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For each of the following situations, explain why the combinations rule or the permutations rule should be used. (a) Determine the number of different groups of 5 items that can be selected from 12 distinct items. (b) Determine the number of different arrangements of 5 items that can be selected from 12 distinct items.

Short Answer

Expert verified
(a) Combinations rule: 792 groups; (b) Permutations rule: 95,040 arrangements.

Step by step solution

01

Identify the Problem Type for Part (a)

In part (a), we need to determine the number of different groups of 5 items out of 12 distinct items. Since the order of selection does not matter when forming groups, the combinations rule should be used.
02

Calculate the Combinations for Part (a)

Use the combinations formula: \(\binom{n}{r} = \frac{n!}{r!(n-r)!}\). Here, \(n = 12\) and \(r = 5\). Calculate \(\binom{12}{5} = \frac{12!}{5!(12-5)!} = \frac{12!}{5! \times 7!}\). Simplify to get the result, \(\binom{12}{5} = 792\).
03

Identify the Problem Type for Part (b)

In part (b), we need to calculate the number of different arrangements of 5 items selected from 12 distinct items. Since the order of arrangement matters, the permutations rule should be applied.
04

Calculate the Permutations for Part (b)

Use the permutations formula: \(P(n, r) = \frac{n!}{(n-r)!}\). Here, \(n = 12\) and \(r = 5\). Calculate \(P(12, 5) = \frac{12!}{(12-5)!} = \frac{12!}{7!}\). Simplify to get the result, \(P(12, 5) = 95,040\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinations
Combinations are all about forming groups where the order of items doesn't matter. Imagine you have a set of items, and you're interested in choosing a certain number without caring how they're arranged. In mathematical terms, a combination is a selection of items from a larger pool without regard to the order in which they are arranged. To calculate combinations, you use the combination formula:\[\binom{n}{r} = \frac{n!}{r!(n-r)!}\]- **\(n\)** represents the total number of items available.- **\(r\)** is the number of items you want to choose.- \(!\) denotes the factorial function.This formula helps you find how many different groups can be formed. For example, in a situation where you need to select 5 items out of 12, and the arrangement in which you select them doesn't matter, you use the combination formula as shown:\[\binom{12}{5} = \frac{12!}{5! \times 7!} = 792\]This tells us there are 792 unique ways to form groups of 5 items from a group of 12.
Permutations
Permutations focus on arrangements where the order of items does matter. Think of it like arranging books on a shelf or seating guests in a specific order around a table. Each different arrangement counts uniquely.The formula for permutations is given by:\[P(n, r) = \frac{n!}{(n-r)!}\]Here:- **\(n\)** denotes the total number of items.- **\(r\)** is the number of items to arrange.- Again, \(!\) denotes the factorial function.This helps calculate all the possible ways to arrange a subset of items from a larger set. When order matters, using permutations makes sense. For example, to determine the number of ways to arrange 5 out of 12 items, you would calculate:\[P(12, 5) = \frac{12!}{7!} = 95,040\]There are 95,040 unique ways to order 5 items from a group of 12. Each different sequence counts as a unique permutation.
Factorial Function
The factorial function is a fundamental concept in combinatorics, often represented by an exclamation point \(!\). It is used to calculate the product of all positive integers up to a certain number. The notation **\(n!\)** means the product of all integers from \(1\) to \(n\). A few key points about the factorial function:- **\(n! = n \times (n-1) \times ... \times 2 \times 1\)**.- **\(0!\)** is a special case, which is defined to be \(1\).Factorials grow rapidly with larger numbers, and they're a crucial component in calculating combinations and permutations. For example, when finding **\(5!\)**, you calculate:\[5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\]This fundamental building block allows you to compute the number of different ways to arrange items (permutations) or to select items without regard for order (combinations). Behind every permutation and combination formula is the strength and simplicity of the factorial function.

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