}=\) firstyear box office receipts and find an \(85 \%\) confidence interval for your prediction (if your software supports prediction intervals). (h) Construct a new regression model with \(x_{3}\) as the response variable and \(x_{1}\), \(x_{2}\), and \(x_{4}\) as explanatory variables. Suppose Hollywood is planning a new epic movie with projected box office sales \(x_{1}=100\) million and production costs \(x_{2}=12\) million. The book on which the movie is based had sales of \(x_{4}=9.2\) million. Forecast the dollar amount (in millions) that should be budgeted for promotion costs \(x_{3}\) and find an \(80 \%\) confidence interval for your prediction.

The following data are based on information from the Harvard Business Review (Vol. 72, No. 1). Let \(x\) be the number of different research programs, and let \(y\) be the mean number of patents per program. As in any business, a company can spread itself too thin. For example, too many research programs might lead to a decline in overall research productivity. The following data are for a collection of pharmaceutical companies and their research programs: $$ \begin{array}{l|rrrrrr} \hline x & 10 & 12 & 14 & 16 & 18 & 20 \\ \hline y & 1.8 & 1.7 & 1.5 & 1.4 & 1.0 & 0.7 \\ \hline \end{array} $$ Complete parts (a) through (e), given \(\Sigma x=90, \Sigma y=8.1, \Sigma x^{2}=1420\), \(\Sigma y^{2}=11.83, \Sigma x y=113.8\), and \(r \approx-0.973 .\) (f) Suppose a pharmaceutical company has 15 different research programs. What does the least-squares equation forecast for \(y=\) mean number of patents per program?

The following data are based on information from the book Life in America's Small Cities (by G. S. Thomas, Prometheus Books). Let \(x\) be the percentage of 16 - to 19 -year-olds not in school and not high school graduates. Let \(y\) be the reported violent crimes per 1000 residents. Six small cities in Arkansas (Blytheville, El Dorado, Hot Springs, Jonesboro, Rogers, and Russellville) reported the following information about \(x\) and \(y\) : $$ \begin{array}{l|llllll} \hline x & 24.2 & 19.0 & 18.2 & 14.9 & 19.0 & 17.5 \\ \hline y & 13.0 & 4.4 & 9.3 & 1.3 & 0.8 & 3.6 \\ \hline \end{array} $$ Complete parts (a) through (e), given \(\Sigma x=112.8, \Sigma y=32.4, \Sigma x^{2}=2167.14\), \(\Sigma y^{2}=290.14, \Sigma x y=665.03\), and \(r \approx 0.764\). (f) If the percentage of 16 - to 19 -year-olds not in school and not graduates reaches \(24 \%\) in a similar city, what is the predicted rate of violent crimes per 1000 residents?

Over the past 30 years in the United States, there has been a strong negative correlation between the number of infant deaths at birth and the number of people over age 65 . (a) Is the fact that people are living longer causing a decrease in infant mortalities at birth? (b) What lurking variables might be causing the increase in one or both of the variables? Explain.

Given the linear regression equation $$ x_{1}=1.6+3.5 x_{2}-7.9 x_{3}+2.0 x_{4} $$ (a) Which variable is the response variable? Which variables are the explanatory variables? (b) Which number is the constant term? List the coefficients with their corresponding explanatory variables. (c) If \(x_{2}=2, x_{3}=1\), and \(x_{4}=5\), what is the predicted value for \(x_{1} ?\) (d) Explain how each coefficient can be thought of as a "slope" under certain conditions. Suppose \(x_{3}\) and \(x_{4}\) were held at fixed but arbitrary values and \(x_{2}\) was increased by 1 unit. What would be the corresponding change in \(x_{1}\) ? Suppose \(x_{2}\) increased by 2 units. What would be the expected change in \(x_{1} ?\) Suppose \(x_{2}\) decreased by 4 units. What would be the expected change in \(x_{1} ?\) (e) Suppose that \(n=12\) data points were used to construct the given regression equation and that the standard error for the coefficient of \(x_{2}\) is \(0.419\). Construct a \(90 \%\) confidence interval for the coefficient of \(x_{2}\). (f) Using the information of part (e) and level of significance \(5 \%\), test the claim that the coefficient of \(x_{2}\) is different from zero. Explain how the conclusion of this test would affect the regression equation.

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