/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 \begin{equation}\text { Each of ... [FREE SOLUTION] | 91Ó°ÊÓ

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\begin{equation}\text { Each of Exercises }31-36 \text { gives a function } f(x), {\text { a point }} c, \\\\{\text { and a positive number }}\varepsilon . {\text { Find } L=\lim _{x \rightarrow c}} f(x) .\\\ {\text { Then find a number }} \delta>0{\text { such that }}\end{equation} \begin{equation}|f(x)-L|<\varepsilon \text { whenever } 0<|x-c|<\delta.\end{equation} $$f(x)=\frac{x^{2}-4}{x-2}, \quad c=2, \quad \varepsilon=0.05$$

Short Answer

Expert verified
The limit is 4, and \( \delta = 0.05 \).

Step by step solution

01

Identify the Limit Problem

We need to find \( L = \lim_{x \to 2} \frac{x^{2} - 4}{x - 2} \). This function appears to be undefined at \( x=2 \), but we expect simplification to determine \( L \).
02

Simplify the Function

Notice that the numerator can be factored as \( (x-2)(x+2) \), giving us \( f(x) = \frac{(x-2)(x+2)}{x-2} \). For \( x eq 2 \), this simplifies to \( f(x)=x+2 \).
03

Evaluate the Limit

With the simplified form \( f(x) = x+2 \), we can find the limit as \( x \to 2 \). Therefore, \( L = \lim_{x \to 2} (x+2) = 4 \).
04

Set Up the Epsilon-Delta Definition

Now that we have \( L = 4 \), we need to find \( \delta > 0 \) such that whenever \( 0 < |x - 2| < \delta \), we get \( |f(x) - 4| < 0.05 \).
05

Analyze the Inequality

From the simplified function \( f(x)=x+2 \), we have \( |f(x) - 4| = |x+2 - 4| = |x - 2| \). Thus, we want \( |x - 2| < 0.05 \).
06

Choose Delta

Since we want \( |x-2| < 0.05 \), we can simply choose \( \delta = 0.05 \).
07

Verify the Solution

If \( 0 < |x - 2| < 0.05 \), then it is straightforward that \( |x-2| < 0.05 \) is satisfied, thus \( |f(x)-4| < 0.05 \) is also satisfied. Therefore, \( \delta = 0.05 \) works.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Epsilon-Delta Definition
The Epsilon-Delta Definition is a formal way of describing the limit of a function at a particular point. It is what mathematicians use to ensure the rigor of limits. This definition states that a function \( f(x) \) approaches a limit \( L \) as \( x \) approaches \( c \), if for every small positive number \( \varepsilon \) (epsilon), there is a corresponding small positive number \( \delta \) (delta), such that whenever \( 0 < |x - c| < \delta \), it guarantees \( |f(x) - L| < \varepsilon \).
This means that we can make \( f(x) \) as close to \( L \) as we want by choosing \( x \) sufficiently close to \( c \). In the exercise, we worked with \( \varepsilon = 0.05 \) and needed to find the delta \( \delta \) that satisfies the \( \varepsilon \)-\( \delta \) criterion.
Function Simplification
Simplifying a function is often essential when evaluating limits, especially when the function seems undefined at a point. In our example, the function given was \( f(x) = \frac{x^2 - 4}{x-2} \). Direct substitution at \( x = 2 \) gives us an indeterminate form \( \frac{0}{0} \).
To simplify, the numerator \( x^2 - 4 \) can be factored. Recognizing it as a difference of squares, we have \( x^2 - 4 = (x-2)(x+2) \). This lets us cancel \( x - 2 \) in the numerator and denominator for \( x eq 2 \), simplifying \( f(x) \) to \( x + 2 \).
With this simpler form, we can better handle limit evaluations.
Limit Evaluation
The process of Limit Evaluation involves determining the value that a function approaches as \( x \) approaches a specific number. Once the function \( f(x) = \frac{x^2 - 4}{x-2} \) was simplified to \( f(x) = x + 2 \) for \( x eq 2 \), we could then easily evaluate its limit.
As \( x \) approaches 2, the function \( x + 2 \) clearly approaches \( 4 \). Hence, the limit \( L \) is indeed \( 4 \). Evaluating limits after simplification allows us to avoid undefined expressions and simplifies calculations.
Factoring Polynomials
Factoring Polynomials is a crucial technique in mathematics used to simplify expressions, solve equations, and evaluate limits. It involves breaking down a polynomial into a product of its factors. In the exercise, we dealt with the polynomial \( x^2 - 4 \).
This polynomial was simplified by recognizing it as a difference of squares: \( x^2 - 4 = (x-2)(x+2) \). Factoring like this allows us to cancel terms and simplify the function to \( f(x) = x + 2 \) when \( x eq 2 \).
This step is vital to avoid undefined conditions and allows for straightforward limit evaluation.

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