Chapter 12: Problem 54
Unit vectors in the plane Show that a unit vector in the plane can be expressed as \(\mathbf{u}=(\cos \theta) \mathbf{i}+(\sin \theta) \mathbf{j},\) obtained by rotating \(\mathbf{i}\) through an angle \(\theta\) in the counterclockwise direction. Explain why this form gives every unit vector in the plane.
Short Answer
Step by step solution
Understanding Unit Vectors
Expressing the Unit Vector
Using Magnitude Condition
Trigonometric Representation
Form of the Unit Vector
Explanation of Rotation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Magnitude
- A unit vector has a magnitude of 1, no matter its direction.
- In mathematical notation, the magnitude of a vector \( \mathbf{u} = a \mathbf{i} + b \mathbf{j} \) is expressed as \( \sqrt{a^2 + b^2} = 1 \).
- This condition is crucial since it ensures that the vector represents purely direction without stretching or shrinking.
Trigonometric Representation
- \(\cos \theta\), which provides the horizontal component.
- \(\sin \theta\), which gives the vertical component.
- Trigonometric identities, such as \( \cos^2 \theta + \sin^2 \theta = 1 \), guarantee that the sum of the squares of these components equals 1.
- It offers a continuous representation of all possible directions by varying \(\theta\), which ranges from 0 to \(2\pi\).
Cartesian Coordinates
- Units along the x and y axes are often expressed using base vectors \( \mathbf{i} \) and \( \mathbf{j} \). These are the unit vectors pointing in the direction of the x-axis and y-axis, respectively.
- Unit vectors arranged in this way—like \( \mathbf{u} = (\cos \theta) \mathbf{i} + (\sin \theta) \mathbf{j} \)—still fall under Cartesian coordinates since you mention explicit values for each axis.