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Answer true or false. Explain your answer. A larger sample size produces a longer confidence interval for \(\mu\).

Short Answer

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False, a larger sample size produces a shorter confidence interval.

Step by step solution

01

Understanding Confidence Intervals

A confidence interval (CI) for the mean (\mu) is a range of values used to estimate the true population mean, calculated as sample mean (\(\bar{x}\)) plus or minus a margin of error. The formula is \(\text{CI} = \bar{x} \pm z\frac{\sigma}{\sqrt{n}}\), where \(\sigma\) is the standard deviation, \(n\) is the sample size, and \(z\) is the z-score corresponding to the desired confidence level.
02

Effect of Sample Size on Confidence Interval

Review the formula \(\text{CI} = \bar{x} \pm z\frac{\sigma}{\sqrt{n}}\). Notice that as the sample size \(n\) increases, the term \(\frac{\sigma}{\sqrt{n}}\) decreases because \(\sqrt{n}\) grows, reducing the margin of error and thereby narrowing the confidence interval.
03

Conclusion

From the formula and explanation, as the sample size increases, the margin of error decreases, resulting in a smaller or narrower confidence interval. Hence, a larger sample size actually produces a shorter confidence interval, not a longer one.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size Effect
When we talk about the effect of sample size, it can be helpful to think of it as getting a clearer picture of the data. The larger our sample size, the more reliable our estimate of the population becomes. This is because larger samples provide more information and help average out any unusual fluctuations or random variations that might happen with smaller samples.

In the context of confidence intervals, a larger sample size affects the margin of error, which is the range of uncertainty in our estimate. As the sample size (\( n \)) increases, the standard deviation of the sample mean (\( \frac{\sigma}{\sqrt{n}} \)) decreases. Since the margin of error depends on this value, it also decreases.

So, what's the big takeaway? As sample size goes up:
  • The margin of error decreases.
  • The confidence interval narrows, giving us a more precise estimate of the population mean.
Margin of Error
The margin of error is a crucial component in statistics that defines the range above and below the sample mean (\( \bar{x} \)) in which we expect the true population mean (\( \mu \)) to lie. This is how we express uncertainty or certainty in our confidence interval.

Mathematically, the margin of error is calculated as:\[ ME = z\frac{\sigma}{\sqrt{n}} \]Here,
  • \( z \) is the z-score, which corresponds to the desired confidence level, like 95% or 99%.
  • \( \sigma \) represents the standard deviation of the population.
  • \( \sqrt{n} \) is the square root of the sample size (\( n \)).
The margin of error ensures that we're accounting for variability and providing a range that is statistically likely to contain the true population mean. Dropping or increasing the sample size can greatly impact the margin. A decent sample size leads to a smaller margin of error, improving our confidence in the range specified by the interval.

Thus, the margin of error is not just a number; it reflects how confident we are about our estimates. It is largely influenced by both the sample size and the level of confidence we strive to achieve.
Population Mean Estimation
Estimating the population mean (\( \mu \)) is one of the main goals in statistics. We usually cannot take measurements from every member of a population, so instead, we take a sample and use it to estimate the mean.

To understand population mean estimation, we first calculate the sample mean (\( \bar{x} \)). This sample mean serves as our best point estimate of the population mean. However, because it's only a sample, we need to acknowledge that there is uncertainty involved.

This is where confidence intervals come in. They provide a range of plausible values for the population mean. A 95% confidence interval, for example, means that if we were to take 100 different samples and compute a confidence interval for each, we would expect about 95 of them to contain the true population mean.

The width of the confidence interval depends on the sample size and variability within the data. Larger sample sizes and lower variability in data will lead to a narrower and more precise interval. By understanding these factors, statisticians and researchers can make more informed decisions regarding the reliability and precision of their estimates.

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Most popular questions from this chapter

22\. | Opinion Poll: Crime and Violence A New York Times/CBS poll asked the question, "What do you think is the most important problem facing this country today?" Nineteen percent of the respondents answered, "Crime and violence." The margin of sampling error was plus or minus 3 percentage points. Following the convention that the margin of error is based on a \(95 \%\) confidence interval, find a \(95 \%\) confidence interval for the percentage of the population that would respond, "Crime and violence" to the question asked by the pollsters.

Answer true or false. Explain your answer. For the same random sample, when the confidence level \(c\) is reduced, the confidence interval for \(\mu\) becomes shorter.

Psychology: Parental Sensitivity "Parental Sensitivity to Infant Cues: Similarities and Differences Between Mothers and Fathers" by M. V. Graham (Journal of Pediatric Nursing, Vol. 8, No. 6 ) reports a study of parental empathy for sensitivity cues and baby temperament (higher scores mean more empathy). Let \(x_{1}\) be a random variable that represents the score of a mother on an empathy test (as regards her baby). Let \(x_{2}\) be the empathy score of a father. A random sample of 32 mothers gave a sample mean of \(\bar{x}_{1}=69.44\). Another random sample of 32 fathers gave \(\bar{x}_{2}=59 .\) Assume that \(\sigma_{1}=11.69\) and \(\sigma_{2}=11.60\). (a) Check Requirements Which distribution, normal or Student's \(t\), do we use to approximate the \(\bar{x}_{1}-\bar{x}_{2}\) distribution? Explain. (b) Let \(\mu_{1}\) be the population mean of \(x_{1}\) and let \(\mu_{2}\) be the population mean of \(x_{2}\). Find a \(99 \%\) confidence interval for \(\mu_{1}-\mu_{2}\). (c) Interpretation Examine the confidence interval and explain what it means in the context of this problem. Does the confidence interval contain all positive, all negative, or both positive and negative numbers? What does this tell you about the relationship between average empathy scores for mothers compared with those for fathers at the \(99 \%\) confidence level?

Answer true or false. Explain your answer. The point estimate for the population mean \(\mu\) of an \(x\) distribution is \(\bar{x}\), computed from a random sample of the \(x\) distribution.

Marketing: Bargain Hunters In a marketing survey, a random sample of 1001 supermarket shoppers revealed that 273 always stock up on an item when they find that item at a real bargain price. See reference in Problem \(19 .\) (a) Let \(p\) represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for \(p\). (b) Find a \(95 \%\) confidence interval for \(p\). Give a brief explanation of the meaning of the interval. (c) Interpretation As a news writer, how would you report the survey results on the percentage of supermarket shoppers who stock up on real-bargain items? What is the margin of error based on a \(95 \%\) confidence interval?

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