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Answer true or false. Explain your answer. For the same random sample, when the confidence level \(c\) is reduced, the confidence interval for \(\mu\) becomes shorter.

Short Answer

Expert verified
True, reducing the confidence level shortens the confidence interval for \(\mu\).

Step by step solution

01

Understanding Confidence Level and Interval

The confidence level, denoted by \(c\), represents the probability that the true parameter (e.g., population mean \(\mu\)) lies within the confidence interval. It is usually expressed as a percentage, such as 95%.
02

Effect of Confidence Level on Interval Width

A higher confidence level means a wider interval because we require more certainty that the true parameter lies within the interval, accommodating for greater variability. Conversely, a lower confidence level allows a narrower interval as we accept a higher chance of the parameter not being included in the interval.
03

Mathematical Explanation

The formula for a confidence interval around the mean \(\mu\) is given by \( \bar{x} \pm z^* \left( \frac{s}{\sqrt{n}} \right) \), where \(\bar{x}\) is the sample mean, \(s\) is the sample standard deviation, \(n\) is the sample size, and \(z^*\) is the z-score corresponding to the confidence level. As \(c\) decreases, \(z^*\) decreases, leading to a smaller margin of error \(z^* \left( \frac{s}{\sqrt{n}} \right)\), thus shortening the confidence interval.
04

Conclusion

When the confidence level \(c\) is reduced, the confidence interval for \(\mu\) becomes shorter because a lower \(z^*\) value results in a reduced margin of error. Hence, the statement is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Level
Confidence level is a core concept when discussing confidence intervals. It tells us how sure we can be that the confidence interval contains the true population parameter, like the population mean (\( \mu \)). For example, a 95% confidence level implies that if we were to collect multiple samples, 95 out of 100 would contain the true parameter value.

A higher confidence level offers more assurance but at the cost of wider intervals. This means, to be more confident in covering the true mean, we expand the range. Conversely, reducing the confidence level makes the interval narrower, indicating a higher risk of not covering the true parameter but less spread.

Understanding this trade-off is crucial in statistical analysis, where you must balance certainty and precision.
Margin of Error
The margin of error in statistics gives you a range within which you can expect the true population parameter to fall. It's directly influenced by the confidence level and the z-score. The formula often used is: \[ \text{Margin of Error} = z^* \left( \frac{s}{\sqrt{n}} \right) \]Here,
  • \(z^*\) is the z-score corresponding to your chosen confidence level.
  • \(s\) stands for sample standard deviation.
  • \(n\) represents the sample size.
An increased margin of error creates a wider confidence interval, suggesting that you need a larger 'buffer' to ensure the interval includes the true population mean.

If the confidence level goes down, the z-score decreases, leading to a smaller margin of error and thus a narrower confidence interval.
Z-Score
The z-score is a statistical measurement describing a value's relation to the mean of a group of values. In the context of confidence intervals, the z-score represents how many standard deviations you have to go from the mean to cover a certain percentage of the data. The z-score can be found using z-tables or standard normal distribution tables, providing the precise score for a given confidence level.

For example, a 95% confidence level often corresponds to a z-score of approximately 1.96. As confidence levels decrease, the z-score drops. This reduction narrows the range of the confidence interval, indicating less certainty but tighter estimates. Adjusting the z-score according to the confidence level is key when determining the reliability and scope of your statistical inference.
Population Mean
The population mean (denoted as \(\mu\)) is a central value that represents the average of a set entire data population. It is a theoretical concept as, in many cases, you can not measure every single item within a population.

In practice, we approximate the population mean using a sample mean \(\bar{x}\) taken from a smaller, random sample. The confidence interval provides an estimated range for the population mean based on the sample data.

Understanding the population mean's role helps you realize why confidence intervals are made: to estimate the possible range within which this mean could lie with a stated level of confidence. The role of statistical formulas is to make sure that predictions about \(\mu\) are both reliable and valid, despite variations across different samples.

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Most popular questions from this chapter

Assume that the population of \(x\) values has an approximately normal distribution. Archaeology: Tree Rings At Burnt Mesa Pueblo, the method of tree-ring dating gave the following years A.D. for an archaeological excavation site (Bandelier Archaeological Excavation Project: Summer 1990 Excavations at Burnt Mesa Pueblo, edited by Kohler, Washington State University): \(\begin{array}{lllllllll}1189 & 1271 & 1267 & 1272 & 1268 & 1316 & 1275 & 1317 & 1275\end{array}\) (a) Use a calculator with mean and standard deviation keys to verify that the sample mean year is \(\bar{x} \approx 1272\), with sample standard deviation \(s \approx 37\) years. (b) Find a \(90 \%\) confidence interval for the mean of all tree-ring dates from this archaeological site. (c) Interpretation What does the confidence interval mean in the context of this problem?

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Small Business: Bankruptcy The National Council of Small Businesses is interested in the proportion of small businesses that declared Chapter 11 bankruptcy last year. Since there are so many small businesses, the National Council intends to estimate the proportion from a random sample. Let \(p\) be the proportion of small businesses that declared Chapter 11 bankruptcy last year. (a) If no preliminary sample is taken to estimate \(p\), how large a sample is necessary to be \(95 \%\) sure that a point estimate \(\hat{p}\) will be within a distance of \(0.10\) from \(p\) ? (b) In a preliminary random sample of 38 small businesses, it was found that six had declared Chapter 11 bankruptcy. How many more small businesses should be included in the sample to be \(95 \%\) sure that a point estimate \(\hat{p}\) will be within a distance of \(0.10\) from \(p\) ?

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