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Assume that \(x\) has a normal distribution with the specified mean and standard deviation. Find the indicated probabilities. $$ P(3 \leq x \leq 6) ; \mu=4 ; \sigma=2 $$

Short Answer

Expert verified
The probability that \( x \) falls between 3 and 6 is approximately 0.5328.

Step by step solution

01

Standardize the Variable

To find the probabilities for a normal distribution, we first convert the values to the standard normal distribution (z-distribution). The formula to convert to a standard score (z-score) is given by \[ z = \frac{x - \mu}{\sigma} \]. Apply this formula to both bounds 3 and 6.
02

Calculate the Z-Scores

For the lower bound 3, the z-score is \( z = \frac{3 - 4}{2} = -0.5 \). For the upper bound 6, the z-score is \( z = \frac{6 - 4}{2} = 1.0 \).
03

Use Z-Table for Probabilities

Consult the standard normal distribution (z) table to find the probabilities for the calculated z-scores. From the z-table, \( P(z \leq -0.5) \approx 0.3085 \) and \( P(z \leq 1.0) \approx 0.8413 \).
04

Calculate Probability of the Range

To find the probability that \( x \) is between 3 and 6, subtract the probability of the lower z-score from the probability of the upper z-score: \( P(3 \leq x \leq 6) = P(z \leq 1.0) - P(z \leq -0.5) \).
05

Final Calculation

Substitute the probabilities from the z-table into the previous step: \( 0.8413 - 0.3085 = 0.5328 \). Thus, the probability that \( x \) falls between 3 and 6 is approximately 0.5328.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score calculation
When dealing with normal distributions, one of the first and crucial steps is calculating the Z-score. It serves as a way to transform your data into a standardized form, which aids in comparing different points in a distribution.
To compute a Z-score, we employ the formula: \[ z = \frac{x - \mu}{\sigma} \]where:
  • \(x\) - the value in the distribution you're examining
  • \(\mu\) - the mean of the distribution
  • \(\sigma\) - the standard deviation
By converting raw data points into Z-scores, you center your data around a mean of zero with a standard deviation of one. This helps to simplify probability calculations, as we'll see in the following sections. Given the problem where \(\mu = 4\) and \(\sigma = 2\), calculating the Z-scores for bounds at \(x = 3\) and \(x = 6\) gives us \(z = -0.5\) and \(z = 1.0\), respectively. These Z-scores are used to find probabilities within the standard normal distribution.
Standard normal distribution
The standard normal distribution, often referred to as the Z-distribution, plays a key role in statistics. It is a normal distribution with a mean \(\mu\) of 0 and a standard deviation \(\sigma\) of 1.
This is a special form of normal distribution that allows us to map any normal distribution to it using Z-scores. Essentially, when we convert our data using Z-scores, we're mapping it onto this template standard distribution. This transformation normalizes any dataset, facilitating easier probability analysis.
Most statistical tables, such as the Z-table, are designed based on this standard normal distribution. By converting different datasets into Z-scores, these tables can be universally applied to find probabilities. In practical terms, once the Z-scores of \(-0.5\) and \(1.0\) are determined, they can be used to look up precise probabilities directly from the Z-table.
Probability range calculation
Calculating the probability for a specific range in a normal distribution involves several steps, starting from transforming your values to a standard form and concluding with range probability analysis.
Once Z-scores are determined, these serve as inputs to ascertain cumulative probabilities from a Z-table. For example:
  • The Z-score of \(-0.5\) corresponds to a cumulative probability roughly equal to \(0.3085\)
  • A Z-score of \(1.0\) holds a cumulative probability close to \(0.8413\)
To find the probability that \(x\) falls between 3 and 6, these individual cumulative probabilities are leveraged. Specifically, on a range, this is done by subtracting the lower cumulative probability from the higher one. Hence, the calculation is expresssed as: \[P(3 \leq x \leq 6) = P(z \leq 1.0) - P(z \leq -0.5)\]This results in \(0.8413 - 0.3085 = 0.5328\). Thus, the probability that \(x\) will fall between the values of 3 and 6 in this distribution is approximately \(53.28\)\%. This makes it clear and straightforward to understand how probabilities manifest across ranges within normal distributions.

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Most popular questions from this chapter

Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and the time a patrol car radios that it has arrived at the scene (based on information from the Denver Post). Over a long period of time, it has been determined that the police response time has a normal distribution with a mean of \(8.4\) minutes and a standard deviation of \(1.7\) minutes. For a randomly received emergency call, what is the probability that the response time will be (a) between 5 and 10 minutes? (b) less than 5 minutes? (c) more than 10 minutes?

Sketch the areas under the standard normal curve over the indicated intervals, and find the specified areas. $$ \text { Between } z=0.32 \text { and } z=1.92 $$

Does a raw score less than the mean correspond to a positive or negative standard score? What about a raw score greater than the mean?

Sketch the areas under the standard normal curve over the indicated intervals, and find the specified areas. $$ \text { To the right of } z=0 $$

A person's blood glucose level and diabetes are closely related. Let \(x\) be a random variable measured in milligrams of glucose per deciliter (1/10 of a liter) of blood. After a 12 -hour fast, the random variable \(x\) will have a distribution that is approximately normal with mean \(\mu=85\) and standard deviation \(\sigma=25\) (Diagnostic Tests with Nursing Implications, edited by S. Loeb, Springhouse Press). Note: After 50 years of age, both the mean and standard deviation tend to increase. What is the probability that, for an adult (under 50 years old) after a 12 -hour fast, (a) \(x\) is more than 60 ? (b) \(x\) is less than \(110 ?\) (c) \(x\) is between 60 and \(110 ?\) (d) \(x\) is greater than 140 (borderline diabetes starts at 140 )?

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