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Lifetime of an electronic component The life expectancy in years of a component in a microcomputer is exponentially distributed, and 1\(/ 3\) of the components fail in the first 3 years. The company that manufactures the component offers a 1 year warranty. What is the probability that a component will fail during the warranty period?

Short Answer

Expert verified
The probability of failure within 1 year is approximately 0.177.

Step by step solution

01

Understanding Exponential Distribution

The lifetime of the component is exponentially distributed. This means that the probability density function is given by \( f(x; \lambda) = \lambda e^{-\lambda x} \), where \( \lambda \) is the rate parameter. The cumulative distribution function (CDF) is \( F(x; \lambda) = 1 - e^{-\lambda x} \).
02

Finding the Rate Parameter

We know that 1/3 or \( 0.33 \) of the components fail within 3 years. We use the CDF for this: \( F(3; \lambda) = 0.33 = 1 - e^{-3\lambda} \). Solving for \( \lambda \) gives us \( e^{-3\lambda} = 0.67 \). Taking the natural logarithm, we find \( -3\lambda = \ln(0.67) \), so \( \lambda = -\frac{\ln(0.67)}{3} \).
03

Calculating Probability of Failure in 1 Year

To find the probability that a component fails within the first year (warranty period), use the CDF: \( F(1; \lambda) = 1 - e^{-\lambda} \). Substitute the \( \lambda \) from Step 2 into this formula to find the desired probability.
04

Solve for Specific Probability

Using the calculated \( \lambda = -\frac{\ln(0.67)}{3} \), we substitute it into \( F(1; \lambda) \): \( F(1; \lambda) = 1 - e^{\ln(0.67)/3} \). Simplify the expression to find the probability that the component fails within the first year.
05

Final Calculation

Using the value of \( \lambda \), calculate \( F(1; \lambda) = 1 - e^{-\lambda} \approx 1 - (0.823) \approx 0.177 \). Thus, the probability that a component will fail during the warranty period is approximately 0.177.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Density Function
The probability density function (PDF) of an exponential distribution helps us understand the expected time between events in a Poisson process. For our microcomputer component, the PDF allows us to model the time until failure. The PDF for the exponential distribution is given by:
  • \( f(x; \lambda) = \lambda e^{-\lambda x} \)
Here, \( \lambda \) is the rate parameter, and \( x \) represents time. In simple terms, this function provides the likelihood of the component failing at any specific time \( x \). As \( x \) increases, \( e^{-\lambda x} \) decreases, reflecting the lower likelihood of failure over long periods. This behavior makes the exponential distribution particularly suitable for modeling product lifetimes such as electronics.
Cumulative Distribution Function
The cumulative distribution function (CDF) gives us the probability that a random variable is less than or equal to a certain value. For exponentially distributed variables, the CDF can be used to calculate the likelihood of a component failing within a certain period, taking into account all possible events up to that point.
  • The CDF is given by: \( F(x; \lambda) = 1 - e^{-\lambda x} \)
This formula tells us the probability that a component fails at or before time \( x \). For instance, to find the probability that a component will fail within the one-year warranty period, we calculate \( F(1; \lambda) \). This is crucial for manufacturers to understand the reliability of their products within specific timeframes.
Rate Parameter
The rate parameter, denoted by \( \lambda \), is a key part of the exponential distribution which indicates how quickly events happen. It is inversely related to the average lifetime of the product. A higher \( \lambda \) implies a quicker rate of event occurrence, meaning a component is more likely to fail sooner.To determine \( \lambda \), we use known failure rates within a given time period. In our case, since \( 1/3 \) of the components fail within 3 years, we apply the CDF formula to find \( \lambda \):
  • \( 0.33 = 1 - e^{-3\lambda} \)
  • Solving this, we find \( \lambda = -\frac{\ln(0.67)}{3} \)
Understanding \( \lambda \) helps manufacturers predict product longevity and optimize economic decisions regarding warranties and replacements.
Warranty Period
A warranty period is the time during which a manufacturer promises to repair or replace a defective product. This period is often chosen based on the expected lifetime of the product, informed by statistical models like the exponential distribution.For our electronic component, the company offers a 1-year warranty. To estimate the risk of component failure during this time, the CDF is applied:
  • Compute \( F(1; \lambda) \) to find the probability of failure within the first year.
  • For this example, the probability is approximately 0.177, suggesting that about 17.7% of components will fail during the warranty period.
Understanding this probability helps businesses make informed warranty policies, balancing customer satisfaction with economic viability.

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