Chapter 8: Problem 70
In Exercises 63-74, find all complex solutions to the given equations. $$ 4 x^{2}+1=0 $$
Short Answer
Expert verified
The solutions are \( x = \frac{i}{2} \) and \( x = -\frac{i}{2} \).
Step by step solution
01
Write the equation in standard form
The equation is already in standard quadratic form: \[ 4x^2 + 1 = 0 \]
02
Move the constant to the other side
Subtract 1 from both sides to isolate the quadratic term on one side:\[ 4x^2 = -1 \]
03
Isolate the squared variable
Divide both sides by 4 to solve for \( x^2 \):\[ x^2 = -\frac{1}{4} \]
04
Solve for x using imaginary numbers
To find \( x \), take the square root of both sides. Remember that taking the square root of a negative number involves an imaginary number, \( i \), where \( i = \sqrt{-1} \):\[ x = \pm \sqrt{-\frac{1}{4}} \]
05
Simplify the expression using i
Break down the square root as follows:\[ x = \pm \sqrt{-1} \times \sqrt{\frac{1}{4}} \] This simplifies to:\[ x = \pm i \times \frac{1}{2} \] Thus, the solutions are:\[ x = \pm \frac{i}{2} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equation
A quadratic equation is a polynomial equation of degree two. Its standard form is expressed as \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \). The equation you are solving here is \( 4x^2 + 1 = 0 \), which is already in the standard form because \( a = 4 \), \( b = 0 \), and \( c = 1 \).
Quadratic equations can have:
Quadratic equations can have:
- Two real solutions,
- One real solution, or
- Two complex solutions.
Imaginary Unit
The imaginary unit, denoted as \( i \), is a mathematical concept that allows us to work with square roots of negative numbers. By definition, \( i = \sqrt{-1} \). This property is fundamental for handling negative square roots while solving quadratic equations when the discriminant is less than zero.
Since our equation leads to \( x^2 = -\frac{1}{4} \), we naturally encounter the need to utilize the imaginary unit to express the square root of a negative number. The square root property, \( \sqrt{-a^2} = ai \), helps us take these complex solutions. In our example, \( x = \pm \frac{i}{2} \) because the square root of \(-\frac{1}{4}\) is expressed using \( i \).
Remember that any real number can also be expressed in terms of imaginary numbers, specifically, as a complex number where the imaginary part is zero.
Since our equation leads to \( x^2 = -\frac{1}{4} \), we naturally encounter the need to utilize the imaginary unit to express the square root of a negative number. The square root property, \( \sqrt{-a^2} = ai \), helps us take these complex solutions. In our example, \( x = \pm \frac{i}{2} \) because the square root of \(-\frac{1}{4}\) is expressed using \( i \).
Remember that any real number can also be expressed in terms of imaginary numbers, specifically, as a complex number where the imaginary part is zero.
Solving Equations
Solving equations, specifically quadratic ones, often involves a clear and systematic process. Here’s the step-by-step breakdown for tackling the equation \( 4x^2 + 1 = 0 \):
- Step 1: **Isolate the quadratic term** by rewriting it in standard form. Our starting point was \( 4x^2 + 1 = 0 \).
- Step 2: **Move constant terms** to the other side of the equation. Subtracting 1 gives \( 4x^2 = -1 \).
- Step 3: **Solve for the squared variable** by dividing by 4, leading to \( x^2 = -\frac{1}{4} \).
- Step 4: **Find \( x \) using square roots**, acknowledging the presence of \( i \): \( x = \pm \sqrt{-\frac{1}{4}} \).
- Step 5: **Simplify using the imaginary unit**: Breakdown the square root, resulting in \( x = \pm i \times \frac{1}{2} \).