Chapter 0: Problem 129
Solve the equation using any convenient method. $$ x^{2}-x-\frac{11}{4}=0 $$
Short Answer
Expert verified
The solutions to the quadratic equation \(x^{2} - x - \frac{11}{4} = 0\) are \(x = 2.23\) and \(x = -1.23\)
Step by step solution
01
Identify the quadratic equation
The given equation is a quadratic equation because it has a term with 'x' raised to the power of 2. The given equation is \(x^{2} - x - \frac{11}{4} = 0\). Here, \(a = 1\), \(b = -1\), and \(c = -\frac{11}{4}\). We will use the quadratic formula \(x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\) to solve this equation.
02
Compute the Discriminant
The formula for the discriminant 'D' is \(D = b^{2} - 4ac\). The discriminant will help us understand the type of roots. So, we substitute \(a = 1\), \(b = -1\), \(c = -\frac{11}{4}\) into the formula which results in: \(D = (-1)^{2} - 4*1*(-\frac{11}{4}) = 1 - (-11) = 12\). Therefore, D is equal to 12 which suggests that the equation will have two distinct real roots as \(D > 0\).
03
Substitute into the quadratic formula
We substitute \(a = 1\), \(b = -1\), and \(D = 12\) into the quadratic formula. This gives us the solutions: \(x = \frac{-(-1) \pm \sqrt{12}}{2*1} = \frac{1 \pm \sqrt{12}}{2}\)
04
Solve for 'x'
We calculate the square root of 12, and evaluate the two roots: \(x = \frac{1 + \sqrt{12}}{2} = \frac{1 + 3.46}{2} = 2.23\) and \(x = \frac{1 - \sqrt{12}}{2} = \frac{1 - 3.46}{2} = -1.23\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a vital tool in algebra for solving quadratic equations. Quadratic equations are in the standard form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants. This formula gives us a way to find the values of \( x \) that satisfy the equation. The formula is: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] It enables us to solve any quadratic equation by substituting the values of \( a \), \( b \), and \( c \) directly into it.
- The symbol \( \pm \) indicates that there are usually two solutions, corresponding to the addition and subtraction of the square root term.
- The formula relies on the discriminant \( b^2 - 4ac \) which determines the nature of the solutions.
Discriminant
The discriminant is a crucial part of the quadratic formula. It is represented as \( D = b^2 - 4ac \), where \( a \), \( b \), and \( c \) are coefficients from the quadratic equation \( ax^2 + bx + c = 0 \). The value of the discriminant tells us about the nature of the roots of the equation:
- If \( D > 0 \), there are two distinct real roots.
- If \( D = 0 \), there is exactly one real root (also known as a repeated root).
- If \( D < 0 \), there are no real roots; instead, the roots are complex numbers.
Real Roots
Real roots in the context of a quadratic equation refer to solutions that are real numbers, as opposed to complex numbers. When solving quadratic equations, determining the type of roots is important:
- When the discriminant \( D > 0 \), as in our example, there are two distinct real roots. This means the parabola represented by the quadratic equation touches the x-axis at two points.
- If \( D = 0 \), there is exactly one real root, meaning the parabola is tangent to the x-axis.
- Conversely, if \( D < 0 \), there are no real roots, as the parabola does not intersect the x-axis.