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In Exercises 1-12, write each expression as a complex number in standard form. If an expression simplifies to either a real number or a pure imaginary number, leave in that form. $$ \sqrt{-20} $$

Short Answer

Expert verified
The expression simplifies to \( 2i\sqrt{5} \).

Step by step solution

01

Identify the Imaginary Part

The expression given is \( \sqrt{-20} \). Recognize that when dealing with the square root of a negative number, we can extract the imaginary unit \( i \), where \( i^2 = -1 \). Thus, we can rewrite \( \sqrt{-20} \) as \( \sqrt{-1} \times \sqrt{20} = i \times \sqrt{20} \).
02

Simplify the Radical

Now focus on simplifying \( \sqrt{20} \). The number 20 can be broken down into its prime factors: \( 20 = 2^2 \times 5 \). By taking the square root, we can simplify this to \( 2 \times \sqrt{5} \), because \( \sqrt{2^2} = 2 \).
03

Combine Results

Combine the results from the previous steps to express the original expression as a complex number: \( i \times 2 \times \sqrt{5} = 2i\sqrt{5} \).
04

Write in Standard Form

The standard form for complex numbers is \( a + bi \), where \( a \) is the real part and \( b \) is the imaginary part. In this expression, the real part is zero and the imaginary part is \( 2\sqrt{5} \). Thus, the expression is in the form \( 0 + 2i\sqrt{5} \) or simply \( 2i\sqrt{5} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Imaginary Unit
When dealing with complex numbers, the term "imaginary unit" often comes up. This is represented by the symbol \( i \), which is the fundamental unit of imaginary numbers. The imaginary unit is defined such that \( i^2 = -1 \). This definition allows us to work with the square roots of negative numbers, a task that's impossible within the realm of real numbers.

Normally, the square root of a negative number doesn't exist within the real number system. However, by introducing the imaginary unit \( i \), we are able to express these square roots in a meaningful way.

For example, \( \sqrt{-20} \) can be expressed using the imaginary unit. It's rewritten as \( i \times \sqrt{20} \), where \( i = \sqrt{-1} \), separating the negative part from the positive part under the square root.
Standard Form
Complex numbers are often expressed in their standard form, which is \( a + bi \). Here, \( a \) represents the real part, while \( b \) is the coefficient of the imaginary part. This form provides a clear structure for complex numbers and is useful for arithmetic operations involving them.

In the expression \( 2i\sqrt{5} \), although it might seem a bit different, it's still a complex number. It fits the standard form because it can be written as \( 0 + 2i\sqrt{5} \). This makes it clear that the real part, \( a \), is zero, and the imaginary part, \( b \), is \( 2\sqrt{5} \).

Understanding and using the standard form makes it easier to add, subtract, and multiply complex numbers, or even just move back and forth between purely real, purely imaginary, or mixed formats.
Radical Simplification
Radical simplification is the process of simplifying expression under a square root sign, often called a radical sign. It's crucial when working with expressions that include square roots, like the \( \sqrt{20} \) in \( \sqrt{-20} \). Breaking numbers down into their prime factors helps achieve this simplification.

Consider \( 20 \), whose prime factors are \( 2^2 \times 5 \). The square root of \( 20 \) is \( \sqrt{2^2 \times 5} = 2\sqrt{5} \), because \( \sqrt{2^2} = 2 \).

By simplifying the radical, calculations become easier and expressions are more manageable. This simplification results in expressing complex numbers with clear terms, aligning with the standard form for easier understanding and computation.

So, when you see \( \sqrt{-20} \), breaking it down becomes \( 2i\sqrt{5} \), a more simplified and usable form.

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Most popular questions from this chapter

In Exercises 45-68, graph each equation. In Exercises 63-68, convert the equation from polar to rectangular form first and identify the resulting equation as a line, parabola, or circle. $$ r^{2} \cos ^{2} \theta-r \sin \theta=-2 $$

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In Exercises 1-20, graph the curve defined by the following sets of parametric equations. Be sure to indicate the direction of movement along the curve. $$ x=-3 t, y=t^{2}+1, t \text { in }[0,4] $$

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For Exercises 77 and 78, refer to the following: The sword artistry of the samurai is legendary in Japanese folklore and myth. The elegance with which a samurai could wield a sword rivals the grace exhibited by modern figure skaters. In more modern times, such legends have been rendered digitally in many different video games (e.g., Ominusha). In order to make the characters realistically move across the screen-and in particular, wield various sword motions true to the legends-trigonometric functions are extensively used in constructing the underlying graphics module. One famous movement is a figure eight, swept out with two hands on the sword. The actual path of the tip of the blade as the movement progresses in this figure-eight motion depends essentially on the length \(L\) of the sword and the speed with which the figure is swept out. Such a path is modeled using a polar equation of the form \(r^{2}(\theta)=L \cos (A \theta)\) or \(r^{2}(\theta)=L \sin (A \theta), \theta_{1} \leq \theta \leq \theta_{2}\). Video Games. Graph the following equations: a. \(r^{2}(\theta)=5 \cos \theta, 0 \leq \theta \leq 2 \pi\) b. \(r^{2}(\theta)=5 \cos (2 \theta), 0 \leq \theta \leq \pi\) c. \(r^{2}(\theta)=5 \cos (4 \theta), 0 \leq \theta \leq \frac{\pi}{2}\) What do you notice about all of these graphs? Suppose that the movement of the tip of the sword in a game is governed by these graphs. Describe what happens if you change the domain in (b) and (c) to \(0 \leq \theta \leq 2 \pi\).

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