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Answer true or false. Explain your answer. If the sample mean \(\bar{x}\) of a random sample from an \(x\) distribution is relatively small, then the confidence interval for \(\mu\) will be relatively short.

Short Answer

Expert verified
False; the sample mean \( \bar{x} \) does not affect the width of the confidence interval.

Step by step solution

01

Understanding the Problem

We need to determine whether a smaller sample mean \( \bar{x} \) leads to a shorter confidence interval for the population mean \( \mu \). A confidence interval is a range of values that estimates where the true population parameter lies based on the sample.
02

Components of the Confidence Interval

A confidence interval for the population mean \( \mu \) is given by:\[\bar{x} \pm z \cdot \frac{s}{\sqrt{n}}\]where \( z \) is the z-score corresponding to the desired confidence level, \( s \) is the sample standard deviation, and \( n \) is the sample size. Notice that the length of the interval is primarily affected by \( s \) and \( n \), not \( \bar{x} \).
03

Analyzing the Effect of Sample Mean

The sample mean \( \bar{x} \) does not directly affect the width of the confidence interval. Instead, the width is determined by the standard error \( \frac{s}{\sqrt{n}} \) and the z-score. Therefore, a smaller or larger sample mean does not inherently make the interval shorter or longer.
04

Conclusion

Since the sample mean \( \bar{x} \) does not appear in the formula for the width of the confidence interval, it does not influence the shortness or length of the interval. The claim is therefore false.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean, often denoted as \( \bar{x} \), is a measure of the central tendency of a set of data drawn from a larger population. It's calculated by taking the sum of all the sample values and dividing it by the number of values in the sample. The formula for the sample mean is:

\[ \bar{x} = \frac{1}{n} \sum_{i=1}^{n} x_i \]

Where \( n \) is the sample size, and \( x_i \) represents each individual data point in the sample. The sample mean is important because it provides an estimate of the population mean, helping us understand more about the whole set of data from just a part of it.

Even though the sample mean is critical in understanding data, it doesn't affect how wide a confidence interval is. The interval's length is determined by other factors.
Population Mean
The population mean, denoted by \( \mu \), is the average of all the values in a population. Unlike the sample mean, it's a fixed value representing the entire group. To calculate the population mean, you would sum up all the individual data points in the population and divide by the population size.

In real-world scenarios, we rarely know the population mean because it involves every single member of the population, which is often impractical. Therefore, we use the sample mean as an estimate. It’s important to realize that the confidence interval aims to capture this population mean, giving us a range within which \( \mu \) likely falls, but the sample mean itself does not affect the width of this range.
Standard Error
The standard error of the mean, represented as \( \frac{s}{\sqrt{n}} \), is a key component in determining the width of a confidence interval. It measures the spread, or variability, of the sample mean around the population mean. Here, \( s \) is the sample standard deviation, and \( n \) is the sample size.

Standard error can be seen as the standard deviation of the sample means, showing how much sample means would vary if you took many samples from the population. A smaller standard error means that the sample mean is closer to the population mean, and it generally leads to a shorter confidence interval.

Factors like the sample's variability and size influence the standard error, making it crucial for interpreting data accurately.
Sample Size
Sample size, denoted as \( n \), refers to the number of observations in your sample. It is a fundamental factor in determining the confidence interval’s width. A larger sample size leads to a smaller standard error, shrinking the confidence interval and providing a more precise estimate of the population mean. This relationship is described by the formula for standard error, \( \frac{s}{\sqrt{n}} \), where increasing \( n \) decreases the overall value.

However, acquiring a larger sample can be resource-intensive and sometimes impractical. Therefore, researchers must balance between obtaining a large enough sample to reduce error while considering constraints like time and cost. Understanding the influence of sample size on confidence intervals helps in designing better studies and drawing accurate conclusions.

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Most popular questions from this chapter

Navajo Lifestyle: Traditional Hogans A random sample of 5222 permanent dwellings on the entire Navajo Indian Reservation showed that 1619 were traditional Navajo hogans (Navajo Architecture: Forms, History, Distributions by Jett and Spencer, University of Arizona Press). (a) Let \(p\) be the proportion of all permanent dwellings on the entire Navajo Reservation that are traditional hogans. Find a point estimate for \(p\). (b) Find a \(99 \%\) confidence interval for \(p .\) Give a brief interpretation of the confidence interval. (c) Check Requirements Do you think that \(n p>5\) and \(n q>5\) are satisfied for this problem? Explain why this would be an important consideration.

Suppose \(x\) has a mound-shaped distribution with \(\sigma=9\). A random sample of size 36 has sample mean 20 . (a) Check Requirements Is it appropriate to use a normal distribution to compute a confidence interval for the population mean \(\mu\) ? Explain. (b) Find a \(95 \%\) confidence interval for \(\mu .\) (c) Interpretation Explain the meaning of the confidence interval you computed

Yellowstone National Park: Old Faithful Geyser The U.S. Geological Survey compiled historical data about Old Faithful Geyser (Yellowstone National Park) from 1870 to \(1987 .\) Some of these data are published in the book The Story of Old Faithful, by G. D. Marler (Yellowstone Association Press). Let \(x_{1}\) be a random variable that represents the time interval (in minutes) between Old Faithful's eruptions for the years 1948 to \(1952 .\) Based on 9340 observations, the sample mean interval was \(\bar{x}_{1}=63.3\) minutes. Let \(x_{2}\) be a random variable that represents the time interval in minutes between Old Faithful's eruptions for the years 1983 to 1987 . Based on 25,111 observations, the sample mean time interval was \(\bar{x}_{2}=72.1\) minutes. Historical data suggest that \(\sigma_{1}=9.17\) minutes and \(\sigma_{2}=12.67\) minutes. Let \(\mu_{1}\) be the population mean of \(x_{1}\) and let \(\mu_{2}\) be the population mean of \(x_{2}\). (a) Check Requirements Which distribution, normal or Student's \(t\), do we use to approximate the \(\bar{x}_{1}-\bar{x}_{2}\) distribution? Explain. (b) Compute a \(99 \%\) confidence interval for \(\mu_{1}-\mu_{2}\). (c) Interpretation Comment on the meaning of the confidence interval in the context of this problem. Does the interval consist of positive numbers only? negative numbers only? a mix of positive and negative numbers? Does it appear (at the \(99 \%\) confidence level) that a change in the interval length between eruptions has occurred? Many geologic experts believe that the distribution of eruption times of Old Faithful changed after the major earthquake that occurred in 1959 .

Expand Your Knowledge: Alternate Method for Confidence Intervals When \(\sigma\) is unknown and the sample is of size \(n \geq 30\), there are two methods for computing confidence intervals for \(\mu\). Method 1: Use the Student's \(t\) distribution with d.f. \(=n-1\). This is the method used in the text. It is widely employed in statistical studies. Also, most statistical software packages use this method. Method 2: When \(n \geq 30\), use the sample standard deviation \(s\) as an estimate for \(\sigma\), and then use the standard normal distribution. This method is based on the fact that for large samples, \(s\) is a fairly good approximation for \(\sigma\). Also, for large \(n\), the critical values for the Student's \(t\) distribution approach those of the standard normal distribution. Consider a random sample of size \(n=31\), with sample mean \(\bar{x}=45.2\) and sample standard deviation \(s=5.3\). (a) Compute \(90 \%, 95 \%\), and \(99 \%\) confidence intervals for \(\mu\) using Method 1 with a Student's \(t\) distribution. Round endpoints to two digits after the decimal. (b) Compute \(90 \%, 95 \%\), and \(99 \%\) confidence intervals for \(\mu\) using Method 2 with the standard normal distribution. Use \(s\) as an estimate for \(\sigma\). Round endpoints to two digits after the decimal. (c) Compare intervals for the two methods. Would you say that confidence intervals using a Student's \(t\) distribution are more conservative in the sense that they tend to be longer than intervals based on the standard normal distribution? (d) Repeat parts (a) through (c) for a sample of size \(n=81\). With increased sample size, do the two methods give respective confidence intervals that are more similar?

Answer true or false. Explain your answer. The point estimate for the population mean \(\mu\) of an \(x\) distribution is \(\bar{x}\), computed from a random sample of the \(x\) distribution.

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