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Weatherwise is a magazine published by the American Meteorological Society. One issue gives a rating system used to classify Nor'easter storms that frequently hit New England and can cause much damage near the ocean. A severe storm has an average peak wave height of \(\mu=16.4\) feet for waves hitting the shore. Suppose that a Nor'easter is in progress at the severe storm class rating. Peak wave heights are usually measured from land (using binoculars) off fixed cement piers. Suppose that a reading of 36 waves showed an average wave height of \(\bar{x}=17.3\) feet. Previous studies of severe storms indicate that \(\sigma=3.5\) feet. Does this information suggest that the storm is (perhaps temporarily) increasing above the severe rating? Use \(\alpha=0.01\).

Short Answer

Expert verified
The data does not support that the storm wave height is significantly above the severe rating at α=0.01.

Step by step solution

01

Understanding the Hypotheses

We need to determine if the storm is increasing above the severe rating. We will form the null hypothesis, which states that the average peak wave height is equal to the severe storm rating mean, \(H_0: \, \mu = 16.4\) feet. The alternative hypothesis, reflecting an increase, is \(H_a: \, \mu > 16.4\) feet.
02

Collecting the Given Data

We have the following data: sample mean \(\bar{x} = 17.3\) feet, population standard deviation \(\sigma = 3.5\) feet, sample size \(n = 36\), and significance level \(\alpha = 0.01\).
03

Calculating the Test Statistic

The test statistic for a one-sample z-test is calculated using the formula: \[ z = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}}} \] Substituting the known values: \[ z = \frac{17.3 - 16.4}{\frac{3.5}{\sqrt{36}}} = \frac{0.9}{0.5833} \approx 1.54 \]
04

Determining the Critical Value for z

For a one-tailed test with \(\alpha = 0.01\), we check the z-table to find the critical z-value, which is approximately 2.33.
05

Making the Decision

Compare the calculated z-value (1.54) to the critical z-value (2.33). Since 1.54 is less than 2.33, we do not reject the null hypothesis.
06

Drawing a Conclusion

Since the z-value does not exceed the critical value, there is not enough statistical evidence at the 0.01 significance level to conclude that the storm is increasing above the severe rating.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a statistical method used to make decisions about data, especially when determining the likelihood of a particular hypothesis being true. At its core, hypothesis testing helps you figure out if what you are observing is just due to random chance or if there is actually something significant happening. In this exercise, the peak wave heights are being tested to see if they hit a severe storm level. To do this, we follow these steps:
  • Identify your hypotheses: Null hypothesis ( $H_0$ ) and alternative hypothesis ( $H_a$ )
  • Collect and analyze data: Here, the average wave height is measured
  • Use statistical calculations to form conclusions
The goal is to gather enough evidence to either support or reject $H_0$ .
Z-test
The z-test is a type of hypothesis test that determines if there is a significant difference between sample data and a known population mean. It's handy when we want to know if a sample comes from a population with a specific mean, and we know the population's standard deviation. For this problem, we perform a one-sample z-test since we are comparing one group of wave data to a known severe storm height mean. The formula used is: \[ z = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}}} \] Where:
  • \(\bar{x}\): Sample mean
  • \(\mu\): Population mean
  • \(\sigma\): Population standard deviation
  • \(n\): Sample size
The calculated z-score tells us how many standard deviations our sample mean is from the actual mean.
Significance Level
The significance level, often denoted as \(\alpha\), is the threshold used in hypothesis testing to decide whether a result is statistically significant. In simpler terms, \(\alpha\) is your risk of incorrectly rejecting the null hypothesis. For this exercise, \(\alpha\) is set at 0.01, suggesting we need very strong evidence to prove an increase in wave heights.
  • If the p-value is less than \(\alpha\), reject \(H_0\)
  • If the p-value is greater than \(\alpha\), do not reject \(H_0\)
Choosing an \(\alpha\) level is a bit like drawing a line in the sand, dictating how confident we want to be about our results.
Null Hypothesis
The null hypothesis (\(H_0\)) acts like the default assumption in hypothesis testing—it represents no effect or no difference.In this context, our \(H_0\) states that the average wave height is equal to the severe storm rating mean, or \(H_0: \mu = 16.4\) feet. Testing \(H_0\) allows us to explore the alternative hypothesis (\(H_a\)), which expects some change, like an increase in wave height. Essentially, accepting or rejecting \(H_0\) helps guide our conclusions:
  • If we fail to reject \(H_0\), the storm might not be any worse than predicted
  • If we reject \(H_0\), there’s statistical evidence suggesting the storm could be stronger
Understanding \(H_0\) provides clarity in verifying or challenging existing assumptions with data.

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Most popular questions from this chapter

For the same sample data and null hypothesis, how does the \(P\) -value for a two-tailed test of \(\mu\) compare to that for a one-tailed test?

USA Today reported that the state with the longest mean life span is Hawaii, where the population mean life span is 77 years. A random sample of 20 obituary notices in the Honolulu Advertizer gave the following information about life span (in years) of Honolulu residents: \(\begin{array}{llllllllll} 72 & 68 & 81 & 93 & 56 & 19 & 78 & 94 & 83 & 84 \\ 77 & 69 & 85 & 97 & 75 & 71 & 86 & 47 & 66 & 27 \end{array}\) i. Use a calculator with mean and standard deviation keys to verify that \(\bar{x}=\) \(71.4\) years and \(s\) \& \(20.65\) years. ii. Assuming that life span in Honolulu is approximately normally distributed, does this information indicate that the population mean life span for Honolulu residents is less than 77 years? Use a \(5 \%\) level of significance.

Is there a relationship between confidence intervals and two-tailed hypothesis tests? Let \(c\) be the level of confidence used to construct a confidence interval from sample data. Let \(\alpha\) be the level of significance for a two-tailed hypothesis test. The following statement applies to hypothesis tests of the mean. For a two-tailed hypothesis test with level of significance \(\alpha\) and null hypothesis \(H_{0}: \mu=k\), we reject \(H_{0}\) whenever \(k\) falls outside the \(c=1-\alpha\) confidence interval for \(\mu\) based on the sample data. When \(k\) falls within the \(c=1-\alpha\) confidence interval, we do not reject \(H_{0}\). (A corresponding relationship between confidence intervals and two-tailed hypothesis tests also is valid for other parameters, such as \(p, \mu_{1}-\mu_{2}\), or \(p_{1}-p_{2}\) which we will study in Sections \(9.3\) and \(9.5 .\) ) Whenever the value of \(k\) given in the null hypothesis falls outside the \(c=1-\alpha\) confidence interval for the parameter, we reject \(H_{0} .\) For example, consider a two-tailed hypothesis test with \(\alpha=0.01\) and \(H_{0}: \mu=20 \quad H_{1}: \mu \neq 20\) A random sample of size 36 has a sample mean \(\bar{x}=22\) from a population with standard deviation \(\sigma=4\). (a) What is the value of \(c=1-\alpha\) ? Using the methods of Chapter 8 , construct a \(1-\alpha\) confidence interval for \(\mu\) from the sample data. What is the value of \(\mu\) given in the null hypothesis (i.e., what is \(k)\) ? Is this value in the confidence interval? Do we reject or fail to reject \(H_{0}\) based on this information? (b) Using methods of Chapter 9 , find the \(P\) -value for the hypothesis test. Do we reject or fail to reject \(H_{0}\) ? Compare your result to that of part (a).

When testing the difference of means for paired data, what is the null hypothesis?

This problem is based on information taken from The Merck Manual (a reference manual used in most medical and nursing schools). Hypertension is defined as a blood pressure reading over \(140 \mathrm{~mm}\) Hg systolic and/or over \(90 \mathrm{~mm}\) Hg diastolic. Hypertension, if not corrected, can cause long- term health problems. In the college-age population \((18-24\) years), about \(9.2 \%\) have hypertension. Suppose that a blood donor program is taking place in a college dormitory this week (final exams week). Before each student gives blood, the nurse takes a blood pressure reading. Of 196 donors, it is found that 29 have hypertension. Do these data indicate that the population proportion of students with hypertension during final exams week is higher than \(9.2 \%\) ? Use a \(5 \%\) level of significance.

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