Chapter 16: Problem 17
\(\begin{array}{l}{\text { Integrate } f(x, y, z)=(x+y+z) /\left(x^{2}+y^{2}+z^{2}\right) \text { over the path }} \\ {\mathbf{r}(t)=t \mathbf{i}+t \mathbf{j}+t \mathbf{k}, 0 < a \leq t \leq b}\end{array}\)
Short Answer
Expert verified
The integral is \( \ln \left(\frac{|b|}{|a|}\right) \).
Step by step solution
01
Parameterize the Path
Given the path as \( \mathbf{r}(t) = t \mathbf{i} + t \mathbf{j} + t \mathbf{k} \), we represent the position vector in components: \( x = t, y = t, z = t \). Hence, along the path, \( x + y + z = 3t \) and \( x^2 + y^2 + z^2 = 3t^2 \).
02
Set Up the Integral
Substitute \( x, y, z \) in \( f(x, y, z) \) to get \( f(t) = \frac{3t}{3t^2} = \frac{1}{t} \). The integral of \( f(t) \) over the path is \( \int_{a}^{b} \frac{1}{t} \, dt \).
03
Calculate the Integral
The integral \( \int \frac{1}{t} \, dt \) is the natural logarithm: \( \ln |t| + C \), where \( C \) is the constant of integration. Therefore, the definite integral from \( a \) to \( b \) is \( \left[ \ln |t| \right]_{a}^{b} = \ln |b| - \ln |a| \).
04
Simplify the Result
Use the properties of logarithms to combine the result: \( \ln |b| - \ln |a| = \ln \left(\frac{|b|}{|a|}\right) \). Therefore, the result of the integral is \( \ln \left(\frac{|b|}{|a|}\right) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Line Integral
A line integral, also know as a path integral, is a type of integral where we integrate over a curve. It extends the concept of a regular integral to functions defined along a path. Unlike regular integrals that deal with functions of one variable, line integrals can work on functions over curves in multi-dimensional space. In our exercise, we're dealing with a path in three dimensions, defined by the vector function \( \mathbf{r}(t) = t \mathbf{i} + t \mathbf{j} + t \mathbf{k} \).
This path is essentially a line along the vector \( \langle 1, 1, 1 \rangle \), starting from the point \((a, a, a)\) and ending at \((b, b, b)\). When setting up the line integral in the exercise, we integrate a scalar field \( f(x, y, z) = \frac{x+y+z}{x^2+y^2+z^2} \) along this path.
This path is essentially a line along the vector \( \langle 1, 1, 1 \rangle \), starting from the point \((a, a, a)\) and ending at \((b, b, b)\). When setting up the line integral in the exercise, we integrate a scalar field \( f(x, y, z) = \frac{x+y+z}{x^2+y^2+z^2} \) along this path.
- You substitute the path coordinates \( x=t, y=t, z=t \) into the scalar field, making it a function of \( t \), allowing you to compute the integral over the interval \( (a, b) \).
- The key idea is understanding how a line integral evaluates the cumulative sum of the function's values along the path in space, capturing the contribution of each point space.
Parametric Equations
Parametric equations are a powerful tool in vector calculus, allowing us to represent curves in multidimensional space. By expressing coordinates \( x, y, z \) based on a common variable \( t \), we can describe complex paths and motions simply. This becomes clear when considering the vector path \( \mathbf{r}(t) = t \mathbf{i} + t \mathbf{j} + t \mathbf{k} \) in our exercise.
In this setup, each component of the vector is expressed individually as a function of \( t \):
Parametric equations simplify integration by rotating the original multi-variable integral into a single-variable integral, which makes the computation significantly more straightforward.
In this setup, each component of the vector is expressed individually as a function of \( t \):
- \( x(t) = t \)
- \( y(t) = t \)
- \( z(t) = t \)
Parametric equations simplify integration by rotating the original multi-variable integral into a single-variable integral, which makes the computation significantly more straightforward.
Natural Logarithm
The natural logarithm, denoted as \( \ln(t) \), is a fundamental mathematical function with properties that are crucial in calculus, especially in integration. Its relevance is seen in our exercise where the function \( f(t) = \frac{1}{t} \) is integrated. The indefinite integral of \( \frac{1}{t} \) is \( \ln |t| + C \), where \( C \) is the constant of integration.
Key properties of the natural logarithm include:
Key properties of the natural logarithm include:
- \( \ln(1) = 0 \)
- \( \ln(e) = 1 \), where \( e \) is the base of the natural logarithm, approximately equal to 2.718.
- The natural logarithm transforms multiplication into addition: \( \ln(a) + \ln(b) = \ln(ab) \).