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Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and the time a patrol car radios that it has arrived at the scene (based on information from the Denver Post). Over a long period of time, it has been determined that the police response time has a normal distribution with a mean of \(8.4\) minutes and a standard deviation of \(1.7\) minutes. For a randomly received emergency call, what is the probability that the response time will be (a) between 5 and 10 minutes? (b) less than 5 minutes? (c) more than 10 minutes?

Short Answer

Expert verified
(a) 0.8036, (b) 0.0228, (c) 0.1736.

Step by step solution

01

Understand the Problem

To solve this problem, we need to calculate probabilities related to a normal distribution with a known mean and standard deviation. The mean response time is \(8.4\) minutes and the standard deviation is \(1.7\) minutes.
02

Define Variables

Let \(X\) be the random variable representing police response time. We have \(X \sim N(8.4, 1.7^2)\), where \(8.4\) is the mean and \(1.7\) is the standard deviation.
03

Standardize the Variable

To find probabilities, we convert the original variable \(X\) into a standard normal variable \(Z\) using the formula: \[ Z = \frac{X - \mu}{\sigma} \] where \(\mu = 8.4\) and \(\sigma = 1.7\).
04

Solve for (a): Probability Between 5 and 10 Minutes

First, convert the limits into \(Z\) values:- For \(X = 5\): \[ Z = \frac{5 - 8.4}{1.7} \approx -2.00 \]- For \(X = 10\): \[ Z = \frac{10 - 8.4}{1.7} \approx 0.94 \]Using a standard normal distribution table or calculator, find:- \(P(Z < 0.94) \approx 0.8264\)- \(P(Z < -2.00) \approx 0.0228\)The required probability is:\[ P(5 < X < 10) = P(-2.00 < Z < 0.94) = 0.8264 - 0.0228 = 0.8036 \]
05

Solve for (b): Probability Less Than 5 Minutes

Convert \(X = 5\) to \(Z\):\[ Z = \frac{5 - 8.4}{1.7} \approx -2.00 \]Using a standard normal distribution table, find:\[ P(Z < -2.00) \approx 0.0228 \]Thus, the probability is:\[ P(X < 5) = 0.0228 \]
06

Solve for (c): Probability More Than 10 Minutes

Convert \(X = 10\) to \(Z\):\[ Z = \frac{10 - 8.4}{1.7} \approx 0.94 \]Using a standard normal distribution table, find:\[ P(Z < 0.94) \approx 0.8264 \]Thus, the probability is:\[ P(X > 10) = 1 - P(Z < 0.94) = 1 - 0.8264 = 0.1736 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability calculation in a normal distribution is a way to determine how likely it is that a random variable, such as police response time, falls within a certain range. In a normal distribution, probabilities are calculated by transforming the original variable into a standard normal variable, also known as a "Z-score." This involves using the formula \( Z = \frac{X - \mu}{\sigma} \), where \(X\) is your data point, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.
After transforming into a Z-score, we refer to a Z-table (or use a statistical calculator) to find the probability that \(Z\) falls below a particular value. This process, known as standardizing, helps us relate our problem to the standard normal distribution table.
  • "Probability between two values": Subtract the smaller probability from the larger one.
  • "Probability less than a value": Directly find the cumulative probability for the Z-score.
  • "Probability more than a value": Subtract the cumulative probability from 1.
Standard Normal Variable
The standard normal variable, denoted as \(Z\), is a way of expressing data points in terms of how many standard deviations they are from the mean. The normal distribution is defined by the mean \(\mu\) and the standard deviation \(\sigma\), whereas the standard normal distribution is centered at zero with a standard deviation of one.
To convert any normal random variable \(X\) into the standard normal variable \(Z\), we use:
  • \( Z = \frac{X - \mu}{\sigma} \)
This conversion is important because it simplifies probability calculations by allowing us to utilize the standard normal distribution table. Thanks to this transformation, a single standard normal probability table is used for all problems of this nature, making it a universal tool in probability and statistics.
This simplification eliminates the need for multiple tables or complex calculations, promoting efficiency and understanding in statistical problem-solving.
Statistical Problem-Solving
Statistical problem-solving is a logical process of collecting, analyzing, and making interpretations or decisions from data. When dealing with problems involving normally distributed variables, like the response time of police units, we engage in a multi-step process.
A key principle in statistical problem-solving is clarity in defining the problem, followed by variable standardization. We first identify what we're solving for, then transform data into the standard normal variable. Assessing the data using these transformations helps us pinpoint probabilities accurately.
The steps can be summarized as:
  • Identify and understand the variables involved.
  • Standardize the variable \(X\) to \(Z\).
  • Consult the Z-table to find probabilities.
  • Interpret results in the context of the problem.
This approach applies not only to calculating response times but is also foundational in handling various statistical inquiries, ensuring structured and reliable results.

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Most popular questions from this chapter

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