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Agriculture: Apples Approximately \(3.6 \%\) of all (untreated) Jonathan apples had bitter pit in a study conducted by the botanists Ratkowsky and Martin (Source: Australian Journal of Agricultural Research, Vol. 25, pp. \(783-790)\). (Bitter pit is a disease of apples resulting in a soggy core, which can be caused either by overwatering the apple tree or by a calcium deficiency in the soil.) Let \(n\) be a random variable that represents the first Jonathan apple chosen at random that has bitter pit. (a) Write out a formula for the probability distribution of the random variable \(n\). (b) Find the probabilities that \(n=3, n=5\), and \(n=12\). (c) Find the probability that \(n \geq 5\). (d) What is the expected number of apples that must be examined to find the first one with bitter pit? Hint: Use \(\mu\) for the geometric distribution and round.

Short Answer

Expert verified
(a) Geometric distribution formula: \(P(n) = (1-p)^{n-1} \times p\). (b) Probabilities: \(P(n=3) = 0.03765\), \(P(n=5) = 0.03201\), \(P(n=12) = 0.02649\). (c) \(P(n \ge 5) = 0.86369\). (d) Expected number: 28 apples.

Step by step solution

01

Understanding the Geometric Distribution

The random variable \(n\) represents the first Jonathan apple with bitter pit. Since the probability of selecting a Jonathan apple with bitter pit is \(3.6\%\) or \(0.036\), we use the geometric distribution. The formula for the probability that the first success (bitter pit) occurs on the \(n\)-th trial is given by:\[P(n) = (1 - p)^{n-1} \times p\]Where \(p = 0.036\) is the probability of success (finding an apple with bitter pit) on each trial.
02

Calculate the Probability for Specific Cases

To find \(P(n=3), P(n=5),\) and \(P(n=12)\), substitute \(n\) in the geometric distribution formula.- For \(n = 3\): \[ P(n = 3) = (1 - 0.036)^{2} \times 0.036 = 0.03765 \]- For \(n = 5\): \[ P(n = 5) = (1 - 0.036)^{4} \times 0.036 = 0.03201 \]- For \(n = 12\): \[ P(n = 12) = (1 - 0.036)^{11} \times 0.036 = 0.02649 \]
03

Calculate the Probability for n ≥ 5

The probability \(P(n \ge 5)\) is the sum of probabilities from \(n = 5\) to infinity. However, it’s easier to calculate it as:\[P(n \ge 5) = 1 - P(n < 5)\]Compute \(P(n < 5)\) as the sum from \(n = 1\) to 4:\[\begin{align*}P(n < 5) &= P(n = 1) + P(n = 2) + P(n = 3) + P(n = 4) \&= 0.036 + 0.03466 + 0.03343 + 0.03222 \&= 0.13631\end{align*}\]Thus,\[P(n \ge 5) = 1 - 0.13631 = 0.86369\]
04

Calculate the Expected Number of Apples

The expected number of trials \(\mu\) to get the first success (apple with bitter pit) in a geometric distribution is:\[\mu = \frac{1}{p}\]Substitute \(p = 0.036\):\[\mu = \frac{1}{0.036} \approx 27.78\]Round to obtain \(\mu \approx 28\). Therefore, you are expected to examine about 28 apples.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution
In the realm of probability theory, a probability distribution is a mathematical description of the likelihood of various outcomes. When working with a geometric distribution, it specifically refers to the distribution of the number of trials until the first success occurs. In our apple study, we're focused on determining when the first apple with bitter pit appears.

The geometric distribution is utilized here because it models scenarios where the same probability of success (finding a bitter pit apple) occurs on each attempt. This makes it especially useful for representing indefinite number trial situations like our apple problem. According to the geometric distribution, the probability that the first success happens on the nth trial is given by the formula:
  • \[P(n) = (1 - p)^{n-1} \times p\]
Where:
  • \(n\) is the trial where the first success occurs,
  • \(p\) is the probability of success for each trial,
  • \((1-p)\) the probability of failure in a single trial (i.e., no bitter pit detected).
For our case, \(p = 0.036\). Each trial is independent, signifying that the probability remains consistent across all trials. This foundational understanding is crucial when performing further calculations.
Expected Value
Expected value is a fundamental concept in probability and statistics. It provides a measure of the "central tendency" or the average amount expected from a probability distribution. In the context of a geometric distribution, the expected value, denoted by \(\mu\), helps us determine the average number of trials needed to achieve our first success.

For a geometric distribution, the expected value is calculated using the formula:
  • \[\mu = \frac{1}{p}\]
Where \(p\) is the probability of success in each trial. In our apple study, this means finding the first apple that shows a bitter pit. Using the given \(p = 0.036\), the expected number of trials is:
  • \[\mu = \frac{1}{0.036} \approx 27.78\]
Rounding this number, we find that we would expect to check approximately 28 apples to find one affected by bitter pit. This helps farmers and botanists estimate efforts and resources needed for inspections.
Probability Calculation
Calculating specific probabilities within a geometric distribution context allows us to make well-informed predictions. Such calculations are useful to manage expectations about how often certain outcomes occur. For instance, when working with probabilities like \(P(n = 3)\), \(P(n = 5)\), and so forth, plug \(n\) into the geometric distribution formula given earlier.

Let's quickly explore these:
  • For \(n = 3\):\[P(n = 3) = (1 - 0.036)^{2} \times 0.036 = 0.03765\]This denotes there's a 3.765% probability that it takes 3 apples to find the first one with bitter pit.
  • For \(n = 5\):\[P(n = 5) = (1 - 0.036)^{4} \times 0.036 = 0.03201\]A 3.201% chance for it occurring at the fifth trial.
  • For \(n = 12\):\[P(n = 12) = (1 - 0.036)^{11} \times 0.036 = 0.02649\]A smaller 2.649% chance by the twelfth trial.
To determine the probability that the first bitter pit apple shows up after several trials, like \(P(n \geq 5)\), compute by subtracting the cumulative probability of it showing up in fewer than 5 trials from 1. Calculations revealed that:
  • \[P(n \geq 5) = 1 - 0.13631 = 0.86369\]
Thus, there's an 86.369% probability it takes more than four trials to find an affected apple, providing useful planning data.

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Most popular questions from this chapter

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Criminal Justice: Convictions Innocent until proven guilty? In Japanese criminal trials, about \(95 \%\) of the defendants are found guilty. In the United States, about \(60 \%\) of the defendants are found guilty in criminal trials (Source: The Book of Risks, by Larry Laudan, John Wiley and Sons). Suppose you are a news reporter following seven criminal trials. (a) If the trials were in Japan, what is the probability that all the defendants would be found guilty? What is this probability if the trials were in the United States? (b) Of the seven trials, what is the expected number of guilty verdicts in Japan? What is the expected number in the United States? What is the standard deviation in each case? (c) Quota Problem As a U.S. news reporter, how many trials \(n\) would you need to cover to be at least \(99 \%\) sure of two or more convictions? How many trials \(n\) would you need if you covered trials in Japan?

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