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In Exercises 73-78, identify the terms. Then identify the coefficients of the variable terms of the expression. $$ \sqrt{3} x^{2}-8 x-11 $$

Short Answer

Expert verified
The terms of the expression are \(\sqrt{3}x^2\), \(-8x\), and \(-11\). The coefficients of the variable terms are \(\sqrt{3}\) and \(-8\), respectively.

Step by step solution

01

Identify terms

In an algebraic expression, terms are separated by plus or minus signs. Thus, the terms in the expression \(\sqrt{3}x^2 - 8x - 11\) are \(\sqrt{3}x^2\), \(-8x\), and \(-11\). It's important to include the signs (- or +) of the terms.
02

Identify coefficients

The coefficient is the number that multiplies a variable. In the term \(\sqrt{3}x^2\), the coefficient of \(x^2\) is \(\sqrt{3}\). In the term \(-8x\), the coefficient of \(x\) is \(-8\). The term \(-11\) is a constant and has no variable attached to it, thus it has no coefficient.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficients
When diving into the world of algebra, understanding the term 'coefficient' is essential. A coefficient is essentially a numerical or constant factor that is paired with a variable in an algebraic term. Think of it as a tag-along number that multiplies the variable and influences its value. For instance, in the algebraic term \( \sqrt{3}x^2 \), \( \sqrt{3} \) is the coefficient of \( x^2 \). This means \( \sqrt{3} \) is the factor by which \( x^2 \) is multiplied.

Having trouble spotting them? Just look for the numbers directly in front of variables. Remember, coefficients can be positive, negative, fractional, or even irrational, as shown by the \( \sqrt{3} \) in our example. It's important to note that coefficients are integral to the overall value of an expression — they determine the 'weight' of each variable term in the equation.

Another example is the term \( -8x \). Here, \( -8 \) is the coefficient of \( x \) and implies that \( x \) is being multiplied by \( -8 \). And if you see a variable without a visible number, like \( x \), know that there's an invisible \( 1 \) acting as the coefficient, since any number multiplied by one is itself.
Polynomials
Polynomials are like the building blocks of algebra and come in many shapes and sizes. A polynomial is an expression made up of variables, coefficients, and exponents, arranged in a way that the exponents of the variables are all whole numbers. The beautifully simple expression \( \sqrt{3}x^2 - 8x - 11 \) is an example of a polynomial.

Polynomials can range from very simple, like \( x \) or \( 5 \), to more complex forms with many terms. Each part of a polynomial separated by a plus \( + \) or minus sign \( - \) is called a 'term.' In the expression we've been looking at, there are three terms: \( \sqrt{3}x^2 \), \( -8x \), and \( -11 \).

One of the coolest things about polynomials is that they can be as long or as short as you need them to be to describe all sorts of naturally occurring patterns, from the paths of falling objects to the growth of populations. The key to working with polynomials is recognizing their structure and how each term and coefficient fits into the bigger picture.
Algebraic Terms
Think of algebraic terms as the individual words in the language of algebra. Each term is a piece of the puzzle that makes up an expression. In the expression \( \sqrt{3}x^2 - 8x - 11 \), each part that is either added or subtracted (\( \sqrt{3}x^2 \) , \( -8x \) and \( -11 \)) is an algebraic term.

Each algebraic term can consist of numbers, variables, and exponents, but it operates as a single unit. A term can be just a number (which is called a 'constant') or just a variable, or it can be a combination of both, possibly raised to a power. In our example, \( \sqrt{3}x^2 \) and \( -8x \) are variable terms because they contain variables, while \( -11 \) is a constant term because it stands alone without a variable.

It's important to remember that in algebraic terms, the variables and their exponents tell us how these terms behave and relate to one another. By identifying and understanding each term within an expression, we unlock the ability to manipulate and solve complex algebraic problems.

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