Chapter 16: Problem 17
In Exercises \(13-18,\) use the surface integral in Stokes' Theorem to calculate the flux of the curl of the field \(\mathbf{F}\) across the surface \(S\) in the direction of the outward unit normal $$\begin{array}{l}{\mathbf{F}=3 y \mathbf{i}+(5-2 x) \mathbf{j}+\left(z^{2}-2\right) \mathbf{k}} \\ {S : \quad \mathbf{r}(\phi, \theta)=(\sqrt{3} \sin \phi \cos \theta) \mathbf{i}+(\sqrt{3} \sin \phi \sin \theta) \mathbf{j}+} \\ {(\sqrt{3} \cos \phi) \mathbf{k}, \quad 0 \leq \phi \leq \pi / 2, \quad 0 \leq \theta \leq 2 \pi}\end{array}$$
Short Answer
Step by step solution
Understand the Problem
State Stokes' Theorem
Compute the Curl of \( \mathbf{F} \)
Evaluate Curl Components
Assemble the Curl
Compute the Flux Across \( S \)
Evaluate the Surface Integral
Solve the Integral
Compute the Final Answer
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
vector field curl
In the exercise, the curl of the vector field \( \mathbf{F} = 3y \mathbf{i} + (5 - 2x) \mathbf{j} + (z^2 - 2) \mathbf{k} \) was computed, resulting in \( abla \times \mathbf{F} = 0\mathbf{i} + 0\mathbf{j} - 5\mathbf{k} \). This means there is rotational behavior around the \( k \)-axis, with the magnitude of \(-5\).
surface integral
In this context, they determine the net flux through a surface, such as a flux of a vector field.When calculating the surface integral of a vector field’s curl, you are essentially measuring how much of the vector field is "crossing" the surface. According to Stokes' Theorem, this is equivalent to a line integral around the boundary of the surface. The formula for a surface integral of a vector field \( \mathbf{F} \) across surface \( S \) is given by:\[\iint_{S} \mathbf{F} \cdot d\mathbf{S}\]In this equation, \( d\mathbf{S} \) is a vector representing the infinitesimal area of the surface with an outward-facing normal.
The exercise describes this process where the surface integral of \(-5\mathbf{k}\) over the surface \( S \), parameterized in spherical coordinates, is calculated. The integration takes into account surface area and the vector field's behavior through \( S \).
flux calculation
To calculate the flux of a vector field through a surface, you must consider the vector field's orientation relative to the surface normal. Flux is measured as the surface integral of the vector field's dot product with the surface area vector:\[\text{Flux} = \iint_{S} \mathbf{F} \cdot d\mathbf{S}\]For our specific exercise, the goal was to find the flux of the curl of \( \mathbf{F} \) across the surface \( S \). That is, to evaluate how the field, represented by the curl \( abla \times \mathbf{F} \), spreads through the surface. In mathematical terms, this became a calculation of \(-5\) multiplied by the surface area of \( S \), after performing the integration over spherical coordinates.
This results in a total flux of \(-30\pi\), indicating a net inward flow through the surface \( S \), under the scenario given in the exercise.