/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Rewrite each of the following us... [FREE SOLUTION] | 91Ó°ÊÓ

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Rewrite each of the following using the corresponding trigonometric function for the inverse trigonometric function. Then determine the exact value of the inverse trigonometric function. (a) \(t=\arcsin \left(\frac{\sqrt{2}}{2}\right)\) (b) \(t=\arcsin \left(-\frac{\sqrt{2}}{2}\right)\) (c) \(t=\arccos \left(\frac{\sqrt{2}}{2}\right)\) (f) \(y=\tan ^{-1}\left(\frac{-\sqrt{3}}{3}\right)\) (g) \(y=\cos ^{-1}(0)\) (d) \(t=\arccos \left(-\frac{\sqrt{2}}{2}\right)\) (h) \(t=\arctan (0)\) (i) \(y=\sin ^{-1}\left(-\frac{1}{2}\right)\) (e) \(y=\tan ^{-1}\left(\frac{\sqrt{3}}{3}\right)\) (j) \(y=\cos ^{-1}\left(-\frac{1}{2}\right)\)

Short Answer

Expert verified
a) \(t = \frac{\pi}{4}\) b) \(t = -\frac{\pi}{4}\) c) \(t = \frac{\pi}{4}\) d) \(y=-\frac{\pi}{6}\) e) \(y = \frac{\pi}{2}\) f) \(t = \frac{3\pi}{4}\) g) \(t = 0\) h) \(y = -\frac{\pi}{6}\) i) \(y = \frac{\pi}{6}\) j) \(y = \frac{2\pi}{3}\)

Step by step solution

01

(a) Rewrite the expression

Rewrite the given expression as: \(t=\arcsin \left(\frac{\sqrt{2}}{2}\right)\) This implies: \(\sin(t) =\frac{\sqrt{2}}{2}\)
02

(a) Find the exact value

From the unit circle, we know that the angle t for which \(\sin(t) =\frac{\sqrt{2}}{2}\) is: \(t = \frac{\pi}{4}\)
03

(b) Rewrite the expression

Rewrite the given expression as: \(t=\arcsin \left(-\frac{\sqrt{2}}{2}\right)\) This implies: \(\sin(t) =-\frac{\sqrt{2}}{2}\)
04

(b) Find the exact value

From the unit circle, we know that the angle t for which \(\sin(t) =-\frac{\sqrt{2}}{2}\) is: \(t = -\frac{\pi}{4}\)
05

(c) Rewrite the expression

Rewrite the given expression as: \(t=\arccos \left(\frac{\sqrt{2}}{2}\right)\) This implies: \(\cos(t) =\frac{\sqrt{2}}{2}\)
06

(c) Find the exact value

From the unit circle, we know that the angle t for which \(\cos(t) =\frac{\sqrt{2}}{2}\) is: \(t = \frac{\pi}{4}\)
07

(d) Rewrite the expression

Rewrite the given expression as: \(y=\tan ^{-1}\left(\frac{-\sqrt{3}}{3}\right)\) This implies: \(\tan(y) =-\frac{\sqrt{3}}{3}\)
08

(d) Find the exact value

Rewrite the given expression as: \(y=-\frac{\pi}{6}\)
09

(e) Rewrite the expression

Rewrite the given expression as: \(y=\cos ^{-1}(0)\) This implies: \(\cos(y) =0\)
10

(e) Find the exact value

From the unit circle, we know that the angle y for which \(\cos(y) =0\) is: \(y = \frac{\pi}{2}\)
11

(f) Rewrite the expression

Rewrite the given expression as: \(t=\arccos \left(-\frac{\sqrt{2}}{2}\right)\) This implies: \(\cos(t) =-\frac{\sqrt{2}}{2}\)
12

(f) Find the exact value

From the unit circle, we know that the angle t for which \(\cos(t) =-\frac{\sqrt{2}}{2}\) is: \(t = \frac{3\pi}{4}\)
13

(g) Rewrite the expression

Rewrite the given expression as: \(t=\arctan (0)\) This implies: \(\tan(t) =0\)
14

(g) Find the exact value

From the unit circle, we know that the angle t for which \(\tan(t) =0\) is: \(t = 0\)
15

(h) Rewrite the expression

Rewrite the given expression as: \(y=\sin ^{-1}\left(-\frac{1}{2}\right)\) This implies: \(\sin(y) =-\frac{1}{2}\)
16

(h) Find the exact value

From the unit circle, we know that the angle y for which \(\sin(y) =-\frac{1}{2}\) is: \(y = -\frac{\pi}{6}\)
17

(i) Rewrite the expression

Rewrite the given expression as: \(y=\tan ^{-1}\left(\frac{\sqrt{3}}{3}\right)\) This implies: \(\tan(y) =\frac{\sqrt{3}}{3}\)
18

(i) Find the exact value

From the unit circle, we know that the angle y for which \(\tan(y) =\frac{\sqrt{3}}{3}\) is: \(y = \frac{\pi}{6}\)
19

(j) Rewrite the expression

Rewrite the given expression as: \(y=\cos ^{-1}\left(-\frac{1}{2}\right)\) This implies: \(\cos(y) =-\frac{1}{2}\)
20

(j) Find the exact value

From the unit circle, we know that the angle y for which \(\cos(y) =-\frac{1}{2}\) is: \(y = \frac{2\pi}{3}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Circle
Understanding the unit circle is crucial for grasping inverse trigonometric functions. The unit circle is a fundamental concept in trigonometry, where a circle has a radius of one unit and is centered at the origin of a coordinate plane. Each point on the unit circle corresponds to an angle, measured in radians from the positive x-axis, and can be represented as \( (cos(\theta), sin(\theta) \)) for that angle \(\theta\).

Recognizing certain angles and their corresponding points on the unit circle allows you to find the exact values of sine, cosine, and tangent functions for those angles. For example, the point \(\left(\frac{\sqrt{2}}{2},\frac{\sqrt{2}}{2}\right)\) corresponds to an angle of \(\frac{\pi}{4}\), which is why \(\sin\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}\) and \(\cos\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}\).

The beauty of the unit circle is that it provides a visual means to understand and remember the exact values for sine, cosine, and tangent functions at various angles, which is especially helpful for solving problems involving inverse trigonometric functions.
Exact Values of Trigonometric Functions
Determining the exact values of trigonometric functions is a skill often used in conjunction with the unit circle. Certain angles, known as special angles, have trigonometric function values that are precisely known without needing a calculator. These include angles like \(0\), \(\frac{\pi}{6}\), \(\frac{\pi}{4}\), \(\frac{\pi}{3}\), and \(\frac{\pi}{2}\), among others.

For instance, the sine of \(\frac{\pi}{6}\) is exactly \(\frac{1}{2}\), and the sine of \(\frac{\pi}{4}\) is \(\frac{\sqrt{2}}{2}\). Similarly, the cosine values follow a pattern that can often be deduced from the unit circle or by remembering the specific ratios associated with the special angles. Precise values for the tangent function can also be derived from the sine and cosine values or directly from the unit circle. Knowing these exact values enables quick solutions to problems involving inverse trigonometric functions and simplifies the process of verifying trigonometric identities.
Trigonometric Function Properties
The properties of trigonometric functions play an essential role in understanding and computing inverse trigonometric functions. Some key properties include the periodicity of sine, cosine, and tangent functions, meaning they repeat values at regular intervals of \(2\pi\) for sine and cosine, and \(\pi\) for tangent.

Another property is symmetry, where sine is odd-symmetrical around the origin, and cosine is even-symmetrical along the y-axis. The tangent function, being the ratio of sine to cosine, is also odd-symmetrical. Additionally, the ranges of these functions provide insights into the possible outputs for their corresponding inverse functions. For example, the range of \(\arcsin(x)\) is limited to the interval \(\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]\), while \(\arccos(x)\) ranges from \(0\) to \(\pi\), and \(\arctan(x)\) from \(\left[-\frac{\pi}{2}, \frac{\pi}{2}\right)\) without including \(\frac{\pi}{2}\).

Understanding these properties aids in accurately finding the angles associated with given trigonometric values, ensuring that answers for inverse trigonometric functions fall within their principal ranges, and helps in confirming the steps followed in solving problems related to inverse trigonometric functions.

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Most popular questions from this chapter

Modeling a Heartbeat. For a given person at rest, suppose the heart pumps blood at a regular rate of about 75 pulses per minute. Also, suppose that the volume of this person's heart is approximately 150 milliliters (ml), and it pushes out about \(54 \%\) its volume with each beat. We will model the volume, \(V(t)\) of blood (in milliliters) in the heart at any time \(t,\) as a sinusoidal function of the form $$ V(t)=A \cos (B t)+D $$ (a) If we choose time 0 to be a time when the heart is full of blood, why is it reasonable to use a cosine function for our model? (b) What is the maximum value of \(V(t) ?\) What is the minimum value of \(V(t) ?\) What does this tell us about the values of \(A\) and \(D ?\) Explain. (c) The frequency of a simple harmonic motion is the number of periods per unit time, or the number of pulses per minute in this example. How is the frequency \(f\) related to the period? What value should \(B\) have? Explain. (d) Draw a graph (without a calculator) of your \(V(t)\) using your values of \(A, B,\) and \(D,\) of two periods beginning at \(t=0\) (e) Clearly identify the maximum and minimum values of \(V(t)\) on the graph. What do these numbers tell us about the heart at these times?

If necessary, refer to Section 1.6 to answer the followiing questions. (a) How is the cotangent function defined? (b) What is the domain of the cotangent function? (c) Where will the graph of the cotangent function have vertical asymptotes? (d) What is the period of the cotangent function?

Draw the graph of each of the following sinusoidal functions over the indicated interval. For each graph, \- State the \(t\) -intercepts on the given interval. \- State the \(y\) -intercept. \- State the maximum value of the function and the coordinates of all the points where the maximum value occurs. \- State the minimum value of the function and the coordinates of all the points where the minimum value occurs. (a) \(y=\sin (t)\) with \(-2 \pi \leq t \leq 2 \pi\). (b) \(y=3 \cos (t)\) with \(-\pi \leq t \leq 3 \pi\) (c) \(y=5 \sin (t)\) with \(0 \leq t \leq 4 \pi\). (d) \(y=\frac{3}{7} \cos (t)\) with \(-\pi \leq t \leq 3 \pi\). (e) \(y=-2.35 \sin (t)\) with \(-\pi \leq t \leq \pi\). (f) \(y=-4 \cos (t)\) with \(0 \leq t \leq 6 \pi\).

As the moon orbits the earth, the appearance of the moon changes. We see various lunar disks at different times of the month. These changes reappear during each lunar month. However, a lunar month is not exactly the same as the twelve months we use in our calendar today. A lunar month is the number of days it takes the moon to go through one complete cycle from a full moon (100\% illumination) to the next full moon. The following data were gathered from the web site for the U.S. Naval Observatory. The data are the percent of the moon that is illuminated is geocentric value of the percent of the moon that is illuminated. That is, the percent of illumination is computed for a fictitious observer located at the center of the Earth.

(a) Use a graphing utility to draw the graph of \(y=\cot (x)\) using \(-\pi \leq\) (b) Use a graphing utility to draw the graph of \(y=\cot (x)\) using \(-2 \pi \leq\) \(x \leq 2 \pi\) and \(-10 \leq y \leq 10\)

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