Chapter 6: Problem 12
In Exercises 1-36, solve each of the trigonometric equations exactly on the interval \(0 \leq x<2 \pi\). $$ \sin (2 x)=\sqrt{3} \sin x $$
Short Answer
Expert verified
Solutions are \(x = 0, \pi, \frac{\pi}{6}, \frac{11\pi}{6}\).
Step by step solution
01
Use Double Angle Identity
Recall the double angle identity for sine: \( \sin(2x) = 2\sin(x)\cos(x) \). Substitute this into the given equation: \( 2\sin(x)\cos(x) = \sqrt{3}\sin(x) \).
02
Factor the Equation
Factor out \(\sin(x)\) from the equation: \( \sin(x)(2\cos(x) - \sqrt{3}) = 0 \). This equation is satisfied when either \(\sin(x) = 0\) or \(2\cos(x) - \sqrt{3} = 0\).
03
Solve for \(\sin(x) = 0\)
\(\sin(x) = 0\) at \(x = 0, \pi, 2\pi\) within the interval \(0 \leq x < 2\pi \). However, since the interval is \([0, 2\pi)\), the point \(2\pi\) is excluded. Thus, solutions are \(x = 0, \pi\).
04
Solve for \(2\cos(x) - \sqrt{3} = 0\)
Rearrange the equation: \(2\cos(x) = \sqrt{3}\). Thus, \(\cos(x) = \frac{\sqrt{3}}{2}\). \(\cos(x) = \frac{\sqrt{3}}{2}\) at \(x = \frac{\pi}{6}\) and \(x = \frac{11\pi}{6}\) within the interval \(0 \leq x < 2\pi\).
05
Compile All Solutions
Combining solutions from Step 3 and Step 4, the complete solution set is \(x = 0, \pi, \frac{\pi}{6}, \frac{11\pi}{6}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Double Angle Identity
The double angle identity for sine is a powerful tool used in trigonometry to simplify and solve equations. The identity is given by:\[ \sin(2x) = 2\sin(x)\cos(x) \]This equation expresses the sine of a double angle in terms of sine and cosine functions of the original angle. It is particularly useful because it breaks down more complicated expressions into simpler parts.
- When you see an equation involving \(\sin(2x)\), consider substituting this identity.
- This helps in transforming the equation into a form that can be more easily solved.
Demystifying the Sine Function
The sine function is a fundamental trigonometric function that describes the y-coordinate of a point on the unit circle. It's periodic with a period of \(2\pi\), which means it repeats every \(2\pi\) units. When solving trigonometric equations like \(\sin(x) = 0\), think about the points where the sine curve crosses the x-axis. These points are crucial as they indicate where the function equals zero.
- \(\sin(x) = 0\) typically at multiples of \(\pi\): specifically at \(x = 0, \pi, 2\pi, \ldots\).
- For an interval \(0 \leq x < 2\pi\), only include solutions at \(x = 0\) and \(x = \pi\), excluding \(2\pi\) because it is outside the specified interval.
Exploring the Cosine Function
Like sine, the cosine function is essential in trigonometry. It gives the x-coordinate of a point on the unit circle and is also periodic with a period of \(2\pi\).The cosine is particularly useful when solving equations where it's given as a specific value. For instance, finding \(x\) for which \(\cos(x) = \frac{\sqrt{3}}{2}\) involves remembering key angles where cosine takes on this value.
- \(\cos(x) = \frac{\sqrt{3}}{2}\) at specific angles \(x = \frac{\pi}{6}\) and \(x = \frac{11\pi}{6}\) within \(0 \leq x < 2\pi\).
- These angles correspond to the positions on the unit circle where the x-coordinate of the point is \(\frac{\sqrt{3}}{2}\).