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In Exercises 1-18, solve each of the trigonometric equations exactly over the indicated intervals. $$ \cos \theta=-\frac{\sqrt{2}}{2}, 0 \leq \theta<2 \pi $$

Short Answer

Expert verified
The solutions are \(\theta = \frac{3\pi}{4}\) and \(\theta = \frac{5\pi}{4}\).

Step by step solution

01

Identify the general solution for cosine

Generally, when \(\cos \theta = -\frac{\sqrt{2}}{2}\), \(\theta\) corresponds to an angle in the second and third quadrants (as cosine is negative in these quadrants). From the unit circle, these angles are \(\frac{3\pi}{4}\) and \(\frac{5\pi}{4}\).
02

Write solutions within the given interval

The interval given is \(0 \leq \theta < 2\pi\). Since \(\frac{3\pi}{4}\) and \(\frac{5\pi}{4}\) are both within this interval, these are the solutions to the equation \(\cos \theta = -\frac{\sqrt{2}}{2}\) within the given range.
03

Final solutions

Thus, the exact solutions for the trigonometric equation \(\cos \theta = -\frac{\sqrt{2}}{2}\) over the interval \([0, 2\pi)\) are \(\theta = \frac{3\pi}{4}\) and \(\theta = \frac{5\pi}{4}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Cosine Function
The cosine function, often abbreviated as "cos," is one of the fundamental trigonometric functions. It gives the x-coordinate of a point on the unit circle for a given angle.

The cosine function is periodic, with a period of \(2\pi\). This means that it repeats every \(2\pi\) radians (or 360 degrees). A single cycle of the cosine function starts at a maximum value, decreases to a minimum, and then returns to the maximum.

Some key characteristics of the cosine function include:
  • Its range, which is from -1 to 1.
  • The function is even, meaning \( \cos(-\theta) = \cos(\theta) \).
  • It starts at \(\cos(0) = 1\).
These properties make the cosine function valuable for solving trigonometric equations, especially when determining angles that correspond to specific cosine values.
Exploring the Unit Circle
The unit circle is a circle with a radius of 1, centered at the origin of a coordinate plane. It is a key concept in trigonometry, used to define sine, cosine, and tangent functions geometrically.

For a given angle \(\theta\), the unit circle helps to determine:
  • The x-coordinate, equivalent to \(\cos(\theta)\).
  • The y-coordinate, equivalent to \(\sin(\theta)\).
On the unit circle, angles are often measured in radians. The negative cosine values occur in the second and third quadrants of the circle, where the x-coordinates are negative. This understanding helps in solving equations like \( \cos \theta = -\frac{\sqrt{2}}{2} \).

The unit circle not only simplifies calculations in trigonometry but also provides a clear visual representation of how trigonometric functions behave, aiding in the understanding of trigonometric solutions.
Finding Trigonometry Solutions
Solving trigonometric equations involves finding all the angles (or "solutions") that satisfy a given equation within a specific interval.

To effectively tackle these solutions:
  • Identify the general values of \(\theta\) related to the trigonometric functions given.
  • Use known angles from the unit circle to pinpoint specific solutions.
  • Ensure solutions are within the specified interval, such as \([0, 2\pi)\).
For example, to find \(\theta\) where \( \cos \theta = -\frac{\sqrt{2}}{2} \), we rely on the unit circle to know these values occur in the second and third quadrants. Thus, the solutions in the interval \([0, 2\pi)\) are \(\theta = \frac{3\pi}{4} \) and \(\theta = \frac{5\pi}{4} \).

This methodical approach, leveraging both conceptual understanding and geometric interpretation, is what makes solving trigonometric equations manageable and systematic.

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Most popular questions from this chapter

In Exercises 37-48, solve each of the trigonometric equations on the interval \(0^{\circ} \leq \theta<360^{\circ}\). Give answers in degrees and round to two decimal places. $$ \cos (2 x)+\sin x+1=0 $$

In Exercises 1-36, solve each of the trigonometric equations exactly on the interval \(0 \leq x<2 \pi\). $$ \sin (2 x)=\sqrt{3} \sin x $$

Business. An analysis of a company's costs and revenue shows that the annual costs of producing its product as well as annual revenues from the sale of a product are generally subject to seasonal fluctuations and are approximated by the function $$ \begin{array}{ll} C(t)=25.7+0.2 \sin \left(\frac{\pi}{6} t\right) & 0 \leq t \leq 11 \\ R(t)=25.7+9.6 \cos \left(\frac{\pi}{6} t\right) & 0 \leq t \leq 11 \end{array} $$ where \(t\) represents time in months \((t=0\) represents January), \(C(t)\) represents the monthly costs of producing the product in millions of dollars, and \(R(t)\) represents monthly revenue from sales of the product in millions of dollars. Find the month(s) in which the company breaks even.

For Exercises 87-92, refer to the following: Graphing calculators can be used to find approximate solutions to trigonometric equations. For the equation \(f(x)=g(x)\), let \(Y_{1}=f(x)\) and \(Y_{2}=g(x)\). The \(x\) values that correspond to points of intersections represent solutions. Use a graphing utility to find all solutions to the equation \(\cos \theta=e^{\theta}\) for \(\theta \geq 0\).

In Exercises 75-78, determine whether each statement is true or false. The solution set for the equation \(\sin ^{2} x=0.5 \sin x\) for \(0 \leq x<2 \pi\) is \(\left[\frac{\pi}{6}, \frac{5 \pi}{6}\right]\).

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