/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Navajo Lifestyle: Traditional Ho... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Navajo Lifestyle: Traditional Hogans A random sample of 5222 permanent dwellings on the entire Navajo Indian Reservation showed that 1619 were traditional Navajo hogans (Navajo Architecture: Forms, History, Distributions by Jett and Spencer, University of Arizona Press). (a) Let \(p\) be the proportion of all permanent dwellings on the entire Navajo Reservation that are traditional hogans. Find a point estimate for \(p\). (b) Find a \(99 \%\) confidence interval for \(p .\) Give a brief interpretation of the confidence interval. (c) Check Requirements Do you think that \(n p>5\) and \(n q>5\) are satisfied for this problem? Explain why this would be an important consideration.

Short Answer

Expert verified
(a) The point estimate for p is 0.3102. (b) The 99% confidence interval is (0.2937, 0.3267). (c) Yes, both np and nq are greater than 5, satisfying normal approximation conditions.

Step by step solution

01

Determine the Point Estimate for p

To find the point estimate for the proportion \( p \), we use the formula for the sample proportion \( \hat{p} \), defined as \( \hat{p} = \frac{x}{n} \), where \( x \) is the number of traditional hogans and \( n \) is the total number of dwellings sampled. Here, \( x = 1619 \) and \( n = 5222 \). So, \( \hat{p} = \frac{1619}{5222} \approx 0.3102 \).
02

Calculate the Standard Error

The standard error (SE) of the sample proportion is calculated using the formula \( SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \). Substituting the values, we get \( SE = \sqrt{\frac{0.3102 \times 0.6898}{5222}} \approx 0.0064 \).
03

Find the Z-score for a 99% Confidence Interval

For a 99% confidence interval, the Z-score is approximately 2.576. This value corresponds to the critical value associated with the 99% confidence level in a standard normal distribution.
04

Calculate the Margin of Error

The margin of error (ME) is calculated as \( ME = Z \times SE \). Here, \( ME = 2.576 \times 0.0064 \approx 0.0165 \).
05

Determine the Confidence Interval

The confidence interval (CI) is given by \( \hat{p} \pm ME \). Therefore, the 99% confidence interval for \( p \) is \( 0.3102 \pm 0.0165 \), which simplifies to \( (0.2937, 0.3267) \).
06

Check Requirements for Normal Approximation

We verify if the assumptions of the normal approximation are met by checking \( np > 5 \) and \( nq > 5 \). We have \( np = 5222 \times 0.3102 = 1619 \) and \( nq = 5222 \times (1 - 0.3102) = 3603 \). Both values are much greater than 5, hence confirming the requirements are satisfied.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Point Estimate
A point estimate provides a single-valued estimate of an unknown population parameter. In simple terms, a point estimate uses sample data to give the best guess of the actual value of the population parameter. For the problem of determining the proportion of traditional Navajo hogans, we use the sample proportion, denoted by \( \hat{p} \).
To calculate \( \hat{p} \), we divide the number of hogans in the sample by the total number of dwellings sampled. In our case, the point estimate is given by the formula \( \hat{p} = \frac{1619}{5222} \approx 0.3102 \).
This means approximately 31.02% of the sampled dwellings are traditional hogans.
Insight into Confidence Intervals
A confidence interval offers a range of values within which the true population parameter is expected to fall. Unlike a point estimate, which gives a single value, a confidence interval provides a span, enhancing our understanding by indicating uncertainty.
The 99% confidence interval is calculated using the sample proportion, the Z-score for the desired confidence level, and the standard error. Here, the 99% confidence interval is \( 0.3102 \pm 0.0165 \)
which results in the interval \( (0.2937, 0.3267) \).
This means we can be 99% confident that between 29.37% and 32.67% of all dwellings are traditional hogans.
Exploring Normal Approximation
Normal approximation allows us to use the normal distribution to approximate the distribution of sample proportions, which simplifies calculations.
This approximation is valid under certain conditions, known as the rule of thumb:
  • The sample size should be large enough such that both \( np > 5 \) and \( nq > 5 \).
  • For our example, with \( np = 1619 \) and \( nq = 3603 \), both conditions are satisfied.
This confirms the use of normal approximation is appropriate, ensuring the reliability of our confidence interval calculations.
Comprehending Sample Proportion
Sample proportion refers to the fraction of the sample that exhibits a particular characteristic. It serves as the point estimate of the population proportion.
In this situation, the sample proportion is calculated as \( \hat{p} = \frac{1619}{5222} \approx 0.3102 \).
This estimation helps to predict the proportion of traditional hogans across the entire Navajo reservation.
The use of sample proportion is crucial because it leverages smaller subset data to make inferences about a larger population.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Archaeology: Cultural Affiliation "Unknown cultural affiliations and loss of identity at high elevations." These words are used to propose the hypothesis that archaeological sites tend to lose their identity as altitude extremes are reached. This idea is based on the notion that prehistoric people tended \(n o t\) to take trade wares to temporary settings and/or isolated areas (Source: Prehistoric New Mexico: Background for Survey, by D. E. Stuart and R. P. Gauthier, University of New Mexico Press). As elevation zones of prehistoric people (in what is now the state of New Mexico) increased, there seemed to be a loss of artifact identification. Consider the following information. $$ \begin{array}{lcc} \hline \text { Elevation Zone } & \text { Number of Artifacts } & \text { Number Unidentified } \\ \hline 7000-7500 \mathrm{ft} & 112 & 69 \\ 5000-5500 \mathrm{ft} & 140 & 26 \\ \hline \end{array} $$ Let \(p_{1}\) be the population proportion of unidentified archaeological artifacts at the elevation zone \(7000-7500\) feet in the given archaeological area. Let \(p_{2}\) be the population proportion of unidentified archaeological artifacts at the elevation zone \(5000-5500\) feet in the given archaeological area. (a) Check Requirements Can a normal distribution be used to approximate the \(\hat{p}_{1}-\hat{p}_{2}\) distribution? Explain. (b) Find a \(99 \%\) confidence interval for \(p_{1}-p_{2}\). (c) Interpretation Explain the meaning of the confidence interval in the context of this problem. Does the confidence interval contain all positive numbers? all negative numbers? both positive and negative numbers? What does this tell you (at the \(99 \%\) confidence level) about the comparison of the population proportion of unidentified artifacts at high elevations \((7000-7500\) feet \()\) with the population proportion of unidentified artifacts at lower elevations (5000-5500 feet)? How does this relate to the stated hypothesis?

Answer true or false. Explain your answer. Every random sample of the same size from a given population will produce exactly the same confidence interval for \(\mu\).

Physicians: Solo Practice A random sample of 328 medical doctors showed that 171 have a solo practice (Source: Practice Patterns of General Internal Medicine, American Medical Association). (a) Let \(p\) represent the proportion of all medical doctors who have a solo practice. Find a point estimate for \(p\). (b) Find a \(95 \%\) confidence interval for \(p\). Give a brief explanation of the meaning of the interval. (c) Interpretation As a news writer, how would you report the survey results regarding the percentage of medical doctors in solo practice? What is the margin of error based on a \(95 \%\) confidence interval?

Assume that the population of \(x\) values has an approximately normal distribution. Wildlife: Mountain Lions How much do wild mountain lions weigh? The 77 th Annual Report of the New Mexico Department of Game and Fish, edited by Bill Montoya, gave the following information. Adult wild mountain lions 18 months or older) captured and released for the first time in the San Andres Mountains gave the following weights (pounds): \(\begin{array}{llllll}68 & 104 & 128 & 122 & 60 & 64\end{array}\) (a) Use a calculator with mean and sample standard deviation keys to verify that \(\bar{x}=91.0\) pounds and \(s \approx 30.7\) pounds. (b) Find a \(75 \%\) confidence interval for the population average weight \(\mu\) of all adult mountain lions in the specified region. (c) Interpretation What does the confidence interval mean in the context of this problem?

Confidence Intervals: Sample Size A random sample is drawn from a population with \(\sigma=12\). The sample mean is 30 . (a) Compute a \(95 \%\) confidence interval for \(\mu\) based on a sample of size 49 . What is the value of the margin of error? (b) Compute a \(95 \%\) confidence interval for \(\mu\) based on a sample of size 100 . What is the value of the margin of error? (c) Compute a \(95 \%\) confidence interval for \(\mu\) based on a sample of size 225 . What is the value of the margin of error? (d) Compare the margins of error for parts (a) through (c). As the sample size increases, does the margin of error decrease? (e) Critical Thinking Compare the lengths of the confidence intervals for parts (a) through (c). As the sample size increases, does the length of a \(90 \%\) confidence interval decrease?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.