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In Exercises 1-20, graph the curve defined by the following sets of parametric equations. Be sure to indicate the direction of movement along the curve. $$ x=-3 t, y=t^{2}+1, t \text { in }[0,4] $$

Short Answer

Expert verified
The curve moves from (0,1) to (-12,17) as \( t \) increases, indicating a leftward and upward motion.

Step by step solution

01

Understand the Parametric Equations

We have given parametric equations: \( x = -3t \) and \( y = t^2 + 1 \), with \( t \) ranging from \( 0 \) to \( 4 \). This means \( x \) and \( y \) are expressed in terms of parameter \( t \). Our first step is to understand what these equations represent in the Cartesian plane.
02

Determine the Range of Values for x and y

Calculate how \( x \) and \( y \) change as \( t \) varies within the given range. For \( t = 0 \), \( x = -3(0) = 0 \) and \( y = 0^2 + 1 = 1 \). For \( t = 4 \), \( x = -3(4) = -12 \) and \( y = 4^2 + 1 = 17 \). The range for \( x \) is from \( 0 \) to \( -12 \), and for \( y \), it is from \( 1 \) to \( 17 \).
03

Describe the Path of the Curve

To illustrate the path on the graph, consider several values of \( t \) within [0,4]. For example, at \( t = 1 \), \( x = -3 \) and \( y = 2 \), at \( t = 2 \), \( x = -6 \) and \( y = 5 \). As \( t \) increases, \( x \) decreases (moving left), and \( y \) increases (moving upwards). This shows the curve moves from right to left and from bottom to top.
04

Graph the Parametric Equations

Plot each of the calculated points on a Cartesian coordinate plane. Start at the point when \( t = 0 \), which is (0, 1), and end at the point when \( t = 4 \), which is (-12, 17). Connect these points with a smooth curve indicating the path direction as \( t \) increases.
05

Indicate the Direction on the Graph

On the graph, you should draw arrows along the curve showing the direction of movement. Since as \( t \) increases, \( x \) decreases, and \( y \) increases, the arrows should point left and upward.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Parametric Equations
Graphing parametric equations requires us to plot points on a plane that are guided by a parameter. In this case, we use the parameter \( t \) to express both \( x \) and \( y \) coordinates. This distinct representation differs from standard Cartesian equations where \( y \) is typically expressed directly as a function of \( x \).
Instead, we have equations like \( x = -3t \) and \( y = t^2 + 1 \). To graph these, we calculate the pairs \((x, y)\) for various values of \( t \).
Plot these points on a coordinate plane. Connect them smoothly to reveal the curve's path. Each plot point corresponds directly to a specific \( t \) value, marking distinct locations. Using this method allows for intricate curves that standard functions might not directly offer.
Parametrization in the Cartesian Plane
Parametrization is a powerful tool that allows us to describe curves in the Cartesian plane. By employing a parameter \( t \), we avoid the limitations of expressing one variable solely in terms of another. For example, by using \( x = -3t \) and \( y = t^2 + 1 \), we can capture the entire motion of a particle along a path, governed by \( t \).
This type of description is highly versatile. It is utilized in numerous fields, such as computer graphics and physics, where the position depends not only on one independent variable but possibly on time or other parameters. With parametric equations, curves that loop, overlap, or change direction are easily represented—expanding beyond simple functional forms.
Direction of a Parametric Curve
Understanding the direction of a parametric curve involves following the trajectory of points as the parameter changes. In our example, as \( t \) increases from 0 to 4, observe how the path is traced. We started with the point \((0, 1)\) when \( t = 0 \) and ended at \((-12, 17)\) when \( t = 4 \).
The direction is indicated by the decrease in \( x \) (moving left) and increase in \( y \) (moving up).
To signify this motion on a graph, arrows are placed along the curve. This visually communicates how the curve progresses with increasing \( t \), helping understand not just the shape but the orientation along which the curve is traced.
Range of Parametric Variables
The range of parametric variables like \( t \) is crucial in understanding the span of the curve. In our example, \( t \) is limited to the interval [0, 4], which controls the range of both \( x \) and \( y \).
Calculate the corresponding \( x \) and \( y \) at these endpoints to determine the effective span of the graph. For \( t = 0 \), we receive \( x = 0 \), \( y = 1 \), and for \( t = 4 \), we see \( x = -12 \), \( y = 17 \).
This analysis shows that within this range, the entire curve from right to left (and bottom to top) is captured. Specifying the parameter interval is as vital as establishing the initial equations, as it sets the stage for physical or theoretical scenarios.

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Most popular questions from this chapter

For Exercises 37-46, recall that the flight of a projectile can be modeled with the parametric equations $$ x=\left(v_{0} \cos \theta\right) t \quad y=-16 t^{2}+\left(v_{0} \sin \theta\right) t+h $$ where \(t\) is in seconds, \(v_{0}\) is the initial velocity in feet per second, \(\theta\) is the initial angle with the horizontal, and \(h\) is the initial height above ground, where \(x\) and \(y\) are in feet. Bullet Fired. A gun is fired from the ground at an angle of \(60^{\circ}\), and the bullet has an initial speed of 700 feet per second. How high does the bullet go? What is the horizontal (ground) distance between where the gun was fired and where the bullet hit the ground?

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