/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 This exercise provides a justifi... [FREE SOLUTION] | 91Ó°ÊÓ

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This exercise provides a justifiction for the properties of the inverse cosine function on page \(150 .\) Let \(t\) be a real number in the closed interval \([0, \pi]\) and let $$ y=\cos (t) $$ We then see that \(-1 \leq y \leq 1\) and $$ \cos ^{-1}(y)=t $$ (a) Use equations (1) and (2) to rewrite the expression \(\cos ^{-1}(\cos (t))\). (b) Use equations (1) and (2) to rewrite the expression \(\cos \left(\cos ^{-1}(y)\right)\).

Short Answer

Expert verified
(a) Using the given equations, we can rewrite the expression \(\cos^{-1}(\cos(t))\) as \(\cos^{-1}(y)\), where \(y = \cos(t)\). Due to the property \(\cos^{-1}(y) = t\), the simplified expression is \(t\). (b) We can rewrite the expression \(\cos(\cos^{-1}(y))\) as \(\cos(t)\), where \(t = \cos^{-1}(y)\). Since \(y = \cos(t)\), the simplified expression is \(y\).

Step by step solution

01

Expression 1: Rewrite \(\cos^{-1}(\cos(t))\)

Given that \(y = \cos(t)\), we can rewrite the expression \(\cos ^{-1}(\cos (t))\) as \(\cos ^{-1}(y)\). Now recall that \(\cos ^{-1}(y)=t\), this means that \(\cos ^{-1}(\cos (t)) = t\). Hence the expression is simplified to its variable, \(t\).
02

Expression 2: Rewrite \(\cos(\cos^{-1}(y))\)

Given that \(y = \cos(t)\), we can rewrite \(t\) as \(\cos ^{-1}(y)\). Now let's replace \(t\) with \(\cos ^{-1}(y)\) in the expression \(\cos(\cos^{-1}(y))\): this becomes \(\cos(\cos^{-1}(y)) = \cos(t)\). Now recall that \(y = \cos(t)\), so the expression \(\cos(\cos^{-1}(y)) = y\). Therefore, the second expression is simplified to just \(y\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometry
Trigonometry is a branch of mathematics that focuses on the relationships between angles and sides of triangles. The basis of trigonometry lies in the study of right-angled triangles where one of the angles is always 90 degrees.

In trigonometry, we define six fundamental functions that relate the angles of a triangle to the lengths of its sides. These functions are sine, cosine, tangent, cotangent, secant, and cosecant. For any given angle in a triangle, these functions represent a ratio of two sides.

The function we focus on in the context of the given exercise is the cosine function. The cosine of an angle in a right-angled triangle is the ratio of the adjacent side to the hypotenuse. This ratio remains constant for a fixed angle, regardless of the triangle's size. One crucial aspect of trigonometry is understanding that these trigonometric functions allow us to work with angles and sides in a variety of practical problems. By mastering these concepts, students are equipped to solve problems in fields such as physics, engineering, astronomy, and even in diverse sectors like music and acoustics.
Cosine
The cosine function is one of the primary functions in trigonometry. Algebraically, for an angle \theta, the cosine function is written as \(\cos(\theta)\) and geometrically, it represents the x-coordinate on the unit circle or the ratio of the adjacent side over the hypotenuse in a right-angled triangle.

What makes the cosine function particularly interesting and useful is its relationship to the unit circle. When dealing with the unit circle, where the radius is 1, the cosine function relates to the coordinates of a point on the circle's circumference. Specifically, if a line makes an angle \(\theta\) with the positive x-axis, the x-coordinate of where this line intersects the unit circle is \(\cos(\theta)\).

It's important for students to grasp that because of the nature of the unit circle, the value of cosine will always be between -1 and 1, inclusive. This property is essential when studying the cosine function and its intricacies, particularly its inverse.
Inverse Trigonometric Functions
Inverse trigonometric functions allow us to find the angle when given a ratio of sides of a right-angled triangle, essentially reversing the standard trigonometric functions. The inverse cosine function, denoted as \(\cos^{-1}\) or arccos, is the function that gives the angle whose cosine is a given number.

Delving into the exercise provided, the inverse cosine of y, written as \(\cos^{-1}(y)\), will return the angle t whose cosine is y. This is crucial to understand when solving problems that require you to move back and forth between angles and their cosine values. The inverse trigonometric functions, just like the trigonometric functions, are defined within specific ranges to ensure they are functions in the mathematical sense - that is, for each input, there is only one output.

For the cosine inverse, the range is limited to \(0, \pi\), which corresponds to 0 to 180 degrees in terms of angles. This means that for every value between -1 and 1, there is a unique angle between 0 and \pi radians (or 0 and 180 degrees) whose cosine is that value. When using inverse trigonometric functions, it is essential to remember their ranges as it helps in correctly solving and understanding problems where these functions are applied.

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Most popular questions from this chapter

For each of the equations of the following equations, use an inverse trigonometric function to write the exact values of all the solutions of the equation on the indicated interval. Then use the periodic property of the trigonometric function to write formulas that can be used to generate all of the solutions of the given equation. (a) \(\sin (x)+2=2.4\) with \(-\pi \leq x \leq \pi\). (b) \(5 \cos (x)+3=7\) with \(-\pi \leq x \leq \pi\) (c) \(2 \tan (x)+4=10\) with \(-\frac{\pi}{2}

Rewrite each of the following using the corresponding trigonometric function for the inverse trigonometric function. Then determine the exact value of the inverse trigonometric function. (a) \(t=\arcsin \left(\frac{\sqrt{2}}{2}\right)\) (b) \(t=\arcsin \left(-\frac{\sqrt{2}}{2}\right)\) (c) \(t=\arccos \left(\frac{\sqrt{2}}{2}\right)\) (f) \(y=\tan ^{-1}\left(\frac{-\sqrt{3}}{3}\right)\) (g) \(y=\cos ^{-1}(0)\) (d) \(t=\arccos \left(-\frac{\sqrt{2}}{2}\right)\) (h) \(t=\arctan (0)\) (i) \(y=\sin ^{-1}\left(-\frac{1}{2}\right)\) (e) \(y=\tan ^{-1}\left(\frac{\sqrt{3}}{3}\right)\) (j) \(y=\cos ^{-1}\left(-\frac{1}{2}\right)\)

Determine the exact value of each of the following expressions. (a) \(\cos \left(\arcsin \left(\frac{2}{5}\right)\right)\) (d) \(\cos \left(\arcsin \left(-\frac{2}{5}\right)\right)\) (b) \(\sin \left(\arccos \left(-\frac{2}{3}\right)\right)\) (e) \(\tan \left(\arccos \left(-\frac{2}{9}\right)\right)\) (c) \(\tan \left(\arcsin \left(\frac{1}{3}\right)\right)\)

For each of the following equations, use a graph to approximate the solutions (to three decimal places) of the equation on the indicated interval. Then use the periodic property of the trigonometric function to write formulas that can be used to approximate any solution of the given equation. (a) \(\sin (x)=0.75\) with \(-\pi \leq x \leq \pi\) (b) \(\cos (x)=0.75\) with \(-\pi \leq x \leq \pi\) (c) \(\tan (x)=0.75\) with \(-\frac{\pi}{2}

Determine the amplitude, period, phase shift, and vertical shift for each of the following sinusoids. Then use this information to graph one complete period of the sinusoid and state coordinates of a high point, a low point, and a point where the sinusoid crosses the center line. (a) \(y=4 \sin \left(\pi x-\frac{\pi}{8}\right)\). (c) \(y=-3.2 \cos \left(50 \pi x-\frac{\pi}{2}\right)\). (b) \(y=5 \cos \left(4 x+\frac{\pi}{2}\right)+2\). (d) \(y=4.8 \sin \left(\frac{1}{4} x+\frac{\pi}{8}\right)\).

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