Chapter 16: Problem 16
Use the Divergence Theorem to find the outward flux of \(\mathbf{F}\) across the boundary of the region \(D .\) Thick cylinder \(\mathbf{F}=\ln \left(x^{2}+y^{2}\right) \mathbf{i}-\left(\frac{2 z}{x} \tan ^{-1} \frac{y}{x}\right) \mathbf{j}+\) \(z \sqrt{x^{2}+y^{2}} \mathbf{k}\) \(D :\) The thick-walled cylinder \(1 \leq x^{2}+y^{2} \leq 2, \quad-1 \leq z \leq 2\)
Short Answer
Step by step solution
Review the Divergence Theorem
Compute the Divergence of \( \mathbf{F} \)
Integrate \( \nabla \cdot \mathbf{F} \) over Region \( D \)
Evaluate the Integral
Conclusion and Result
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Flux Calculation
- Divergence Theorem Formula: \( \iint_{S} \mathbf{F} \cdot \mathbf{n} \, dS = \iiint_{D} (abla \cdot \mathbf{F}) \, dV \)
- This theorem simplifies flux calculation by converting a complex surface integral into a more manageable volume integral.
Vector Field
- \( F_1 = \ln(x^2 + y^2) \)
- \( F_2 = -\left( \frac{2z}{x} \tan^{-1} \frac{y}{x} \right) \)
- \( F_3 = z\sqrt{x^2+y^2} \)
Cylindrical Coordinates
- \( r \) - the radial distance from the origin; \( r = \sqrt{x^2 + y^2} \)
- \( \theta \) - the angular coordinate around the z-axis; ranging from \( 0 \) to \( 2\pi \)
- \( z \) - the axial coordinate parallel to the z-axis.
Partial Derivatives
- First, compute \( \frac{\partial}{\partial x}(\ln(x^2 + y^2)) \)
- Second, compute \( \frac{\partial}{\partial y}\left( -\frac{2z}{x} \tan^{-1} \frac{y}{x} \right) \)
- Third, compute \( \frac{\partial}{\partial z}(z\sqrt{x^2+y^2}) \)