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When data consist of rates of change, such as speeds, the harmonic mean is an appropriate measure of central tendency. For \(n\) data values, Harmonic mean \(=\frac{n}{\sum \frac{1}{x}}, \quad\) assuming no data value is 0 Suppose you drive 60 miles per hour for 100 miles, then 75 miles per hour for 100 miles. Use the harmonic mean to find your average speed.

Short Answer

Expert verified
The average speed is approximately 66.67 mph.

Step by step solution

01

Understand the Problem

We need to find the average speed using the harmonic mean for two segments of a journey, each with different speeds. The first segment has a speed of 60 mph, and the second segment has a speed of 75 mph. We are given the formula for the harmonic mean, which requires the number of data values and their reciprocal sum.
02

Identify the Number of Data Values

Determine how many speeds we are considering in this problem. Here, we have two different speeds: 60 mph and 75 mph. Thus, the number of data values, denoted as \(n\), is 2.
03

Calculate the Reciprocal of Each Speed

Compute the reciprocal of each given speed: \(\frac{1}{60}\) for the first speed and \(\frac{1}{75}\) for the second speed. This is essential as the harmonic mean requires the sum of these reciprocals.
04

Sum the Reciprocals

Add the reciprocals of the speeds calculated in Step 3: \(\frac{1}{60} + \frac{1}{75}\). We need a common denominator to add these fractions, which is 300. Thus, the sum is \(\frac{5}{300} + \frac{4}{300} = \frac{9}{300}\).
05

Apply the Harmonic Mean Formula

Using the harmonic mean formula, substitute \(n = 2\) and the sum of reciprocals \(\frac{9}{300}\): \[ \text{Harmonic Mean} = \frac{2}{\frac{9}{300}} = \frac{2 \times 300}{9} = \frac{600}{9} = 66.67\] mph.
06

Interpret the Result

The harmonic mean provides the average speed over the entire journey. We calculated an average speed of approximately 66.67 miles per hour, which takes into account both segments of the trip.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Speed Calculation
When dealing with journeys involving different segments traveled at different speeds, calculating the average speed is key to understanding the overall pace of the trip. The average speed is not just a simple average of the speeds but a specific calculation that considers the time spent at each speed. This concept is especially important if you want to know the central value of rates of change, like speeds, when traveling over the same distance.

To calculate the average speed using the harmonic mean, we first acknowledge that the harmonic mean is a type of average specifically suitable for rates, like speed or flow rates, when the distance covered remains consistent across segments. By using the harmonic mean, we get a more accurate representation of the average speed during the journey because it accounts for the different durations spent at each speed.
  • Harmonic mean emphasizes the lower speeds, where more time might be spent.
  • Better reflects the effect of each speed segment on the total journey.
Understanding this concept aids in real-life scenarios like road trips, determining efficient travel times, or analyzing speed data in tracks and races.
Reciprocal Sum
The reciprocal sum is an important part of the harmonic mean calculation process. It involves taking the reciprocal of each individual rate, in this context, each speed. The reciprocal of a number is simply 1 divided by that number. Thus, for a speed of 60 mph, the reciprocal is calculated as \(\frac{1}{60}\), and for 75 mph, it is \(\frac{1}{75}\).

The next step is to sum these reciprocals. This needs careful mathematical handling when dealing with fractions, as you must ensure a common denominator. For our speeds example:
  • Find the reciprocal for each speed.
  • Add the reciprocals together by converting them to a common denominator if necessary.
Calculating the reciprocal sum accurately is crucial because this sum forms the basis of calculating the harmonic mean. It directly influences the final average speed, giving a fair representation of different speeds over equal distances. Comprehending how to work with reciprocals can make many mathematical processes clearer, particularly those involving rates and ratios.
Rates of Change
Rates of change are integral to understanding and calculating averages in various contexts, especially in equations like average speed where we're comparing different segments.

In our example, each speed represents a rate of change—how quickly a distance is covered. Recognizing this helps in realizing why the harmonic mean is more suitable here rather than the arithmetic mean.
  • When speeds vary, each one is a rate of how much distance changes over time.
  • The harmonic mean accurately incorporates the effect of these differing rates on total travel time.
By setting attention on these rates, we can adjust the typical approach for averaging to get results that better match real-world experiences. Whether you're comparing water flow, velocities, or other scenarios involving changing rates over consistent measures, understanding how rates of change impact outcomes is vital. This ensures more precise and representative calculations in relevant applications, from travel planning to scientific data analysis.

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Most popular questions from this chapter

One standard for admission to Redfield College is that the student rank in the upper quartile of his or her graduating high school class. What is the minimal percentile rank of a successful applicant?

What symbol is used for the arithmetic mean when it is a sample statistic? What symbol is used when the arithmetic mean is a population parameter?

Some data sets include values so high or so low that they seem to stand apart from the rest of the data. These data are called outliers. Outliers may represent data collection errors, data entry errors, or simply valid but unusual data values. It is important to identify outliers in the data set and examine the outliers carefully to determine if they are in error. One way to detect outliers is to use a box-and-whisker plot. Data values that fall beyond the limits Lower limit: \(Q_{1}-1.5 \times(I Q R)\) Upper limit: \(Q_{3}+1.5 \times(I Q R)\) where \(I Q R\) is the interquartile range, are suspected outliers. In the computer software package Minitab, values beyond these limits are plotted with asterisks ( \(^{*}\) ). Students from a statistics class were asked to record their heights in inches. The heights (as recorded) were \(\begin{array}{llllllllllll}65 & 72 & 68 & 64 & 60 & 55 & 73 & 71 & 52 & 63 & 61 & 74 \\ 69 & 67 & 74 & 50 & 4 & 75 & 67 & 62 & 66 & 80 & 64 & 65\end{array}\) (a) Make a box-and-whisker plot of the data. (b) Find the value of the interquartile range \((I Q R)\). (c) Multiply the \(I Q R\) by \(1.5\) and find the lower and upper limits. (d) Are there any data values below the lower limit? above the upper limit? List any suspected outliers. What might be some explanations for the outliers?

Consider a data set of 15 distinct measurements with mean \(A\) and median \(B\). (a) If the highest number were increased, what would be the effect on the median and mean? Explain. (b) If the highest number were decreased to a value still larger than \(B\), what would be the effect on the median and mean? (c) If the highest number were decreased to a value smaller than \(B\), what would be the effect on the median and mean?

In some reports, the mean and coefficient of variation are given. For instance, in Statistical Abstract of the United States, \(116 \mathrm{th}\) Edition, one report gives the average number of physician visits by males per year. The average reported is \(2.2\), and the reported coefficient of variation is \(1.5 \%\). Use this information to determine the standard deviation of the annual number of visits to physicians made by males.

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