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In Exercises \(35-68\) , use integration, the Direct Comparison Test, or the Limit Comparison Test to test the integrals for convergence. If more than one method applies, use whatever method you prefer. $$\int_{2}^{\infty} \frac{x d x}{\sqrt{x^{4}-1}}$$

Short Answer

Expert verified
The integral diverges by the Limit Comparison Test.

Step by step solution

01

Problem Analysis

The given integral is \( \int_{2}^{\infty} \frac{x \, dx}{\sqrt{x^4 - 1}} \). We need to find if this integral converges or diverges on the interval from 2 to infinity. We can use the Limit Comparison Test to compare with a simpler integral.
02

Choose a Comparison Function

Considering the expression under the square root, \(x^4 - 1\) is best approximated by \(x^4\) for large \(x\). Thus, consider the function \(f(x) = \frac{x}{x^2} = \frac{1}{x}\). This function simplifies to make comparison possible.
03

Apply Limit Comparison Test

The Limit Comparison Test requires us to find \(\lim_{x \to \infty} \frac{\frac{x}{\sqrt{x^4 - 1}}}{\frac{1}{x}}\). Simplify the expression: \(\frac{x}{{x^2}} \cdot \sqrt{\frac{x^4}{x^4-1}}\). At large \(x\), \(x^2 \approx x^2 \sqrt{\frac{1}{1}} = x^2\). Limit evaluates to 1.
04

Evaluate the Comparison Integral

Calculate \(\int_{2}^{\infty} \frac{1}{x} \, dx \). This integral is \(\ln|x|\) evaluated from 2 to infinity. As \(x\) approaches infinity, \(\ln|x|\) diverges. Therefore, the comparison integral diverges.
05

Conclusion

Since the limit comparison gave a positive finite number and the simpler integral \(\int_{2}^{\infty} \frac{1}{x} \, dx \) diverges, by the Limit Comparison Test, the original integral \(\int_{2}^{\infty} \frac{x \, dx}{\sqrt{x^4 - 1}} \) also diverges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Direct Comparison Test
The Direct Comparison Test is a powerful technique used in calculus to analyze the convergence or divergence of improper integrals. This method involves comparing a given function with another function that is easier to integrate and whose convergence properties are known. It works because if one function is consistently larger or smaller than another known function, then that integral will behave similarly in terms of convergence or divergence.

If you have two functions, suppose that for all \( x \) in the interval you're considering, \( 0 \leq f(x) \leq g(x) \). If \( \int_{a}^{b} g(x) \, dx \) converges, then \( \int_{a}^{b} f(x) \, dx \) must also converge. Conversely, if \( \int_{a}^{b} f(x) \, dx \) diverges, then \( \int_{a}^{b} g(x) \, dx \) will surely diverge as well.

This test requires a strategic choice of \( g(x) \), usually made by simplifying the given function to remove complicated terms. Through this simplification, one can focus on a dominant term that governs the behavior of the function as \( x \to \infty \) or \( x \to a \) for limits from \( a \) to \( b \). This approach simplifies the integral's complexity, offering a clearer path to determining convergence or divergence.
Limit Comparison Test
The Limit Comparison Test is a versatile tool in calculus that extends the idea of the Direct Comparison Test by simplifying the process of determining convergence or divergence without direct inequality comparison. This technique involves taking the limit of the ratio of two functions as \( x \) approaches infinity (or the point of limit).

Suppose you have two functions \( f(x) \) and \( g(x) \), and you want to determine the convergence property of the integral \( \int f(x) \, dx \). You identify a function \( g(x) \) that is simpler and well-understood, then compute the limit:
\[ \lim_{x \to a} \frac{f(x)}{g(x)} \]
If this limit \( L \) is a positive finite number, then both \( \int f(x) \, dx \) and \( \int g(x) \, dx \) will exhibit the same outcome regarding convergence or divergence. It is particularly useful when direct comparison is challenging or impractical.

In practice, this test often involves algebraic simplifications to match the behavior of more complex terms. For example, examining variations like removing smaller terms from polynomials offers a clear directive for comparison, preserving the relationship of the principal term like \( x^n \) for simplifications.
Improper Integrals
Improper integrals are integrals that have either an infinite limit of integration or an integrand discontinuous at some point in the range of integration. They extend the concept of a definite integral to accommodate functions and domains that do not fit within the typical limits. This makes them an essential tool for handling limits and continuity issues in calculus.

There are generally two types of improper integrals. These include:
  • Integrals with infinite bounds. Example: \( \int_{a}^{\infty} f(x) \, dx \)
  • Integrals with integrands that have improper nature at a certain point within the integral such as at points where the function is undefined.

To evaluate an improper integral, one must often use limits. For example, if the integral is \( \int_{a}^{\infty} f(x) \, dx \), we consider \( \lim_{b \to \infty} \int_{a}^{b} f(x) \, dx \).

Understanding the convergence or divergence of improper integrals is crucial in evaluating these integrals and is often determined using comparison tests like the Direct Comparison Test and the Limit Comparison Test. These integrals appear frequently in real-world applications, such as calculating probabilities in statistics or analyzing physically unbounded domains in physics.

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