/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Would you favor spending more fe... [FREE SOLUTION] | 91Ó°ÊÓ

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Would you favor spending more federal tax money on the arts? This question was asked by a research group on behalf of The National Institute (Reference: Painting by Numbers, J. Wypijewski, University of California Press). Of a random sample of \(n_{1}=220\) women, \(r_{1}=\) 59 responded yes. Another random sample of \(n_{2}=175\) men showed that \(r_{2}=\) 56 responded yes. Does this information indicate a difference (either way) between the population proportion of women and the population proportion of men who favor spending more federal tax dollars on the arts? Use \(\alpha=0.05\).

Short Answer

Expert verified
No, there is no significant difference between the proportions of women and men who favor spending more on the arts.

Step by step solution

01

Understanding the Problem

We are given two sample groups: women and men, with different responses to a survey question about spending more federal tax money on the arts. We need to determine if there's a significant difference between the proportions of 'yes' responses from these two groups using a hypothesis test for the difference of proportions at a significance level of \( \alpha = 0.05 \).
02

Set Up Hypotheses

Define the null and alternative hypotheses: - Null hypothesis \( H_0 \): \( p_1 = p_2 \) (there is no difference between the proportions).- Alternative hypothesis \( H_a \): \( p_1 eq p_2 \) (there is a difference between the proportions).
03

Calculate Sample Proportions

Calculate the sample proportions of 'yes' responses for both groups: \( \hat{p}_1 = \frac{r_1}{n_1} = \frac{59}{220} \approx 0.2682 \) for women.\( \hat{p}_2 = \frac{r_2}{n_2} = \frac{56}{175} \approx 0.32 \) for men.
04

Calculate the Pooled Proportion

The pooled proportion \( \hat{p} \) is calculated because we assume under the null hypothesis that both samples come from the same population:\[ \hat{p} = \frac{r_1 + r_2}{n_1 + n_2} = \frac{59 + 56}{220 + 175} \approx 0.2924 \]
05

Find the Test Statistic

The formula for the test statistic \( z \) for the difference in proportions is:\[ z = \frac{\hat{p}_1 - \hat{p}_2}{\sqrt{\hat{p} (1 - \hat{p}) \left( \frac{1}{n_1} + \frac{1}{n_2} \right)}} \]Substitute the known values:\[ z = \frac{0.2682 - 0.32}{\sqrt{0.2924 \times 0.7076 \left( \frac{1}{220} + \frac{1}{175} \right)}} \approx -1.106 \]
06

Determine the Critical Value and Decision

For a two-tailed test at \( \alpha = 0.05 \), the critical z-values are approximately \( \pm 1.96 \). Since the calculated \( z \approx -1.106 \) is between \(-1.96\) and \(1.96\), we do not reject the null hypothesis.
07

Conclusion

There is not enough statistical evidence to indicate a significant difference in proportions of women and men who favor spending more federal tax money on the arts, at the \( \alpha = 0.05 \) significance level.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportions
Population proportions refer to the ratio or percentage of individuals in a population who exhibit a particular characteristic. When conducting hypothesis testing, especially with surveys or experiments involving groups, population proportions are essential. They help us understand the makeup of groups and compare differences between them. For instance, in the exercise, we consider two population groups: women and men. Each group has its own proportion of 'yes' responses regarding support for arts funding.

Calculating these proportions involves dividing the number of favorable responses by the total respondents in each group. For women, this means using the formula \( \hat{p}_1 = \frac{r_1}{n_1} \), where \( r_1 \) is the number of women who responded 'yes,' and \( n_1 \) is the total number of women surveyed. Similarly, for men, \( \hat{p}_2 = \frac{r_2}{n_2} \). By setting up these proportions, we form the basis for comparing if there's a meaningful difference between the groups.
Two-Tailed Test
A two-tailed test is a statistical method used to evaluate if there is a significant difference in either direction between two data groups. It's called "two-tailed" because it looks for deviations on both sides of the expected value distribution. In our exercise, we need to check if the population proportions of men and women who favor increased arts funding are significantly different.

In hypothesis testing, the null hypothesis usually posits that there's no difference between groups. A two-tailed test challenges this by checking for possibilities in both directions — greater than or less than. Here, our null hypothesis \( H_0 \) is \( p_1 = p_2 \), indicating no difference in proportions. The alternative hypothesis \( H_a \) is \( p_1 eq p_2 \), suggesting there is indeed a difference.

We calculate the test statistic (often a z-score) and compare it to critical values from the standard normal distribution. For a two-tailed test at a 0.05 significance level, these critical values are approximately \( \pm 1.96 \). If our calculated value falls outside this range, we reject the null hypothesis, hinting at a significant difference.
Significance Level
The significance level, often denoted as \( \alpha \), is the probability of rejecting the null hypothesis when it is actually true. It's a threshold used in hypothesis testing to determine if the test statistic is statistically significant. In our example, the significance level is set at 0.05. This means we are willing to accept a 5% chance of incorrectly concluding that there is a difference when there isn't one.

Setting the significance level is critical as it reflects the degree of certainty desired in a hypothesis test. A smaller \( \alpha \) (like 0.01) indicates a stricter test with less chance of a Type I error, but it might reduce the test's sensitivity. Conversely, a larger \( \alpha \) increases the chances of detecting an effect but also the likelihood of a false positive.

When conducting a two-tailed test, we adjust this level to account for both ends of the distribution. For instance, with \( \alpha = 0.05 \), we split this, attributing 2.5% to each tail, leading to critical z-values of \( \pm 1.96 \). These help decide whether our sample evidence sufficiently contradicts the null hypothesis, determining the test's outcome.

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Most popular questions from this chapter

Please read the Focus Problem at the beginning of this chapter. Recall that Benford's Law claims that numbers chosen from very large data files tend to have "1" as the first nonzero digit disproportionately often. In fact, research has shown that if you randomly draw a number from a very large data file, the probability of getting a number with " 1 " as the leading digit is about \(0.301\) (see the reference in this chapter's Focus Problem). Now suppose you are an auditor for a very large corporation. The revenue report involves millions of numbers in a large computer file. Let us say you took a random sample of \(n=215\) numerical entries from the file and \(r=46\) of the entries had a first nonzero digit of 1 . Let \(p\) represent the population proportion of all numbers in the corporate file that have a first nonzero digit of \(1 .\) i. Test the claim that \(p\) is less than \(0.301\). Use \(\alpha=0.01\). ii. If \(p\) is in fact less than \(0.301\), would it make you suspect that there are not enough numbers in the data file with leading 1's? Could this indicate that the books have been "cooked" by "pumping up" or inflating the numbers? Comment from the viewpoint of a stockholder. Comment from the perspective of the Federal Bureau of Investigation as it looks for money laundering in the form of false profits. iii. Comment on the following statement: If we reject the null hypothesis at level of significance \(\alpha\), we have not proved \(H_{0}\) to be false. We can say that the probability is \(\alpha\) that we made a mistake in rejecting \(H_{0} .\) Based on the outcome of the test, would you recommend further investigation before accusing the company of fraud?

A random sample of \(n_{1}=288\) voters registered in the state of California showed that 141 voted in the last general election. A random sample of \(n_{2}=216\) registered voters in the state of Colorado showed that 125 voted in the most recent general election. (See reference in Problem 25.) Do these data indicate that the population proportion of voter turnout in Colorado is higher than that in California? Use a \(5 \%\) level of significance.

Prose rhythm is characterized as the occurrence of five-syllable sequences in long passages of text. This characterization may be used to assess the similarity among passages of text and sometimes the identity of authors. The following information is based on an article by D. Wishart and S. V. Leach appearing in Computer Studies of the Humanities and Verbal Behavior (Vol. 3, pp. 90-99). Syllables were categorized as long or short. On analyzing Plato's Republic, Wishart and Leach found that about \(26.1 \%\) of the five-syllable sequences are of the type in which two are short and three are long. Suppose that Greek archaeologists have found an ancient manuscript dating back to Plato's time (about \(427-347\) B.C. \() .\) A random sample of 317 five-syllable sequences from the newly discovered manuscript showed that 61 are of the type two short and three long. Do the data indicate that the population proportion of this type of fivesyllable sequence is different (either way) from the text of Plato's Republic? Use \(\alpha=0.01\)

In general, if sample data are such that the null hypothesis is rejected at the \(\alpha=1 \%\) level of significance based on a two-tailed test, is \(H_{0}\) also rejected at the \(\alpha=1 \%\) level of significance for a corresponding one-tailed test? Explain.

The U.S. Department of Transportation, National Highway Traffic Safety Administration, reported that \(77 \%\) of all fatally injured automobile drivers were intoxicated. A random sample of 27 records of automobile driver fatalities in Kit Carson County, Colorado, showed that 15 involved an intoxicated driver. Do these data indicate that the population proportion of driver fatalities related to alcohol is less than \(77 \%\) in Kit Carson County? Use \(\alpha=0.01\).

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