/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 129 Solve the equation using any con... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve the equation using any convenient method. $$ x^{2}-x-\frac{11}{4}=0 $$

Short Answer

Expert verified
The solutions to the quadratic equation \(x^{2} - x - \frac{11}{4} = 0\) are \(x = 2.23\) and \(x = -1.23\)

Step by step solution

01

Identify the quadratic equation

The given equation is a quadratic equation because it has a term with 'x' raised to the power of 2. The given equation is \(x^{2} - x - \frac{11}{4} = 0\). Here, \(a = 1\), \(b = -1\), and \(c = -\frac{11}{4}\). We will use the quadratic formula \(x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\) to solve this equation.
02

Compute the Discriminant

The formula for the discriminant 'D' is \(D = b^{2} - 4ac\). The discriminant will help us understand the type of roots. So, we substitute \(a = 1\), \(b = -1\), \(c = -\frac{11}{4}\) into the formula which results in: \(D = (-1)^{2} - 4*1*(-\frac{11}{4}) = 1 - (-11) = 12\). Therefore, D is equal to 12 which suggests that the equation will have two distinct real roots as \(D > 0\).
03

Substitute into the quadratic formula

We substitute \(a = 1\), \(b = -1\), and \(D = 12\) into the quadratic formula. This gives us the solutions: \(x = \frac{-(-1) \pm \sqrt{12}}{2*1} = \frac{1 \pm \sqrt{12}}{2}\)
04

Solve for 'x'

We calculate the square root of 12, and evaluate the two roots: \(x = \frac{1 + \sqrt{12}}{2} = \frac{1 + 3.46}{2} = 2.23\) and \(x = \frac{1 - \sqrt{12}}{2} = \frac{1 - 3.46}{2} = -1.23\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Formula
The quadratic formula is a vital tool in algebra for solving quadratic equations. Quadratic equations are in the standard form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants. This formula gives us a way to find the values of \( x \) that satisfy the equation. The formula is: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] It enables us to solve any quadratic equation by substituting the values of \( a \), \( b \), and \( c \) directly into it.
  • The symbol \( \pm \) indicates that there are usually two solutions, corresponding to the addition and subtraction of the square root term.
  • The formula relies on the discriminant \( b^2 - 4ac \) which determines the nature of the solutions.
In our example, \( a = 1 \), \( b = -1 \), and \( c = -\frac{11}{4} \) enabled us to find solutions using these values. Using the quadratic formula helps us solve various real-world problems where quadratic equations appear.
Discriminant
The discriminant is a crucial part of the quadratic formula. It is represented as \( D = b^2 - 4ac \), where \( a \), \( b \), and \( c \) are coefficients from the quadratic equation \( ax^2 + bx + c = 0 \). The value of the discriminant tells us about the nature of the roots of the equation:
  • If \( D > 0 \), there are two distinct real roots.
  • If \( D = 0 \), there is exactly one real root (also known as a repeated root).
  • If \( D < 0 \), there are no real roots; instead, the roots are complex numbers.
In our problem, the discriminant \( D = 12 \) was calculated using \( b = -1 \) and \( a = 1, c = -\frac{11}{4} \). Since \( D = 12 \) which is greater than zero, it confirmed the presence of two distinct real roots for the equation.
Real Roots
Real roots in the context of a quadratic equation refer to solutions that are real numbers, as opposed to complex numbers. When solving quadratic equations, determining the type of roots is important:
  • When the discriminant \( D > 0 \), as in our example, there are two distinct real roots. This means the parabola represented by the quadratic equation touches the x-axis at two points.
  • If \( D = 0 \), there is exactly one real root, meaning the parabola is tangent to the x-axis.
  • Conversely, if \( D < 0 \), there are no real roots, as the parabola does not intersect the x-axis.
For the equation \( x^2 - x - \frac{11}{4} = 0 \), solving yielded two distinct real roots, approximately \( x = 2.23 \) and \( x = -1.23 \). These values show where the equation reaches zero or where the curve crosses the x-axis, highlighting important intersections.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.