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Find the \(z\) value described and sketch the area described. Find \(z\) such that \(55 \%\) of the standard normal curve lies to the left of \(z\).

Short Answer

Expert verified
The z-value is approximately 0.125.

Step by step solution

01

Understanding the Standard Normal Distribution

The standard normal distribution, also known as the Z-distribution, is a special normal distribution with a mean of 0 and a standard deviation of 1. The z-value corresponds to the number of standard deviations away from the mean.
02

Identify the Problem Context

We need to find the z-value for which 55% of the distribution lies to the left of this value. This implies we are looking for the z-value associated with the 55th percentile of the standard normal distribution.
03

Locate the Z-Value Using Z-Table or Calculator

Use a Z-table or statistical calculator to find the z-value that corresponds to an area of 0.55 to the left. Search for the closest entry under the cumulative probability column to 0.55. Typically, this is done using statistical calculators or z-tables commonly available in textbooks.
04

Z-Value Observation

The closest cumulative probability value to 0.55 in the z-table is typically 0.5495, which corresponds approximately to a z-value of 0.125.
05

Sketching the Area

Draw a standard normal distribution curve (bell-shaped curve). Mark the mean at 0 on the x-axis. Indicate the point where z approximately equals 0.125 on the x-axis. Shade the area to the left of this z-value, which represents 55% of the total area under the curve.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-value
In statistics, a Z-value is a key concept used in the context of the standard normal distribution. It indicates how far and in what direction, a point is from the mean, expressed in terms of standard deviations. In a standard normal distribution, where the mean is 0 and the standard deviation is 1, a Z-value tells us exactly how many standard deviations away from the mean a specific point lies. To calculate a Z-value, we use the formula:
  • \[ z = \frac{(X - \mu)}{\sigma} \]
where:
  • \( X \) is the value in question,
  • \( \mu \) is the mean (0 for standard normal distribution), and
  • \( \sigma \) is the standard deviation (1 for standard normal distribution).
The resulting Z-value can be positive or negative, indicating whether the value is above or below the mean, respectively.
Cumulative Probability
Cumulative probability refers to the probability that a random variable takes on a value less than or equal to a certain value. In the context of the standard normal distribution, it represents the total area under the curve to the left of a specific Z-value. The cumulative probability is crucial when seeking a specific value's relative position in the broader context of the entire distribution. Using a Z-table, we can find the cumulative probability that corresponds to a given Z-value. For example, if we're trying to find the Z-value at which 55% of the data falls to the left, we search the Z-table for a cumulative probability close to 0.55. This cumulative area indicates that the probability of a value being less than that Z-value is 55%. The remaining 45% falls to the right. Statistical calculators often simplify this process by directly providing the Z-values associated with given cumulative probabilities, removing the need to search manually.
Percentile
A percentile is a statistic that provides insight into the distribution of data and represents the value below which a given percentage of observations fall. If a value is at the 55th percentile of a dataset, it means that 55% of the observations fall below this value. In the standard normal distribution, finding the 55th percentile involves identifying the corresponding Z-value. This is typically achieved through a Z-table or statistical software. Once determined, the percentile indicates that the value is greater than 55% of the observations and less than the remaining 45%. Understanding percentiles helps contextualize a specific value's ranking within a dataset, providing a clearer understanding of its relative standing.

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Most popular questions from this chapter

Let \(x\) be a random variable that represents the level of glucose in the blood (milligrams per deciliter of blood) after a 12 -hour fast. Assume that for people under 50 years old, \(x\) has a distribution that is approximately normal, with mean \(\mu=85\) and estimated standard deviation \(\sigma=25\) (based on information from Diagnostic Tests with Nursing Applications, edited by S. Loeb, Springhouse). A test result \(x<40\) is an indication of severe excess insulin, and medication is usually prescribed. (a) What is the probability that, on a single test, \(x<40\) ? (b) Suppose a doctor uses the average \(\bar{x}\) for two tests taken about a week apart. What can we say about the probability distribution of \(\bar{x}\) ? Hint: See Theorem 6.1. What is the probability that \(\bar{x}<40\) ? (c) Repeat part (b) for \(n=3\) tests taken a week apart. (d) Repeat part (b) for \(n=5\) tests taken a week apart. (e) Compare your answers to parts (a), (b), (c), and (d). Did the probabilities decrease as \(n\) increased? Explain what this might imply if you were a doctor or a nurse. If a patient had a test result of \(\bar{x}<40\) based on five tests, explain why either you are looking at an extremely rare event or (more likely) the person has a case of excess insulin.

Suppose we have a binomial experiment with \(n=40\) trials and a probability of success \(p=0.50\) . (a) Is it appropriate to use a normal approximation to this binomial distribution? Why? (b) Compute \(\mu\) and \(\sigma\) of the approximating normal distribution. (c) Use a continuity correction factor to convert the statement \(r \geq 23\) successes to a statement about the corresponding normal variable \(x\). (d) Estimate \(P(r \geq 23)\). (e) Is it unusual for a binomial experiment with 40 trials and probability of success \(0.50\) to have 23 or more successes? Explain.

The heights of 18 -year-old men are approximately normally distributed, with mean 68 inches and standard deviation 3 inches (based on information from Statistical Abstract of the United States, 112 th Edition). (a) What is the probability that an 18 -year-old man selected at random is between 67 and 69 inches tall? (b) If a random sample of nine 18 -year-old men is selected, what is the probability that the mean height \(\bar{x}\) is between 67 and 69 inches? (c) Compare your answers to parts (a) and (b). Is the probability in part (b) much higher? Why would you expect this?

Based on long experience, an airline has found that about \(6 \%\) of the people making reservations on a flight from Miami to Denver do not show up for the flight. Suppose the airline overbooks this flight by selling 267 ticket reservations for an airplane with only 255 seats. (a) What is the probability that a person holding a reservation will show up for the flight? (b) Let \(n=267\) represent the number of ticket reservations. Let \(r\) represent the number of people with reservations who show up for the flight. Which expression represents the probability that a seat will be available for everyone who shows up holding a reservation? $$ P(255 \leq r) ; \quad P(r \leq 255) ; \quad P(r \leq 267) ; \quad P(r=255) $$ (c) Use the normal approximation to the binomial distribution and part (b) to answer the following question: What is the probability that a seat will be available for every person who shows up holding a reservation?

(a) If we have a distribution of \(x\) values that is more or less mound-shaped and somewhat symmetrical, what is the sample size needed to claim that the distribution of sample means \(\bar{x}\) from random samples of that size is approximately normal? (b) If the original distribution of \(x\) values is known to be normal, do we need to make any restriction about sample size in order to claim that the distribution of sample means \(\bar{x}\) taken from random samples of a given size is normal?

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