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Give parametric equations and parameter intervals for the motion of a particle in the \(x y\) -plane. Identify the particle's path by finding a Cartesian equation for it. Graph the Cartesian equation. (The graphs will vary with the equation used.) Indicate the portion of the graph traced by the particle and the direction of motion. $$x=-\cosh t, \quad y=\sinh t, \quad-\infty< t <\infty$$

Short Answer

Expert verified
The particle moves along the right branch of the hyperbola \(x^2 - y^2 = 1\) from left to right.

Step by step solution

01

Analyze the given parametric equations

The given parametric equations are \(x = -\cosh t\) and \(y = \sinh t\). These equations describe the motion of a particle in the \(xy\)-plane, where \(t\) is the parameter controlling the position over time.
02

Find the Cartesian equation

To find the Cartesian equation, we need to eliminate the parameter \(t\). Utilizing the hyperbolic identities, we know \(\cosh^2 t - \sinh^2 t = 1\). Rearrange the equations to find \(\cosh^2 t\) and \(\sinh^2 t\) in terms of \(x\) and \(y\):- From \(x = -\cosh t\), we have \(\cosh t = -x\).- From \(y = \sinh t\), we have \(\sinh t = y\).Substituting back into the identity, we get:\[(-x)^2 - y^2 = 1 \quad\Rightarrow\quad x^2 - y^2 = 1\].Hence, the Cartesian equation is \(x^2 - y^2 = 1\).
03

Graph the Cartesian equation

Graph \(x^2 - y^2 = 1\). This equation describes a hyperbola centered at the origin (0,0), opening horizontally along the x-axis. The hyperbola consists of two branches in the first and third quadrants.
04

Indicate the portion and direction of the graph traced by the particle

The parametric equations trace out the right branch of the hyperbola starting from \((-1,0)\) to negative infinity along the x-axis. As \(t\) increases, the particle moves from left to right along the right branch of the hyperbola in the coordinate frame. This is indicated by the parametric range \(-\infty < t < \infty\). As \(t\) goes to positive or negative infinity, \(x\) approaches negative infinity, and \(y\) covers all real numbers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hyperbolic Functions
Hyperbolic functions are a group of mathematical functions that are analogous to the trigonometric functions but based on hyperbolas instead of circles. There are three primary hyperbolic functions: hyperbolic sine (\( \sinh t \)), hyperbolic cosine (\( \cosh t \)), and hyperbolic tangent (\( \tanh t \)). These functions are defined as follows:
  • \( \sinh t = \frac{e^t - e^{-t}}{2} \)
  • \( \cosh t = \frac{e^t + e^{-t}}{2} \)
  • \( \tanh t = \frac{\sinh t}{\cosh t} \)
Hyperbolic functions are used in many areas of mathematics, including calculus and complex analysis. They have properties similar to trigonometric functions. For instance, the identity \( \cosh^2 t - \sinh^2 t = 1 \) is a key relationship when working with these functions, similar to the Pythagorean identity \( \cos^2 t + \sin^2 t = 1 \). This identity also helps when converting between parametric and Cartesian equations, as we see in this exercise. Hyperbolic functions can describe the shape of hyperbolas, which is a fundamental concept in this problem.
Cartesian Equations
A Cartesian equation is a standard form equation that describes a curve in terms of the x and y coordinates. When given parametric equations, like \( x = -\cosh t \) and \( y = \sinh t \), a typical task is to manipulate these into a Cartesian format by eliminating the parameter, here \( t \).

To do this, use identities and algebraic manipulation. For hyperbolic functions, the identity \( \cosh^2 t - \sinh^2 t = 1 \) is crucial. Given the parametric forms, we express \( \cosh t \) and \( \sinh t \) in terms of x and y: \( \cosh t = -x \) and \( \sinh t = y \). Substituting these into the identity, we derive the Cartesian equation:
  • Substitute \( \cosh t = -x \) into \( \cosh^2 t = x^2 \)
  • Substitute \( \sinh t = y \) into \( \sinh^2 t = y^2 \)
  • Use the identity: \( x^2 - y^2 = 1 \)
Hence, the Cartesian equation \(x^2 - y^2 = 1\) represents a hyperbola centered at the origin.
Graphing Hyperbolas
Graphing hyperbolas involves understanding their shape and orientation in the Cartesian plane. The equation \( x^2 - y^2 = 1 \) defines a particular type of hyperbola, with certain characteristics based on its form.

This hyperbola is centered at the origin (0,0). Its axis of symmetry is along the x-axis, indicating it opens left and right. The standard structure of a hyperbola equation \( x^2/a^2 - y^2/b^2 = 1 \) shows that the hyperbola's transverse axis extends horizontally. For our equation where \( a^2 = 1 \) and \( b^2 = 1 \), the branches are parallel to the x-axis, positioned symmetrically about the y-axis.

To graph this type of hyperbola, follow these steps:
  • Start by marking the center at the origin (0,0).
  • Since \( a = 1 \) and \( b = 1 \), particularly focus on the points (\( \pm 1, 0 \)). These are near the vertices of the hyperbola along the x-axis.
  • Sketch the two branches of the hyperbola.
The hyperbola consists of two curves that seemingly "mirror" each other across the y-axis. Each curve extends infinitely in the horizontal direction. By understanding the characteristics and the graph arrangement, you can visualize the role of hyperbolas in real-world contexts and mathematical applications.

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Most popular questions from this chapter

Exercises \(29-36\) give the eccentricities of conic sections with one focus at the origin along with the directrix corresponding to that focus. Find a polar equation for each conic section. $$e=1 / 2, \quad x=1$$

Find the coordinates of the centroid of the curve $$ x=\cos t, \quad y=t+\sin t, \quad 0 \leq t \leq \pi $$

Exercises \(53-56\) give equations for hyperbolas and tell how many units up or down and to the right or left each hyperbola is to be shifted. Find an equation for the new hyperbola, and find the new center, foci, vertices, and asymptotes. $$ y^{2}-x^{2}=1, \quad \text { left } 1, \text { down } 1 $$

Exercises \(35-38\) give information about the foci, vertices, and asymptotes of hyperbolas centered at the origin of the \(x y\) -plane. In each case, find the hyperbola's standard-form equation from the information given. $$ \begin{array}{l}{\text { Foci: }( \pm 2,0)} \\ {\text { Asymptotes: } y=\pm \frac{1}{\sqrt{3}} x}\end{array} $$

Use a CAS to perform the following steps for the given curve over the closed interval. a. Plot the curve together with the polygonal path approximations for \(n=2,4,8\) partition points over the interval. (See Figure \(11.15 . )\) b. Find the corresponding approximation to the length of the curve by summing the lengths of the line segments. c. Evaluate the length of the curve using an integral. Compare your approximations for \(n=2,4,8\) with the actual length given by the integral. How does the actual length compare with the approximations as \(n\) increases? Explain your answer. $$ x=t-\cos t, \quad y=1+\sin t, \quad-\pi \leq t \leq \pi $$

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