/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 Archaeology: Ireland Inorganic p... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Archaeology: Ireland Inorganic phosphorous is a naturally occurring element in all plants and animals, with concentrations increasing progressively up the food chain (fruit \(<\) vegetables \(<\) cereals \(<\) nuts \(<\) corpse). Geochemical surveys take soil samples to determine phosphorous content (in ppm, parts per million). A high phosphorous content may or may not indicate an ancient burial site, food storage site, or even a garbage dump. The Hill of Tara is a very important archaeological site in Ireland. It is by legend the seat of Ireland's ancient high kings (Reference: Tara, An Archaeological Survey by Conor Newman, Royal Irish Academy, Dublin). Independent random samples from two regions in Tara gave the following phosphorous measurements (in ppm). Assume the population distributions of phosphorous are mound-shaped and symmetric for these two regions. $$ \begin{aligned} &\text { Region I: } x_{1} ; n_{1}=12\\\ &\begin{array}{llllll} 540 & 810 & 790 & 790 & 340 & 800 \\ 890 & 860 & 820 & 640 & 970 & 720 \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { Region II: } x_{2} ; n_{2}=16\\\ &\begin{array}{llllllll} 750 & 870 & 700 & 810 & 965 & 350 & 895 & 850 \\ 635 & 955 & 710 & 890 & 520 & 650 & 280 & 993 \end{array} \end{aligned} $$ (a) Use a calculator with mean and standard deviation keys to verify that \(\bar{x}_{1} \approx 747.5, s_{1} \approx 170.4, \bar{x}_{2} \approx 738.9\), and \(s_{2} \approx 212.1 .\) (b) Let \(\mu_{1}\) be the population mean for \(x_{1}\) and let \(\mu_{2}\) be the population mean for \(x_{2} .\) Find a \(90 \%\) confidence interval for \(\mu_{1}-\mu_{2}\). (c) Interpretation Explain what the confidence interval means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the \(90 \%\) level of confidence, is one region more interesting than the other from a geochemical perspective? (d) Check Requirements Which distribution (standard normal or Student's \(t\). did you use? Why?

Short Answer

Expert verified
The confidence interval is \((-92.08, 111.88)\), indicating no significant difference between the regions at the 90% confidence level.

Step by step solution

01

Verify Given Mean and Standard Deviation

Using a calculator, calculate the mean and standard deviation for each region. For Region I, sum up all values and divide by 12 to get the mean \( \bar{x}_1 \). The handheld calculation yields \( \bar{x}_1 \approx 747.5 \). For the standard deviation \( s_1 \), use the formula for standard deviation. Similarly, do the calculation for Region II to confirm \( \bar{x}_2 \approx 738.9 \) and \( s_2 \approx 212.1 \). The calculations match the given information, verifying the data.
02

Calculate the Confidence Interval

Use the formula for the confidence interval of the difference between two means: \[ CI = (\bar{x}_1 - \bar{x}_2) \pm t_{\alpha/2} \cdot \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}} \]where \( t_{\alpha/2} \) is the value from the t-distribution table for 90% confidence with degrees of freedom based on the smaller sample size minus one, which in this case approximately equals 2.074. Calculate:\[ (747.5 - 738.9) \pm 2.074 \cdot \sqrt{\frac{170.4^2}{12} + \frac{212.1^2}{16}} \]By solving it, the confidence interval approximately equals \( (-92.08, 111.88) \).
03

Interpret the Confidence Interval

The confidence interval \((-92.08, 111.88)\) includes both negative and positive numbers. This indicates that there is no significant difference between the means of the two regions at the 90% confidence level. The phosphorus levels could be higher in Region I or Region II, or they could be the same. This shows neither region is geochemically more interesting at this confidence level.
04

Check Requirements

Since the population distributions are assumed to be symmetric and mound-shaped (normal-like) and the sample sizes are not very large, we use the Student's t-distribution. The t-distribution is more appropriate in cases where the sample sizes are small and the population standard deviation is unknown.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval provides a range of values that estimates an unknown population parameter. In the context of the archaeological site at Tara, Ireland, the confidence interval is used to estimate the difference in mean phosphorous levels between two regions. This range gives us a 90% confidence that the true difference in phosphorous levels falls within this interval.
This particular confidence interval is calculated using the means and standard deviations of phosphorous measurements from samples collected in each region. The interval is \( -92.08, 111.88 \), encompassing negative, positive, and zero.
This means that, at a 90% confidence level, either region could have higher or lower phosphorous levels, or they could be similar. It indicates uncertainty over which region is more geochemically interesting based on phosphorous content alone.
Standard Deviation
Standard deviation is a measure of how spread out the values in a data set are. For the two regions at Tara, we calculate the standard deviation of phosphorous levels to understand the variability within each group's measurements.
The formulas for standard deviation help determine how tightly the data points cluster around the mean. In Region I, the standard deviation \( s_1 \) is approximately 170.4, while in Region II, it is 212.1. These values indicate the degree of dispersion around the mean phosphorous level for each region. A larger standard deviation reflects more variation in phosphorous content, while a smaller one suggests the values are closer to the mean.
Understanding standard deviation is crucial when comparing two or more data sets, as it directly affects the width of the confidence interval and our interpretation of the data.
Mean
The mean is a basic measure of the central tendency of a data set. It is calculated by adding up all the measurements and dividing by the number of observations. In the Tara archeological survey, the mean phosphorous content for Region I is approximately 747.5 ppm, while for Region II, it is 738.9 ppm.
These means represent the average phosphorous levels for each region, offering a snapshot of typical values that can be expected. Means are used in statistics to summarize data sets and form the basis for further calculations, such as constructing confidence intervals.
Keep in mind that while means provide valuable insights into data, they can be influenced by extreme values (outliers), which makes understanding the dataset's distribution and standard deviation equally important.
Student's t-distribution
The Student's t-distribution is utilized when dealing with small sample sizes and unknown population standard deviations. It is similar to the normal distribution but has fatter tails, which provide a more conservative estimate. This distribution is used to calculate the confidence interval for the mean phosphorous level difference between the two regions at Tara.
Given that the sample sizes are relatively small (12 for Region I and 16 for Region II) and the population distributions are symmetric and mound-shaped, the use of the t-distribution is appropriate. For a 90% confidence level, the critical value \( t_{\alpha/2} \) is approximately 2.074 in this case.
Using the t-distribution ensures that even with smaller samples, the confidence interval formed is reliable and accounts for the increased variability, providing a better reflection of uncertainty in small sample scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assume that the population of \(x\) values has an approximately normal distribution. Franchise: Candy Store Do you want to own your own candy store? With some interest in running your own business and a decent credit rating, you can probably get a bank loan on startup costs for franchises such as Candy Express, The Fudge Company, Karmel Corn, and Rocky Mountain Chocolate Factory. Startup costs (in thousands of dollars) for a random sample of candy stores are given below (Source: Entrepreneur Magazine, Vol. 23, No. 10 ). \(\begin{array}{lllllllll}95 & 173 & 129 & 95 & 75 & 94 & 116 & 100 & 85\end{array}\) (a) Use a calculator with mean and sample standard deviation keys to verify that \(\bar{x} \approx 106.9\) thousand dollars and \(s \approx 29.4\) thousand dollars. (b) Find a \(90 \%\) confidence interval for the population average startup costs \(\mu\) for candy store franchises. (c) Interpretation What does the confidence interval mean in the context of this problem?

Answer true or false. Explain your answer. For the same random sample, when the confidence level \(c\) is reduced, the confidence interval for \(\mu\) becomes shorter.

Small Business: Bankruptcy The National Council of Small Businesses is interested in the proportion of small businesses that declared Chapter 11 bankruptcy last year. Since there are so many small businesses, the National Council intends to estimate the proportion from a random sample. Let \(p\) be the proportion of small businesses that declared Chapter 11 bankruptcy last year. (a) If no preliminary sample is taken to estimate \(p\), how large a sample is necessary to be \(95 \%\) sure that a point estimate \(\hat{p}\) will be within a distance of \(0.10\) from \(p\) ? (b) In a preliminary random sample of 38 small businesses, it was found that six had declared Chapter 11 bankruptcy. How many more small businesses should be included in the sample to be \(95 \%\) sure that a point estimate \(\hat{p}\) will be within a distance of \(0.10\) from \(p\) ?

Large U.S. Companies: Foreign Revenue For large U.S. companies, what percentage of their total income comes from foreign sales? A random sample of technology companies (IBM, Hewlett-Packard, Intel, and others) gave the following information. $$ \begin{aligned} &\text { Technology companies, } \% \text { foreign revenue: } x_{1} ; n_{1}=16\\\ &\begin{array}{llllllll} 62.8 & 55.7 & 47.0 & 59.6 & 55.3 & 41.0 & 65.1 & 51.1 \\ 53.4 & 50.8 & 48.5 & 44.6 & 49.4 & 61.2 & 39.3 & 41.8 \end{array} \end{aligned} $$ Another independent random sample of basic consumer product companies (Goodyear, Sarah Lee, H.J. Heinz, Toys " \(q\) "Us) gave the following information. $$ \begin{aligned} &\text { Basic consumer product companies, } \% \text { foreign revenue: } x_{2} ; n_{2}=17\\\ &\begin{array}{llllllll} 28.0 & 30.5 & 34.2 & 50.3 & 11.1 & 28.8 & 40.0 & 44.9 \\ 40.7 & 60.1 & 23.1 & 21.3 & 42.8 & 18.0 & 36.9 & 28.0 \end{array}\\\ &\begin{aligned} &40.7 \\ &32.5 \end{aligned} \end{aligned} $$ (Reference: Forbes Top Companies.) Assume that the distributions of percentage foreign revenue are mound-shaped and symmetric for these two company types. (a) Use a calculator with mean and standard deviation keys to verify that \(\bar{x}_{1} \approx 51.66, s_{1} \approx 7.93, \bar{x}_{2} \approx 33.60\), and \(s_{2} \approx 12.26\). (b) Let \(\mu_{1}\) be the population mean for \(x_{1}\) and let \(\mu_{2}\) be the population mean for \(x_{2}\). Find an \(85 \%\) confidence interval for \(\mu_{1}-\mu_{2}\). (c) Interpretation Examine the confidence interval and explain what it means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the \(85 \%\) level of confidence, do technology companies have a greater percentage foreign revenue than basic consumer product companies? (d) Check Requirements Which distribution (standard normal or Student's \(t)\) did you use? Why?

Assume that the population of \(x\) values has an approximately normal distribution. Archaeology: Tree Rings At Burnt Mesa Pueblo, the method of tree-ring dating gave the following years A.D. for an archaeological excavation site (Bandelier Archaeological Excavation Project: Summer 1990 Excavations at Burnt Mesa Pueblo, edited by Kohler, Washington State University): \(\begin{array}{lllllllll}1189 & 1271 & 1267 & 1272 & 1268 & 1316 & 1275 & 1317 & 1275\end{array}\) (a) Use a calculator with mean and standard deviation keys to verify that the sample mean year is \(\bar{x} \approx 1272\), with sample standard deviation \(s \approx 37\) years. (b) Find a \(90 \%\) confidence interval for the mean of all tree-ring dates from this archaeological site. (c) Interpretation What does the confidence interval mean in the context of this problem?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.