Chapter 2: Problem 53
Find the limits in Exercises \(53-58 .\) $$\lim \frac{1}{x^{2}-4}$ as$$ $${ a. }x \rightarrow 2^{+} \quad \text { b. } x \rightarrow 2^{-}$$ $${ c. }x \rightarrow-2^{+} \quad \text { d. } x \rightarrow-2^{-}$$
Short Answer
Expert verified
a) \(+\infty\), b) \(-\infty\), c) \(-\infty\), d) \(+\infty\).
Step by step solution
01
Identify the Expression
We need to analyze the limit \( \lim \frac{1}{x^2 - 4} \). The denominator \( x^2 - 4 \) can be factored into \((x-2)(x+2)\). The problem involves limits approaching 2 from both the positive and negative directions, as well as approaching -2 from both directions.
02
Evaluate Limit as \(x \to 2^{+}\)
As \( x \) approaches 2 from the positive side, \( x^2 - 4 = (x-2)(x+2) \) approaches 0 from the positive side because \( x-2 > 0 \) and \( x+2 > 0 \). Thus, \( \frac{1}{x^2 - 4} \) approaches positive infinity: \[ \lim_{x \to 2^{+}} \frac{1}{x^2 - 4} = +\infty \]
03
Evaluate Limit as \(x \to 2^{-}\)
As \( x \) approaches 2 from the negative side, \( x^2 - 4 = (x-2)(x+2) \) approaches 0 from the negative side because \( x-2 < 0 \) and \( x+2 > 0 \). Therefore, \( \frac{1}{x^2 - 4} \) approaches negative infinity: \[ \lim_{x \to 2^{-}} \frac{1}{x^2 - 4} = -\infty \]
04
Evaluate Limit as \(x \to -2^{+}\)
As \( x \) approaches -2 from the positive side, \( x^2 - 4 = (x-2)(x+2) \) approaches 0 from the negative side because \( x-2 > -4 \) and \( x+2 < 0 \). Consequently, \( \frac{1}{x^2 - 4} \) approaches negative infinity: \[ \lim_{x \to -2^{+}} \frac{1}{x^2 - 4} = -\infty \]
05
Evaluate Limit as \(x \to -2^{-}\)
As \( x \) approaches -2 from the negative side, \( x^2 - 4 = (x-2)(x+2) \) approaches 0 from the positive side because \( x-2 < 0 \) and \( x+2 < 0 \). Thus, \( \frac{1}{x^2 - 4} \) approaches positive infinity: \[ \lim_{x \to -2^{-}} \frac{1}{x^2 - 4} = +\infty \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
One-Sided Limits
In calculus, one-sided limits help us determine the behavior of a function as it approaches a specific point from only one direction—either from the left or right. For the function \( \frac{1}{x^2 - 4} \), this means observing what happens as \( x \) nears certain critical values from one side.
In our exercise, we computed the limits as \( x \) approaches 2 and -2 from both the right (positive side) and the left (negative side). Here’s how it works:
In our exercise, we computed the limits as \( x \) approaches 2 and -2 from both the right (positive side) and the left (negative side). Here’s how it works:
- For \( x \to 2^+ \), the expression is analyzed as \( x \) gets close to 2 from the right-hand side, affecting the sign of the factor \( x-2 \).
- For \( x \to 2^- \), it focuses on approaching 2 from the left-hand side. Again, it's the sign of \( x-2 \) that's key here.
- The same concept applies when we look at \( x \to -2^+ \) and \( x \to -2^- \), determining how the factors in the denominator behave as \( x \) comes close to -2 from the right and left respectively.
Infinite Limits
When a function grows larger and larger without bound as it approaches a certain value, we say it has an infinite limit.
In our exercise concerning \( \frac{1}{x^2 - 4} \):
In our exercise concerning \( \frac{1}{x^2 - 4} \):
- As \( x \to 2^+ \), the denominator \((x-2)(x+2)\) approaches zero from the positive side, leading to the function tending towards \(+\infty\) because dividing by a very small positive number results in a very large positive number.
- On the other hand, when \( x \to 2^- \), the same denominator approaches zero from the negative side, so the limit becomes \(-\infty\) as division by a very small negative number results in a very large negative number.
- Similarly, as \( x \to -2^+ \), the denominator heads toward zero from the negative side, making the limit \(-\infty\).
- Finally, when \( x \to -2^- \), the denominator approaches zero from the positive side, causing the limit to be \(+\infty\).
Factoring in Limits
Factoring is a mathematical tool that can greatly simplify the process of evaluating limits, especially when the function involves polynomial expressions.
For example, the function in our exercise is \( \frac{1}{x^2 - 4} \). By factoring the denominator, we have:\[ x^2 - 4 = (x-2)(x+2) \]This factorization converts the function into a product, making it easier to analyze how the expression behaves as \( x \) approaches critical values like 2 and -2.
For example, the function in our exercise is \( \frac{1}{x^2 - 4} \). By factoring the denominator, we have:\[ x^2 - 4 = (x-2)(x+2) \]This factorization converts the function into a product, making it easier to analyze how the expression behaves as \( x \) approaches critical values like 2 and -2.
- It helps us clearly identify points where the denominator becomes zero, which are potential points of discontinuity or undefined behavior.
- Understanding the factorization allows us to determine the direction from which the denominator approaches zero, which is crucial for correctly evaluating one-sided limits and determining whether they lead to positive or negative infinity.