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Josh and Kendra each calculated a \(90 \%\) confidence interval for the difference of means using a Student's \(t\) distribution for random samples of size \(n_{1}=20\) and \(n_{2}=31\). Kendra followed the convention of using the smaller sample size to compute d.f. \(=19 .\) Josh used his calculator and Satterthwaite's approximation and obtained \(d . f . \approx 36.3 .\) Which confidence interval is shorter? Which confidence interval is more conservative in the sense that the margin of error is larger?

Short Answer

Expert verified
Josh's confidence interval is shorter; Kendra's is more conservative.

Step by step solution

01

Identify the Parameters and Formulas

We have two sample sizes: \(n_1 = 20\) and \(n_2 = 31\). Kendra uses degrees of freedom (d.f.) of 19, while Josh uses an approximate d.f. of 36.3 using Satterthwaite's approximation. The margin of error for a confidence interval is given by the formula \( E = t_{\alpha/2} \times SE \), where \( t_{\alpha/2} \) is the critical value from the \( t \)-distribution and \( SE \) is the standard error.
02

Understanding Degrees of Freedom (d.f.) Impact

The degrees of freedom affect the critical value \( t_{\alpha/2} \). A smaller d.f. results in a larger critical \( t \)-value, increasing the margin of error and thus making the confidence interval wider. Kendra's d.f. of 19 will have a larger \( t \)-value compared to Josh's d.f. of 36.3.
03

Critical t-Value for Kendra and Josh

For a 90% confidence interval, look up the critical \( t \)-values: \( t_{0.05} \) for d.f. = 19 is approximately 1.729, and for d.f. = 36.3, we'll approximate \( t_{0.05} \) to be slightly less, around 1.685 from a standard table.
04

Comparing the Confidence Intervals

Since Josh has a smaller critical \( t \)-value due to a larger d.f., his confidence interval will be shorter. Kendra's larger critical \( t \)-value results in a larger margin of error, so her confidence interval is more conservative.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Intervals
A confidence interval is a range of values that is used to estimate an unknown population parameter. This range is derived from a sample statistic and is designed to capture the parameter with a certain level of confidence, usually expressed as a percentage, such as 90%, 95%, or 99%.
Confidence intervals provide a way to understand how reliable the estimated parameter is by showing the degree of uncertainty we have about it. A 90% confidence interval, for example, suggests that if you were to take numerous samples and construct a confidence interval from each sample, then approximately 90% of those intervals will contain the true population parameter.
  • The width of the confidence interval gives an idea of the precision of the estimate: narrow intervals suggest more precise estimates, while wider intervals suggest less precision.
  • Factors affecting the width include sample size and variability within the data. Larger samples and less variable data produce narrower confidence intervals.
  • The confidence level chosen affects the range: higher confidence levels lead to wider intervals because they account for more uncertainty by choosing a larger portion of the distribution.
In statistical analysis, it's important to report not only the estimate but also the confidence interval to provide a full picture of the data's implications.
Degrees of Freedom
Degrees of freedom (d.f.) is a crucial concept in statistics that refers to the number of values in a statistical calculation that are free to vary. It plays a critical role in defining the shape of the probability distributions used in tests and intervals.
In practical terms, degrees of freedom are used to determine the appropriate critical value in statistical tests. For instance, in the context of Josh and Kendra's exercise, degrees of freedom influence the exact shape of the Student's t-distribution, which in turn affects the width of the confidence intervals.
  • Using a smaller degrees of freedom yields a higher critical value and thus a wider confidence interval, making it more conservative.
  • Larger degrees of freedom usually mean that the sample size is larger, which lowers the critical t-value and usually results in a narrower interval.
In situations with two sample sizes, like in the exercise, techniques such as Satterthwaite's approximation can be used to estimate degrees of freedom instead of simply choosing the smaller sample size. This approach typically provides a better approximation of the actual distribution from which data is drawn, refining the precision of the confidence interval.
Student's t-Distribution
The Student's t-distribution is a probability distribution that is a staple in inferential statistics, particularly with smaller sample sizes or when the population standard deviation is unknown. It's similar to the normal distribution but has heavier tails, which means it accounts for more variability.
This distribution becomes important in calculating confidence intervals and conducting hypothesis tests when sample sizes are relatively small, say below 30, as in the exercise with Josh and Kendra.
  • The t-distribution's exact shape is determined by the degrees of freedom. With fewer degrees of freedom, the tails of the t-distribution are thicker, reflecting more uncertainty and variability, which is why Kendra's interval was wider due to a smaller d.f. of 19.
  • As sample sizes increase (and thus degrees of freedom), the t-distribution approaches the normal distribution. This is why Josh's approximation using a larger d.f. results in a narrower interval.
Overall, the Student's t-distribution provides a more flexible model when dealing with small samples, allowing statisticians to make more accurate inferences about population parameters, even with limited data.

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Most popular questions from this chapter

Jerry tested 30 laptop computers owned by classmates enrolled in a large computer science class and discovered that 22 were infected with keystroke- tracking spyware. Is it appropriate for Jerry to use his data to estimate the proportion of all laptops infected with such spyware? Explain.

Basic Computation: Confidence Interval Suppose \(x\) has a mound-shaped distribution. A random sample of size 16 has sample mean 10 and sample standard deviation \(2 .\) (a) Check Requirements Is it appropriate to use a Student's \(t\) distribution to compute a confidence interval for the population mean \(\mu ?\) Explain. (b) Find a \(90 \%\) confidence interval for \(\mu .\) (c) Interpretation Explain the meaning of the confidence interval you computed.

Answer true or false. Explain your answer. For the same random sample, when the confidence level \(c\) is reduced, the confidence interval for \(\mu\) becomes shorter.

Focus Problem: Wood Duck Nests In the Focus Problem at the beginning of this chapter, a study was described comparing the hatch ratios of wood duck nesting boxes. Group I nesting boxes were well separated from each other and well hidden by available brush. There were a total of 474 eggs in group I boxes, of which a field count showed about 270 had hatched. Group II nesting boxes were placed in highly visible locations and grouped closely together. There were a total of 805 eggs in group II boxes, of which a field count showed about 270 had hatched. (a) Find a point estimate \(\hat{p}_{1}\) for \(p_{1}\), the proportion of eggs that hatched in group I nest box placements. Find a \(95 \%\) confidence interval for \(p_{1}\). (b) Find a point estimate \(\hat{p}_{2}\) for \(p_{2}\), the proportion of eggs that hatched in group II nest box placements. Find a \(95 \%\) confidence interval for \(p_{2}\). (c) Find a \(95 \%\) confidence interval for \(p_{1}-p_{2}\). Does the interval indicate that the proportion of eggs hatched from group I nest boxes is higher than, lower than, or equal to the proportion of eggs hatched from group II nest boxes? (d) Interpretation What conclusions about placement of nest boxes can be drawn? In the article discussed in the Focus Problem, additional concerns are raised about the higher cost of placing and maintaining group I nest box placements. Also at issue is the cost efficiency per successful wood duck hatch.

Assume that the population of \(x\) values has an approximately normal distribution. Franchise: Candy Store Do you want to own your own candy store? With some interest in running your own business and a decent credit rating, you can probably get a bank loan on startup costs for franchises such as Candy Express, The Fudge Company, Karmel Corn, and Rocky Mountain Chocolate Factory. Startup costs (in thousands of dollars) for a random sample of candy stores are given below (Source: Entrepreneur Magazine, Vol. 23, No. 10 ). \(\begin{array}{lllllllll}95 & 173 & 129 & 95 & 75 & 94 & 116 & 100 & 85\end{array}\) (a) Use a calculator with mean and sample standard deviation keys to verify that \(\bar{x} \approx 106.9\) thousand dollars and \(s \approx 29.4\) thousand dollars. (b) Find a \(90 \%\) confidence interval for the population average startup costs \(\mu\) for candy store franchises. (c) Interpretation What does the confidence interval mean in the context of this problem?

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