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Exercises \(17-24\) give equations for ellipses. Put each equation in standard form. Then sketch the ellipse. Include the foci in your sketch. $$ 16 x^{2}+25 y^{2}=400 $$

Short Answer

Expert verified
Standard form: \(\frac{x^2}{25} + \frac{y^2}{16} = 1\). Foci: \((3, 0)\), \((-3, 0)\).

Step by step solution

01

Identify the equation format

The given equation is \(16x^2 + 25y^2 = 400\). This is a generalized form of an ellipse equation \(Ax^2 + By^2 = C\). We will convert it into the standard form of an ellipse \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), where \(a\) and \(b\) are the semi-major and semi-minor axes respectively.
02

Divide by the constant term

Divide the entire equation \(16x^2 + 25y^2 = 400\) by 400 to get the equation in standard form:\[\frac{16x^2}{400} + \frac{25y^2}{400} = 1\].
03

Simplify the fractions

Simplify the fractions:\[\frac{x^2}{25} + \frac{y^2}{16} = 1\].This corresponds to the standard form \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\) with \(a^2 = 25\) and \(b^2 = 16\). Thus, \(a = 5\) and \(b = 4\).
04

Determine the orientation of the ellipse

Since \(a > b\), the ellipse is horizontal, meaning the major axis is along the x-axis.
05

Calculate the foci

The coordinates of the foci are given by \((\pm c, 0)\) where \(c = \sqrt{a^2 - b^2}\). Calculate \(c\) as follows:\[c = \sqrt{25 - 16} = \sqrt{9} = 3\].Thus, the foci are at \((3, 0)\) and \((-3, 0)\).
06

Sketch the ellipse

The ellipse has a horizontal major axis with a semi-major axis of 5 and a semi-minor axis of 4. Plot a horizontal ellipse centered at the origin (0,0), extending 5 units on either side of the x-axis and 4 units on either side of the y-axis. Include the foci at \((3, 0)\) and \((-3, 0)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Form of an Ellipse
The standard form is essential for understanding many properties of an ellipse. An ellipse in standard form is expressed as \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), where \(a\) and \(b\) correspond to the lengths of the semi-major and semi-minor axes, respectively.
To convert the given equation \(16x^2 + 25y^2 = 400\) into the standard form, you first divide every term by 400, resulting in \(\frac{16x^2}{400} + \frac{25y^2}{400} = 1\).
This simplifies to \(\frac{x^2}{25} + \frac{y^2}{16} = 1\), indicating a semi-major axis value squared of 25 and a semi-minor axis value squared of 16. This allows us to identify \(a = 5\) and \(b = 4\).
Understanding the standard form helps you easily identify the major axis of the ellipse and determine the overall shape. In this case, since \(a > b\), the ellipse is oriented horizontally.
Foci of an Ellipse
The foci are crucial in defining the unique elliptical shape. For an ellipse centered at the origin, the foci are located along the major axis. The formulas for calculating the foci are \((\pm c, 0)\) for a horizontal ellipse, or \((0, \pm c)\) for a vertical ellipse, where \(c = \sqrt{a^2 - b^2}\).
Using the given \(a = 5\) and \(b = 4\) from the standard form \(\frac{x^2}{25} + \frac{y^2}{16} = 1\), we find\
\[c = \sqrt{25 - 16} = \sqrt{9} = 3\].
Thus, the foci for this ellipse are at \((3, 0)\) and \((-3, 0)\), which lie along the x-axis since it's a horizontal ellipse.
The foci are important because they provide another degree of measurement in terms of the ellipse's eccentricity (how stretched out it is) and play a major role in its geometric definition.
Elliptical Equations
Elliptical equations are fundamental in describing the shape and orientation of an ellipse. An ellipse can be recognized by its general equation format \(Ax^2 + By^2 = C\), which then needs to be transposed into a standard format for clarity.
In our example, \(16x^2 + 25y^2 = 400\), we convert this to standard form to clearly identify the ellipse's properties. Simplification results in \(\frac{x^2}{25} + \frac{y^2}{16} = 1\), offering insight into the ellipse's axes and overall orientation.
Equations of ellipses can be horizontal or vertical oriented, determined by comparing \(a\) and \(b\).
  • Horizontal ellipses have \(a > b\).
  • Vertical ellipses have \(b > a\).
Converting these equations correctly allows us to clearly visualize and graph the ellipse, showcasing its major axis, minor axis, and even its foci, providing a better geometric understanding of its form.

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Most popular questions from this chapter

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