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What percentage of the area under the normal curve lies (a) to the left of \(\mu\) ? (b) between \(\mu-\sigma\) and \(\mu+\sigma\) ? (c) between \(\mu-3 \sigma\) and \(\mu+3 \sigma\) ?

Short Answer

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(a) 50%, (b) 68%, (c) 99.7%

Step by step solution

01

Understanding the Problem

First, we need to understand that a normal distribution is symmetric about the mean (denoted as \(\mu\)), and \(\sigma\) represents the standard deviation. The problem is asking for percentages within this distribution. The total area under the normal distribution curve is always 100%.
02

Finding Area to the Left of the Mean

Since the normal distribution is symmetric about the mean, the area to the left of \(\mu\) is exactly half of the total area under the curve. Therefore, 50% of the area under the normal curve lies to the left of the mean.
03

Finding Area Within One Standard Deviation

To find the area between \(\mu-\sigma\) and \(\mu+\sigma\), we use the empirical rule, which states that approximately 68% of the data in a normal distribution lies within one standard deviation from the mean.
04

Finding Area Within Three Standard Deviations

The empirical rule also tells us that approximately 99.7% of the data in a normal distribution lies within three standard deviations from the mean, which means from \(\mu-3\sigma\) to \(\mu+3\sigma\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

standard deviation
Standard deviation is a measure of how spread out the values in a data set are. In a normal distribution, it's denoted by the Greek letter \( \sigma \). The smaller the standard deviation, the more closely the data points cluster around the mean. Conversely, a larger standard deviation indicates more spread out data.

In statistics, standard deviation tells us about the variability or dispersion within the data set. You can think of it as an average distance of each data point from the mean. It's a crucial component when analyzing data since it helps us understand the context of the distribution and make predictions and inferences about the entire data set.

For example, if you have data on students' test scores, with a mean score of 75 and a small standard deviation, this suggests that most students scored close to 75.
  • Calculation: To calculate the standard deviation, you find the square root of the variance. The variance is the average of the squared deviations from the mean.
  • Symbol: \( \sigma \).
  • Effect: High \( \sigma \) implies high variability, low \( \sigma \) implies low variability.
mean (mu)
The mean, often referred to by the symbol \( \mu \), is the average of all the data points in a set. It represents the center of a normal distribution and acts as the point of symmetry. For a data set with \( n \) values, the mean is calculated by summing all data points and dividing by \( n \).

Understanding the mean is crucial since it tells you the general tendency of the data. If you know the mean, you can better interpret individual data points' positions within the distribution.

In the context of a normal distribution, the mean is especially important because the distribution is perfectly symmetric around it. This means that half of the data points fall to the left of the mean, and half fall to the right.
  • Calculation: \( \mu = \frac{\sum x}{n} \) where \( x \) represents each data point.
  • Symbol: \( \mu \).
  • Role: Acts as the center point and symmetry marker of a normal distribution.
empirical rule
The empirical rule, sometimes known as the 68-95-99.7 rule, provides a quick way to estimate probabilities and percentages for a normal distribution. This rule states that:
  • Approximately 68% of data lies within one standard deviation (\( \mu \pm \sigma \)).
  • About 95% falls within two standard deviations (\( \mu \pm 2\sigma \)).
  • Roughly 99.7% of the data is within three standard deviations (\( \mu \pm 3\sigma \)).
This rule is particularly useful for quickly assessing the spread of data without needing complex calculations.

Let's say you have a normally distributed data set of a class test with a mean score of 70 and a standard deviation of 5. Using the empirical rule, you know that most students (68%) scored between 65 and 75. Almost all (99.7%) scored between 55 and 85.

This rule assists in identifying outliers and making inferences about the population from a sample. When you apply the empirical rule, it becomes easier to anticipate data behaviors in practice.

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Most popular questions from this chapter

What are the chances that a person who is murdered actually knew the murderer? The answer to this question explains why a lot of police detective work begins with relatives and friends of the victim! About \(64 \%\) of people who are murdered actually knew the person who committed the murder (Chances: Risk and Odds in Everyday Life, by James Burke). Suppose that a detective file in New Orleans has 63 current unsolved murders. What is the probability that (a) at least 35 of the victims knew their murderers? (b) at most 48 of the victims knew their murderers? (c) fewer than 30 victims did \(n o t\) know their murderers? (d) more than 20 victims did \(n o t\) know their murderers?

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Give an example of a specific sampling distribution we studied in this section. Outline other possible examples of sampling distributions from areas such as business administration, economics, finance, psychology, political science, sociology, biology, medical science, sports, engineering, chemistry, linguistics, and so on.

Binomial probability distributions depend on the number of trials \(n\) of a binomial experiment and the probability of success \(p\) on each trial. Under what conditions is it appropriate to use a normal approximation to the binomial?

Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage. Let \(x\) be a random variable that represents the number of milligrams of porphyrin per deciliter of blood. In healthy adults, \(x\) is approximately normally distributed with mean \(\mu=38\) and standard deviation \(\sigma=12\) (see reference in Problem 25). What is the probability that (a) \(x\) is less than 60 ? (b) \(x\) is greater than \(16 ?\) (c) \(x\) is between 16 and 60 ? (d) \(x\) is more than 60 ? (This may indicate an infection, anemia, or another type of illness.)

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