/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 The curve \(y=\) \(a x^{2}+b x+c... [FREE SOLUTION] | 91Ó°ÊÓ

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The curve \(y=\) \(a x^{2}+b x+c\) passes through the point (1,2) and is tangent to the line \(y=x\) at the origin. Find \(a, b,\) and \(c\).

Short Answer

Expert verified
The values are \(a = 1\), \(b = 1\), and \(c = 0\).

Step by step solution

01

Understand Curve Equation

The given curve is a quadratic function of the form \(y = ax^2 + bx + c\). This is a parabola, and we need to find the coefficients \(a\), \(b\), and \(c\).
02

Condition: Pass Through Point (1,2)

The curve \(y = ax^2 + bx + c\) passes through the point (1,2). Substitute \(x = 1\) and \(y = 2\) into the equation:\[2 = a(1)^2 + b(1) + c \Rightarrow 2 = a + b + c.\]This gives us the first equation: \(a + b + c = 2\).
03

Condition: Tangent to Line at Origin

The curve is tangent to the line \(y = x\) at the origin \((0,0)\). For them to be tangent, they must meet at \((0,0)\) and have the same slope there.- At \(x = 0\), the curve \(y = ax^2 + bx + c\) becomes \(c = 0\) since \(y = 0\) when \(x = 0\).- The slope of \(y = x\) is \(1\). - The derivative of the curve \(y = ax^2 + bx + c\) is \(y' = 2ax + b\). At \(x = 0\), \(y' = b\). - Equating the slopes: \(b = 1\).
04

Substitute Known Values

- We found that \(c = 0\) and \(b = 1\). - Substitute \(b = 1\) and \(c = 0\) into the equation \(a + b + c = 2\): \[a + 1 + 0 = 2\] Solving this gives \(a = 1\).
05

Final Values

We solved the equations and found the values: - \(a = 1\)- \(b = 1\)- \(c = 0\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parabola
A parabola is a curve that is often represented by a quadratic function such as \(y = ax^2 + bx + c\). This quadratic equation describes an arch-like shape that can open either upward or downward, depending on the value of \(a\). If \(a > 0\), the parabola opens upward, resembling a U shape. If \(a < 0\), it opens downward, like an upside-down U.
Parabolas have a unique feature called the vertex, which is the highest or lowest point on the curve. The x-coordinate of the vertex can be found at \(x = -\frac{b}{2a}\). Parabolas are also symmetrical around a vertical line passing through the vertex, known as the axis of symmetry. Understanding how a parabola behaves is crucial when graphing quadratic functions or solving problems related to them.
In the given exercise, the function \(y = ax^2 + bx + c\) forms a parabola that passes through certain points and has specific tangency conditions, which allows us to solve for the coefficients \(a\), \(b\), and \(c\).
Tangent Line
A tangent line is a straight line that touches a curve at only one point without crossing it at that location. This special point is called the point of tangency. At this point, the tangent line has the same slope as the curve. This means it represents the instantaneous rate of change of the curve at that exact spot.
In the context of our problem, the line \(y = x\) acts as a tangent to the parabola \(y = ax^2 + bx + c\) at the origin \((0,0)\). Therefore, the parabola and the line not only intersect at this point but also share the same slope there. Understanding the concept of a tangent line helps solve problems involving curves and linear approximations.
Tangents are crucial in calculus and geometry as they help in understanding how curves behave at specific points and how they can be approximated by using lines.
Derivative
The derivative is a fundamental concept in calculus that measures how a function changes as its input changes. In simpler terms, you can think of it as the slope of the tangent line to the curve at any given point. For a quadratic function \(y = ax^2 + bx + c\), its derivative is \(y' = 2ax + b\). This equation gives us the slope of the curve at any point \(x\).
Calculating the derivative of a function allows us to find where the slope is zero (maximum or minimum points) or where the slope matches that of a tangent line. This is particularly useful in optimization problems and physics. In our example, when the curve \(y = ax^2 + bx + c\) is tangent to the line \(y = x\) at the origin, their slopes must be equal at \(x = 0\). By substituting into the derivative formula, we found \(b = 1\), which matched the slope of \(y = x\), demonstrating the power of applying derivatives to real-world problems.
Slope
Slope is a measure of the steepness or incline of a line. It can be described as the ratio of the vertical change to the horizontal change between two points. In mathematics, it's often represented by the letter \(m\). For straight lines, the slope remains constant, but for curves, the slope changes at every point.
The slope of a line can be calculated using the formula \(m = \frac{\Delta y}{\Delta x}\), where \(\Delta y\) represents the change in \(y\) and \(\Delta x\) represents the change in \(x\). For the linear function \(y = x\), the slope is 1, meaning the line rises one unit vertically for each unit it moves horizontally.
Understanding slope is crucial when dealing with tangents on curves, as it shows how the function behaves locally. In the problem, when the parabola \(y = ax^2 + bx + c\) is tangent to the line \(y = x\), their slopes at the point of tangency (the origin) must be equal. This gave us one of the key conditions (\(b=1\)) to solve for the unknowns in the parabola equation.

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Most popular questions from this chapter

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