/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Locating People Old Friends Info... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Locating People Old Friends Information Service is a California company that is in the business of finding addresses of long-lost friends. Old Friends claims to have a \(70 \%\) success rate (Source: Wall Street Journal). Suppose that you have the names of six friends for whom you have no addresses and decide to use Old Friends to track them. (a) Make a histogram showing the probability of \(r=0\) to 6 friends for whom an address will be found. (b) Find the mean and standard deviation of this probability distribution. What is the expected number of friends for whom addresses will be found? (c) Quota Problem How many names would you have to submit to be \(97 \%\) sure that at least two addresses will be found?

Short Answer

Expert verified
The mean is 4.2 and the standard deviation is 1.13. Submit at least 6 names to be 97% sure of finding at least 2 addresses.

Step by step solution

01

Define the Binomial Distribution

Since each friend's address retrieval is an independent event with two possible outcomes (finding or not finding the address), we use a binomial distribution. Here, the probability of finding an address for any friend, \( p \), is 0.7. The random variable, \( r \), denotes the number of friends for whom addresses are found, and \( n = 6 \) is the number of trials or friends.
02

Calculate Probabilities

To find the probabilities for \( r = 0 \) to 6, use the binomial probability formula: \[ P(r) = \binom{n}{r} p^r (1-p)^{n-r} \]. Calculate \( P(r) \) for \( r = 0, 1, 2, 3, 4, 5, 6 \).
03

Draw the Histogram

Create a histogram with the x-axis representing the number of friends \( r \) for whom addresses could be found (ranging from 0 to 6) and the y-axis representing the probability \( P(r) \). Plot each calculated probability to form the histogram.
04

Calculate the Mean

For a binomial distribution, the mean (expected value), \( \mu \), is given by \( \mu = np \). Here, \( n = 6 \) and \( p = 0.7 \), so \( \mu = 6 \times 0.7 \).
05

Calculate the Standard Deviation

The standard deviation, \( \sigma \), of a binomial distribution is calculated by \( \sigma = \sqrt{np(1-p)} \). Substituting the values: \( \sigma = \sqrt{6 \times 0.7 \times 0.3} \).
06

Solve the Quota Problem

To find \( n \), the number of names needed for a 97% probability of finding at least two addresses, use the complement probability and the cumulative binomial distribution: \[P(\text{at least 2}) = 1 - P(0) - P(1)\]. Calculate for different \( n \) until \( P(\text{at least 2}) \geq 0.97 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution
In probability theory, a probability distribution describes how a random variable behaves. For this exercise, we use the **Binomial Distribution** as the addresses either are found or are not, with a fixed number of trials. Each trial is an independent attempt to find an address, giving us a binary outcome. The probability of success (finding an address) is denoted as 0.7, and the probability of failure is 0.3 (since failing is 1 minus the success rate).
To calculate the binomial probabilities, we use the formula for each possible outcome where \( r \) ranges from 0 to 6:
\[ P(r) = \binom{n}{r} p^r (1-p)^{n-r} \]
where \( n \) is the total number of friends (6), and \( p \) is the probability of success (0.7). Therefore, you calculate these probabilities to understand how likely you are to find addresses for varying numbers of friends. This distribution helps visualize potential outcomes for situations involving random variables like this.
Mean and Standard Deviation
The **mean** of a probability distribution provides the expected value, which is the central tendency or average number of successes. For a binomial distribution, the mean \( \mu \) is calculated by multiplying the number of trials \( n \) by the probability of success \( p \):
\[ \mu = np \]
In this case, with 6 friends and a 70% success rate, you expect 4.2 addresses found.

The **standard deviation** measures the spread of the probability distribution, indicating how much variation exists from the average:
\[ \sigma = \sqrt{np(1-p)} \]
For our situation, calculate it as the square root of \( 6 \times 0.7 \times 0.3 \). The standard deviation reflects uncertainty in the number of successful address findings.
Both parameters, mean and standard deviation, offer insight into the performance of Old Friends service, framing how typically successful the address retrieval will be, and how much the results might differ each time.
Histogram Construction
A histogram is a graphical representation of data used to summarize the distribution of a data set. For a binomial distribution, a histogram visually illustrates the probabilities of obtaining each possible number of successes.

To create the histogram for this particular problem, plot the number of friends \( r \) found on the x-axis, ranging from 0 to 6, and the calculated probability \( P(r) \) on the y-axis for each corresponding value. Each bar in the histogram represents the probability of finding an address for a certain number of friends.
  • Each bar's height is proportional to the probability \( P(r) \), showing how likely you are to find addresses for exactly 0, 1, 2,..., up to 6 friends.
  • The area under the histogram represents the total probability, which is always equal to 1.
  • This visual aid helps in understanding how likely each outcome is and identifying the most probable number of friends you can expect to get addresses for.
The histogram serves as a practical tool to visualize and comprehend the distribution of probabilities in binomial events like this one.
Cumulative Probability
**Cumulative Probability** provides the likelihood of obtaining a number of successes that is less than or equal to a particular value. It's calculated by summing the individual probabilities of all outcomes up to that number. This concept is crucial in situations where we need to determine the probability of achieving at least a specific number of successes.
In this exercise, to find how many names need to be submitted to be 97% certain of finding at least two addresses, you would use the cumulative function:
\[ P(\text{at least 2}) = 1 - P(0) - P(1) \]
This equation uses the complement rule which says the probability of finding at least two addresses is one minus the probabilities of finding none or only one. You would adjust the number of friends \( n \) being submitted to ensure this cumulative probability surpasses 0.97.
  • Calculate the cumulative probability for different \( n \) values.
  • Determine the minimum \( n \) where this probability reaches or exceeds 97%.
  • This ensures a strategic approach to finding a desired number of addresses with high confidence.
Cumulative probability provides a comprehensive view, allowing decisions based on confident estimates of success rates.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Are your finances, buying habits, medical records, and phone calls really private? A real concern for many adults is that computers and the Internet are reducing privacy. A survey conducted by Peter D. Hart Research Associates for the Shell Poll was reported in USA Today. According to the survey, \(37 \%\) of adults are concerned that employers are monitoring phone calls. Use the binomial distribution formula to calculate the probability that (a) out of five adults, none is concerned that employers are monitoring phone calls. (b) out of five adults, all are concerned that employers are monitoring phone calls. (c) out of five adults, exactly three are concerned that employers are monitoring phone calls.

: Brain Teaser If you enjoy a little abstract thinking, you may want to derive the formula for the negative binomial probability distribution. Use the notation of Problem 26. Consider two events, \(A\) and \(B\). \(A=\\{\) event that the first \(n-1\) trials contain \(k-1\) successes \(\\}\) \(B=\\{\) event that the \(n\) th trial is a success\\} (a) Use the binomial probability distribution to show that the probability of \(A\) is \(P(A)=\mathrm{C}_{n-1, k-1} p^{k-1} q^{(n-1)-(k-1)} .\) (b) Show that the probability of \(B\) is that of a single trial in a binomial experiment, \(P(B)=p\). (c) Why is \(P(A\) and \(B)=P(A) \cdot P(B) ?\) Hint \(:\) Binomial trials are independent. (d) Use parts (a), (b), and (c) to compute and simplify \(P(A\) and \(B)\). (e) Compare \(P(A\) and \(B)\) with the negative binomial formula and comment on the meaning of your results.

In a binomial experiment, is it possible for the probability of success to change from one trial to the next? Explain.

Norb and Gary are entered in a local golf tournament. Both have played the local course many times. Their scores are random variables with the following means and standard deviations. $$ \text { Norb, } x_{1}: \mu_{1}=115 ; \sigma_{1}=12 \quad \text { Gary, } x_{2}: \mu_{2}=100 ; \sigma_{2}=8 $$ In the tournament, Norb and Gary are not playing together, and we will assume their scores vary independently of each other. (a) The difference between their scores is \(W=x_{1}-x_{2} .\) Compute the mean, variance, and standard deviation for the random variable \(W\). (b) The average of their scores is \(W=0.5 x_{1}+0.5 x_{2}\). Compute the mean, variance, and standard deviation for the random variable W (c) The tournament rules have a special handicap system for each player. For Norb, the handicap formula is \(L=0.8 x_{1}-2 .\) Compute the mean, variance, and standard deviation for the random variable \(L .\) (d) For Gary, the handicap formula is \(L=0.95 x_{2}-5 .\) Compute the mean, variance, and standard deviation for the random variable \(L\).

For a binomial experiment, what probability distribution is used to find the probability that the first success will occur on a specified trial?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.