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Find the mean, median, and mode of the data set \(\begin{array}{llllll}8 & 2 & 7 & 2 & 6 & 5\end{array}\)

Short Answer

Expert verified
Mean is 5, median is 5.5, and mode is 2.

Step by step solution

01

Understanding Mean

The mean is the average of all numbers in a data set. To calculate the mean, add all the numbers together, and then divide by the number of values.
02

Calculating the Mean

Add all the values together: \(8 + 2 + 7 + 2 + 6 + 5 = 30\). The number of values is 6. So, the mean is \(\frac{30}{6} = 5\).
03

Understanding Median

The median is the middle number when a data set is ordered from least to greatest. If there are an even number of values, the median is the average of the two middle numbers.
04

Finding the Median

Order the data set: \(2, 2, 5, 6, 7, 8\). There are 6 numbers, so the median is the average of the 3rd and 4th numbers. The 3rd number is 5, and the 4th number is 6. Median = \(\frac{5 + 6}{2} = 5.5\).
05

Understanding Mode

The mode is the number that appears most frequently in the data set. A set can have more than one mode or no mode at all.
06

Finding the Mode

Look for the number that appears more than once: 2 appears twice. Hence, the mode is 2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Mean: The Average Value
The mean, often known as the average, is a fundamental concept in statistics that helps us understand the central tendency of a data set. To find the mean of a collection of numbers, you simply add up all the numbers and then divide by the total count.
For example, in the data set \[8, 2, 7, 2, 6, 5\], you first sum the numbers: \(8 + 2 + 7 + 2 + 6 + 5 = 30\). Then, you divide this total by the number of values in the set, which is 6. So, the mean is \( \frac{30}{6} = 5\).
Keep in mind that the mean gives us an idea of what a typical value in the data set might be, but it can be influenced by extremely high or low values. Hence, if a single number is unusually large or small, the mean might not accurately reflect the center of the data.
Uncovering the Median: The Middle Value
The median is the value that separates a data set into two equal halves when the numbers are ordered from smallest to largest. It provides us with a better understanding of the distribution of data when compared with the mean, especially in the presence of outliers.
To find the median of an even-numbered data set, like \[2, 2, 5, 6, 7, 8\], you first need to order the numbers.
The median is then the average of the two middle numbers. Here, the middle numbers are 5 and 6, so the median is calculated as \(\frac{5 + 6}{2} = 5.5\).
This measure is especially helpful in skewed distributions since it is not affected by very large or very small values.
Exploring the Mode: The Most Frequent Value
The mode is the number that appears most frequently in a data set. It is a useful statistical measure when you want to determine the most common item or trend in a set of data.
In our given data set \[8, 2, 7, 2, 6, 5\], you can easily spot the mode by looking for repeated numbers.
Here, the number 2 appears twice, while all other numbers appear only once. Therefore, the mode of this data set is 2.
It's important to note that a data set can have more than one mode if multiple numbers appear with the same highest frequency, and it can also have no mode at all if all numbers occur with the same frequency.

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Most popular questions from this chapter

One indicator of an outlier is that an observation is more than \(2.5\) standard deviations from the mean. Consider the data value \(80 .\) (a) If a data set has mean 70 and standard deviation 5, is 80 a suspect outlier? (b) If a data set has mean 70 and standard deviation 3 , is 80 a suspect outlier?

Consider two data sets. Set \(\mathrm{A}: n=5 ; \bar{x}=10 \quad\) Set B: \(n=50 ; \bar{x}=10\) (a) Suppose the number 20 is included as an additional data value in Set \(\mathrm{A}\). Compute \(\bar{x}\) for the new data set. Hint: \(\Sigma x=n \bar{x} .\) To compute \(\bar{x}\) for the new data set, add 20 to \(\Sigma x\) of the original data set and divide by 6 . (b) Suppose the number 20 is included as an additional data value in Set \(\mathrm{B}\). Compute \(\bar{x}\) for the new data set. (c) Why does the addition of the number 20 to each data set change the mean for Set A more than it does for Set B?

In some reports, the mean and coefficient of variation are given. For instance, in Statistical Abstract of the United States, \(116 \mathrm{th}\) Edition, one report gives the average number of physician visits by males per year. The average reported is \(2.2\), and the reported coefficient of variation is \(1.5 \%\). Use this information to determine the standard deviation of the annual number of visits to physicians made by males.

Find the mean, median, and mode of the data set \(\begin{array}{lllll}8 & 2 & 7 & 2 & 6\end{array}\)

Kevlar epoxy is a material used on the NASA space shuttles. Strands of this epoxy were tested at the \(90 \%\) breaking strength. The following data represent time to failure (in hours) for a random sample of 50 epoxy strands (Reference: R. E. Barlow, University of California, Berkeley). Let \(x\) be a random variable representing time to failure (in hours) at \(90 \%\) breaking strength. Note: These data are also available for download at the Online Study Center. \(\begin{array}{llllllllll}0.54 & 1.80 & 1.52 & 2.05 & 1.03 & 1.18 & 0.80 & 1.33 & 1.29 & 1.11 \\ 3.34 & 1.54 & 0.08 & 0.12 & 0.60 & 0.72 & 0.92 & 1.05 & 1.43 & 3.03 \\ 1.81 & 2.17 & 0.63 & 0.56 & 0.03 & 0.09 & 0.18 & 0.34 & 1.51 & 1.45 \\ 1.52 & 0.19 & 1.55 & 0.02 & 0.07 & 0.65 & 0.40 & 0.24 & 1.51 & 1.45 \\ 1.60 & 1.80 & 4.69 & 0.08 & 7.89 & 1.58 & 1.64 & 0.03 & 0.23 & 0.72\end{array}\) (a) Find the range. (b) Use a calculator to verify that \(\Sigma x=62.11\) and \(\Sigma x^{2} \approx 164.23\). (c) Use the results of part (b) to compute the sample mean, variance, and standard deviation for the time to failure. (d) Use the results of part (c) to compute the coefficient of variation. What does this number say about time to failure? Why does a small \(C V\) indicate more consistent data, whereas a larger \(\mathrm{CV}\) indicates less consistent data? Explain.

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