/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Find the mean, median, and mode ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the mean, median, and mode of the data set \(\begin{array}{lllll}8 & 2 & 7 & 2 & 6\end{array}\)

Short Answer

Expert verified
Mean is 5, median is 6, and mode is 2.

Step by step solution

01

Arrange the Data

First, arrange the given data in ascending order. The data set is \( \{8, 2, 7, 2, 6\} \), which rearranges to \( \{2, 2, 6, 7, 8\} \).
02

Calculate the Mean

Calculate the mean by adding all the numbers together and then dividing by the total number of values. \[\text{Mean} = \frac{2 + 2 + 6 + 7 + 8}{5} = \frac{25}{5} = 5\]
03

Identify the Median

Since the dataset is now \( \{2, 2, 6, 7, 8\} \), the median is the middle number in an odd-numbered set. Here, it is the third number: \(6\).
04

Find the Mode

The mode is the number that appears most frequently in the dataset. Here, the number \(2\) appears twice, while all others only appear once. Thus, the mode is \(2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
When talking about statistics, the mean is one of the most common measures used to find the average of a data set. To calculate the mean, start by summing all the numbers in your data set. In this case, our set is \( \{2, 2, 6, 7, 8\} \). This adds up to \(25\).

Next, count the number of items in your list. Here, there are five numbers. To find the mean, take the total sum, \(25\), and divide it by the count of numbers, \(5\): \[\text{Mean} = \frac{25}{5} = 5\]

Using this method, the mean, or average, tells us that if each number in the set were changed into the same value, each number would be \(5\). It provides a useful overview of what each data point would look like if the data were evenly distributed across the set.
Median Identification
The median is the middle value that separates the highest half from the lowest half of a data set. It's especially useful in determining the center of a data distribution, particularly when dealing with outliers that can skew the mean.

First, the data must be arranged in ascending order, just as we did with our set: \( \{2, 2, 6, 7, 8\} \). As there is an odd number of observations, pinpointing the median is straightforward—the third number, which is \(6\).

Here's a friendly tip: if your set has an even number of values, you would then take the average of the two middle numbers.

By finding the median, you gain insight into the central point of the dataset, providing clarity that might be obscured by extreme values if you only looked at the mean.
Mode Determination
The mode is the number that appears most frequently in a data set. It provides insight into the most common value or the popularity of a particular number in the dataset.

For the set \( \{2, 2, 6, 7, 8\} \), we notice that the number \(2\) appears twice, while all other numbers appear only once. Therefore, the mode is \(2\).

In cases where more than one number appears with the same highest frequency, your data set is bimodal or multimodal, reflecting multiple modes.
  • Example: A set like \( \{2, 2, 3, 3, 4\} \) would be bimodal with modes of \(2\) and \(3\).
Identifying the mode helps you understand which values in your data occur most frequently, providing an additional layer of analysis especially useful in fields like marketing for understanding consumer preferences.

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Most popular questions from this chapter

Consider the following ordered data: \(\begin{array}{llllllllll}2 & 5 & 5 & 6 & 7 & 8 & 8 & 9 & 10 & 12\end{array}\) (a) Find the low, \(Q_{1}\), median, \(Q_{3}\) high. (b) Find the interquartile range. (c) Make a box-and-whisker plot.

When data consist of rates of change, such as speeds, the harmonic mean is an appropriate measure of central tendency. For \(n\) data values, Harmonic mean \(=\frac{n}{\sum \frac{1}{x}}, \quad\) assuming no data value is 0 Suppose you drive 60 miles per hour for 100 miles, then 75 miles per hour for 100 miles. Use the harmonic mean to find your average speed.

Kevlar epoxy is a material used on the NASA space shuttles. Strands of this epoxy were tested at the \(90 \%\) breaking strength. The following data represent time to failure (in hours) for a random sample of 50 epoxy strands (Reference: R. E. Barlow, University of California, Berkeley). Let \(x\) be a random variable representing time to failure (in hours) at \(90 \%\) breaking strength. Note: These data are also available for download at the Online Study Center. \(\begin{array}{llllllllll}0.54 & 1.80 & 1.52 & 2.05 & 1.03 & 1.18 & 0.80 & 1.33 & 1.29 & 1.11 \\ 3.34 & 1.54 & 0.08 & 0.12 & 0.60 & 0.72 & 0.92 & 1.05 & 1.43 & 3.03 \\ 1.81 & 2.17 & 0.63 & 0.56 & 0.03 & 0.09 & 0.18 & 0.34 & 1.51 & 1.45 \\ 1.52 & 0.19 & 1.55 & 0.02 & 0.07 & 0.65 & 0.40 & 0.24 & 1.51 & 1.45 \\ 1.60 & 1.80 & 4.69 & 0.08 & 7.89 & 1.58 & 1.64 & 0.03 & 0.23 & 0.72\end{array}\) (a) Find the range. (b) Use a calculator to verify that \(\Sigma x=62.11\) and \(\Sigma x^{2} \approx 164.23\). (c) Use the results of part (b) to compute the sample mean, variance, and standard deviation for the time to failure. (d) Use the results of part (c) to compute the coefficient of variation. What does this number say about time to failure? Why does a small \(C V\) indicate more consistent data, whereas a larger \(\mathrm{CV}\) indicates less consistent data? Explain.

Consider the data set $$ \begin{array}{lllll} 2 & 3 & 4 & 5 & 6 \end{array} $$ (a) Find the range. (b) Use the defining formula to compute the sample standard deviation \(s\). (c) Use the defining formula to compute the population standard deviation \(\sigma\).

Clayton and Timothy took different sections of Introduction to Economics. Each section had a different final exam. Timothy scored 83 out of 100 and had a percentile rank in his class of 72 . Clayton scored 85 out of 100 but his percentile rank in his class was 70 . Who performed better with respect to the rest of the students in the class, Clayton or Timothy? Explain your answer.

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