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Let \(z\) be a random variable with a standard normal distribution. Find the indicated probability, and shade the corresponding area under the standard normal curve. $$ P(-0.45 \leq z \leq 2.73) $$

Short Answer

Expert verified
The probability \( P(-0.45 \leq z \leq 2.73) \) is approximately 0.6704.

Step by step solution

01

Understanding the Problem

We need to find the probability that the standard normal random variable \( z \) falls between -0.45 and 2.73, i.e., \( P(-0.45 \leq z \leq 2.73) \). This corresponds to finding the area under the standard normal curve between these two z-scores.
02

Using the Standard Normal Distribution Table

We will use the standard normal distribution table (also known as the Z-table) to find the cumulative probabilities associated with the z-scores -0.45 and 2.73.
03

Find the Cumulative Probability for z = -0.45

Look up the value for \( z = -0.45 \) in the Z-table. This will give us the probability \( P(z \leq -0.45) \). According to the table, \( P(z \leq -0.45) \approx 0.3264 \).
04

Find the Cumulative Probability for z = 2.73

Look up the value for \( z = 2.73 \) in the Z-table. This will give us the probability \( P(z \leq 2.73) \). According to the table, \( P(z \leq 2.73) \approx 0.9968 \).
05

Calculate the Desired Probability

The probability that \( z \) is between -0.45 and 2.73 is the difference between the cumulative probabilities: \( P(-0.45 \leq z \leq 2.73) = P(z \leq 2.73) - P(z \leq -0.45) = 0.9968 - 0.3264 \).
06

Compute the Result

Subtract the cumulative probability at \( z = -0.45 \) from the cumulative probability at \( z = 2.73 \): \[ P(-0.45 \leq z \leq 2.73) = 0.9968 - 0.3264 = 0.6704 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
The concept of probability calculation is crucial in statistics, especially when working with the standard normal distribution. Probability, in this context, refers to the likelihood of a specific event happening. In our problem, we are interested in the event where a standard normal random variable, denoted as \( z \), falls within a specific range, which is from \(-0.45\) to \(2.73\).
An effective way to calculate this probability is to measure the area under the standard normal curve between these two z-scores. This area represents the probability. To find this area, or probability, we rely on the cumulative probabilities provided in the standard normal distribution table, commonly known as the Z-table. Using the Z-table, we can determine the cumulative probability for each z-score and then subtract them to find the probability that \( z \) falls between our desired range.
Through this process, the probability becomes a tangible measurement, showcasing how likely an event is to occur within a specified interval of a standard normal distribution.
Z-Score
The Z-Score is a fundamental concept in statistical analysis, particularly when dealing with the normal distribution. It quantifies how many standard deviations an element is from the mean. In a standard normal distribution, the mean is zero, and the standard deviation is one. The Z-Score is used to calculate probabilities in a normal distribution, making it a useful tool for data analysis.
In our specific problem, the z-scores \(-0.45\) and \(2.73\) represent points on the standard normal distribution curve. The z-score of \(-0.45\) indicates that this point is 0.45 standard deviations below the mean, while a z-score of \(2.73\) tells us this point is 2.73 standard deviations above the mean.
By using these z-scores, you can identify areas under the curve, which correspond to probabilities. Understanding how to determine and interpret z-scores is essential for accurately finding probabilities in statistics, especially when it involves dealing with data that adheres closely to a normal distribution.
Cumulative Probability
Cumulative probability refers to the total probability that a random variable is less than or equal to a particular value. In the context of the standard normal distribution, this is found using a Z-table, which lists cumulative probabilities associated with different z-scores.
To find the cumulative probability in our problem, we look up the z-scores in the Z-table:
  • For \( z = -0.45 \), the cumulative probability \( P(z \leq -0.45) \) is approximately 0.3264.
  • For \( z = 2.73 \), the cumulative probability \( P(z \leq 2.73) \) is approximately 0.9968.
This means that there is a 32.64% chance that a standard normal z-value is less than or equal to \(-0.45\), and a 99.68% chance for \(2.73\).
By using the concept of cumulative probability, we can better understand the distribution of data and the likelihood of various outcomes, which is immensely useful in statistical decision-making and predictions.
Normal Curve Area
The area under the normal curve is integral to understanding probability calculations in the standard normal distribution. Every part of the curve represents different probabilities. Typically, the entire area under the curve equals 1, which stands for 100% probability. Each segment of the curve represents a probability that a random variable will fall within that range.
In our problem, calculating \( P(-0.45 \leq z \leq 2.73) \) is essentially finding the area under the normal curve between the z-scores \(-0.45\) and \(2.73\). This means identifying the space covered by all the possible z-values that lie within these two points.
The area between these points is determined by the difference in their cumulative probabilities from the Z-table. This subtraction yields the probability associated with that range. In this case,
  • The area, and thus the probability, between \(-0.45 \) and \( 2.73 \) is \( 0.6704 \).
Grasping the concept of normal curve area allows one to visually compete probability, providing a powerful tool for statistical analysis and prediction.

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Most popular questions from this chapter

Find the \(z\) value described and sketch the area described. Find \(z\) such that \(97.5 \%\) of the standard normal curve lies to the left of \(z\)

Let \(z\) be a random variable with a standard normal distribution. Find the indicated probability, and shade the corresponding area under the standard normal curve. $$ P(z \leq-2.15) $$

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